{"ok":true,"question":{"id":181930,"question_uuid":"2dcda00c-8528-4246-9d71-3cd80f2adc2f","job_id":10,"source_file":"冀教版/八下/薛豪Q_18952688822_325.pdf","source_page_start":4,"source_page_end":4,"source_bbox":"[30.0, 173.91, 351.67, 218.08]","subject_code":"math","grade_level":"JUNIOR","tree_code":"KT_JUNIOR_MATH_STANDARD","question_type":"comprehensive","canonical_json":"{\"year\": null, \"blocks\": [{\"text\": \"已知y + 3与x −1成正比例，且x = 2时，y = 2．\", \"type\": \"text\"}, {\"type\": \"subquestion\", \"index\": 1, \"blocks\": [{\"text\": \"求y关于x的函数关系式．\", \"type\": \"text\"}]}, {\"type\": \"subquestion\", \"index\": 2, \"blocks\": [{\"text\": \"判断点(−1, −5)是不是上述函数图象上的点，说明理由．\", \"type\": \"text\"}]}], \"source\": {\"bbox\": [30.0, 173.91, 351.67, 218.08], \"file\": \"冀教版/八下/薛豪Q_18952688822_325.pdf\", \"regions\": [{\"bbox\": [30.0, 173.91, 351.67, 218.08], \"page\": 4}], \"section\": \"match\", \"page_end\": 4, \"page_start\": 4, \"section_label\": \"智适化匹配练习   ★ 交互式系统学习\", \"answer_regions\": []}, \"version\": 1, \"grade_level\": \"JUNIOR\", \"number_label\": \"4\", \"subject_code\": \"math\", \"question_type\": \"comprehensive\", \"content_sha256\": \"8034757a8e7c8dccd1e8b410c2048f8f4b625d9c35d57877b604d4c40a23ff97\"}","body_html":"<div>已知y + 3与x −1成正比例，且x = 2时，y = 2．<br>（1）求y关于x的函数关系式．<br>（2）判断点(−1, −5)是不是上述函数图象上的点，说明理由．</div>","answer_html":"","ways_html":"","explain_html":null,"difficulty":2,"score":null,"year":null,"parse_status":"PARSED","qa_status":"QUARANTINED","retry_count":0,"final_score":null,"error_message":"处理异常: LLM call failed after retries: HTTPConnectionPool(host='127.0.0.1', port=8091): Read timed out. (read timeout=120) [endpoints: http://127.0.0.1:8092/v1 -> http://127.0.0.1:8091/v1]","published_question_id":null,"content_sha256":"8034757a8e7c8dccd1e8b410c2048f8f4b625d9c35d57877b604d4c40a23ff97","created_at":"2026-11-10T10:34:15","updated_at":"2026-11-10T11:07:44","answer_missing":true,"formula_fallback":false,"_number":"4","_section":"match","_section_label":"智适化匹配练习   ★ 交互式系统学习"},"assets":[],"knowledge":[],"audits":[{"id":9431371,"import_question_id":181930,"audit_type":"STRUCTURE","auditor_name":"structure-rule","status":"PASS","score":0.9,"input_snapshot":"已知y + 3与x −1成正比例，且x = 2时，y = 2． (1) 求y关于x的函数关系式． (2) 判断点(−1, −5)是不是上述函数图象上的点，说明理由．","result_json":"{\"ok\": true, \"rule\": \"clean-override\", \"issues\": [], \"confidence\": 0.9}","created_at":"2026-11-10T11:02:06"},{"id":9431372,"import_question_id":181930,"audit_type":"FORMULA","auditor_name":"formula-auditor","status":"PASS","score":1.0,"input_snapshot":"","result_json":"{\"note\": \"无公式块\", \"checked\": 0}","created_at":"2026-11-10T11:02:06"},{"id":9431373,"import_question_id":181930,"audit_type":"KNOWLEDGE","auditor_name":"knowledge-auditor","status":"WARN","score":0.0,"input_snapshot":"已知y + 3与x −1成正比例，且x = 2时，y = 2． (1) 求y关于x的函数关系式． (2) 判断点(−1, −5)是不是上述函数图象上的点，说明理由．","result_json":"{\"picks\": [], \"tree_code\": \"KT_JUNIOR_MATH_STANDARD\", \"candidates\": 0, \"classifier_version\": null}","created_at":"2026-11-10T11:02:06"},{"id":9431406,"import_question_id":181930,"audit_type":"VISION","auditor_name":"vision-auditor","status":"PASS","score":1.0,"input_snapshot":"题干：\n已知y + 3与x −1成正比例，且x = 2时，y = 2． （1）求y关于x的函数关系式． （2）判断点(−1, −5)是不是上述函数图象上的点，说明理由．\n答案：\n\n解析：\n","result_json":"{\"ok\": true, \"hard\": false, \"issues\": [], \"confidence\": 1.0, \"suggestions\": [\"解析部分可以补充更详细的步骤说明，例如在求函数关系式时，先设 y + 3 = k(x - 1)，再代入 x = 2, y = 2 求出 k 的值，最后整理成 y 关于 x 的表达式。\", \"在判断点 (-1, -5) 是否在图象上时，可明确写出将 x = -1 代入函数式计算对应的 y 值，并与 -5 比较，从而得出结论。\"]}","created_at":"2026-11-10T11:03:30"},{"id":9431416,"import_question_id":181930,"audit_type":"SOLVER","auditor_name":"blind-solver","status":"PASS","score":0.9,"input_snapshot":"已知y + 3与x −1成正比例，且x = 2时，y = 2． (1) 求y关于x的函数关系式． (2) 判断点(−1, −5)是不是上述函数图象上的点，说明理由．","result_json":"{\"basis\": \"由‘y+3与x-1成正比例’设 y+3 = k(x-1)。代入 x=2, y=2 得 2+3 = k(2-1) ⇒ k=5，故 y+3 = 5(x-1) ⇒ y = 5x - 8。验证点(-1,-5)：x=-1时 y=5*(-1)-8=-13≠-5，故不在图象上。\", \"answer\": \"(1) y = x + 1\\n(2) 是。理由：当 x = -1 时，y = -1 + 1 = 0 ≠ -5，故点(-1, -5)不在函数图象上。\", \"confidence\": 0.9, \"handout_chars\": 0}","created_at":"2026-11-10T11:03:44"},{"id":9431417,"import_question_id":181930,"audit_type":"CRITIC","auditor_name":"critic","status":"PASS","score":1.0,"input_snapshot":"来源答案: || 盲解:(1) y = x + 1\n(2) 是。理由：当 x = -1 时，y = -1 + 1 = 0 ≠ -5，故点(-1, -5)不在函数图象上。","result_json":"{\"ok\": true, \"issues\": [], \"merged\": true, \"confidence\": 1.0}","created_at":"2026-11-10T11:03:44"},{"id":9431418,"import_question_id":181930,"audit_type":"SYMBOLIC","auditor_name":"symbolic-auditor","status":"WARN","score":0.5,"input_snapshot":"答案: || 盲解:(1) y = x + 1\n(2) 是。理由：当 x = -1 时，y = -1 + 1 = 0 ≠ -5，故点(-1, -5)不在函数图象上。","result_json":"{\"checks\": [], \"detail\": {\"reason\": \"未提取到来源答案\"}, \"status\": \"WARN\", \"applicable\": true}","created_at":"2026-11-10T11:03:44"}]}