{"ok":true,"question":{"id":181821,"question_uuid":"502c69f9-6674-4a7d-a87c-2d6b3fadda38","job_id":10,"source_file":"冀教版/八下/薛豪Q_18952688822_320.pdf","source_page_start":2,"source_page_end":2,"source_bbox":"[31.56, 532.02, 275.45, 596.28]","subject_code":"math","grade_level":"JUNIOR","tree_code":"KT_JUNIOR_MATH_STANDARD","question_type":"comprehensive","canonical_json":"{\"year\": null, \"blocks\": [{\"text\": \"[\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\textbf{小试1}\"}, {\"text\": \"]\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\quad \\\\text{已知函数}\"}, {\"text\": \"y = (3m - 2)\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"x^{2+n}\"}, {\"text\": \"+ (m +\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\frac{n}{2}\"}, {\"text\": \").\", \"type\": \"text\"}, {\"type\": \"subquestion\", \"index\": 1, \"blocks\": [{\"text\": \"当m, n为何值时，该函数是一次函数？\", \"type\": \"text\"}]}, {\"type\": \"subquestion\", \"index\": 2, \"blocks\": [{\"text\": \"当m, n为何值时，该函数是正比例函数？\", \"type\": \"text\"}]}, {\"type\": \"answer\", \"blocks\": [{\"text\": \"(1)当 m ≠\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"2_{3}\"}, {\"text\": \", n = −1时，该函数是一次函数.\", \"type\": \"text\"}]}, {\"type\": \"solution\", \"blocks\": [{\"text\": \"(2)当 m =\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"1_{2}\"}, {\"text\": \", n = −1时，该函数是正比例函数. 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(1)由题意，得：3m −2 ≠0,2 + n = 1，解得 m ≠\\(2 _{3}\\), n = −1, 即当m ≠\\(2 _{3}\\), n=−1时，该函数是一次函数． (2)由题意，得 3m −2 ≠0,2 + n = 1, m + n 1\\(1 _{2}\\)= 0，解得m = _{2}, n = −1, 即当m = _{2}, n = −1时，该函数是正比例函数．","explain_html":null,"difficulty":2,"score":null,"year":null,"parse_status":"PARSED","qa_status":"QUARANTINED","retry_count":0,"final_score":null,"error_message":"处理异常: LLM call failed after retries: HTTPConnectionPool(host='127.0.0.1', port=8092): Read timed out. (read timeout=120) [endpoints: http://127.0.0.1:8091/v1 -> http://127.0.0.1:8092/v1]","published_question_id":null,"content_sha256":"a5a39bff4ccf855339677559c1083d78794b6f2e80d47c3470f6f91aa366cbd2","created_at":"2026-11-10T09:51:20","updated_at":"2026-11-10T10:18:41","answer_missing":false,"formula_fallback":false,"_number":"1","_section":"quiz","_section_label":"小试牛刀   ★ 独立完成，见证实力！"},"assets":[],"knowledge":[],"audits":[{"id":9422010,"import_question_id":181821,"audit_type":"STRUCTURE","auditor_name":"structure-rule","status":"PASS","score":0.9,"input_snapshot":"[ \\textbf{小试1} ] \\quad \\text{已知函数} y = (3m - 2) x^{2+n} + (m + \\frac{n}{2} ). (1) 当m, n为何值时，该函数是一次函数？ (2) 当m, n为何值时，该函数是正比例函数？","result_json":"{\"ok\": true, \"rule\": \"clean-override\", \"issues\": [], \"confidence\": 0.9}","created_at":"2026-11-10T10:14:41"},{"id":9422011,"import_question_id":181821,"audit_type":"FORMULA","auditor_name":"formula-auditor","status":"PASS","score":1.0,"input_snapshot":"\\textbf{小试1}; \\quad \\text{已知函数}; x^{2+n}; \\frac{n}{2}; 2_{3}","result_json":"{\"risky\": 7, \"issues\": [], \"checked\": 9, \"invalid\": 0, \"visual_check\": \"delegated_to_question_vision\", \"invalid_details\": [], \"visually_verified\": 0}","created_at":"2026-11-10T10:14:41"},{"id":9422012,"import_question_id":181821,"audit_type":"KNOWLEDGE","auditor_name":"knowledge-auditor","status":"WARN","score":0.0,"input_snapshot":"[ \\textbf{小试1} ] \\quad \\text{已知函数} y = (3m - 2) x^{2+n} + (m + \\frac{n}{2} ). (1) 当m, n为何值时，该函数是一次函数？ (2) 当m, n为何值时，该函数是正比例函数？","result_json":"{\"picks\": [], \"tree_code\": \"KT_JUNIOR_MATH_STANDARD\", \"candidates\": 0, \"classifier_version\": null}","created_at":"2026-11-10T10:14:41"},{"id":9422047,"import_question_id":181821,"audit_type":"VISION","auditor_name":"vision-auditor","status":"PASS","score":0.95,"input_snapshot":"题干：\n[\\(\\textbf{小试1}\\)]\\(\\quad \\text{已知函数}\\)y = (3m - 2)\\(x^{2+n}\\)+ (m +\\(\\frac{n}{2}\\)). （1）当m, n为何值时，该函数是一次函数？ （2）当m, n为何值时，该函数是正比例函数？\n答案：\n(1)当 m ≠\\(2_{3}\\), n = −1时，该函数是一次函数.\n解析：\n(2)当 m =\\(1_{2}\\), n = −1时，该函数是正比例函数. (1)由题意，得：3m −2 ≠0,2 + n = 1，解得 m ≠\\(2 _{3}\\), n = −1, 即当m ≠\\(2 _{3}\\), n=−1时，该函数是一次函数． (2)由题意，得 3m −2 ≠0,2 + n = 1, m + n 1\\(1 _{2}\\)= 0，解得m = _{2}, n = −1, 即当m = _{2}, n = −1时，该函数是正比例函数．","result_json":"{\"ok\": true, \"hard\": false, \"issues\": [], \"confidence\": 0.95, \"suggestions\": [\"题干中的函数表达式排版略显紧凑，建议在 x^{2+n} 前后增加空格以提升可读性，例如：y = (3m - 2)x^{2+n} + (m + n/2)\"]}","created_at":"2026-11-10T10:15:58"}]}