{"ok":true,"question":{"id":182085,"question_uuid":"317d02fa-64c5-4c6f-8c24-b4844021be54","job_id":10,"source_file":"冀教版/八下/薛豪Q_18952688822_335_检测.pdf","source_page_start":1,"source_page_end":1,"source_bbox":"[30.22, 144.62, 444.2, 225.33]","subject_code":"math","grade_level":"JUNIOR","tree_code":"KT_JUNIOR_MATH_STANDARD","question_type":"single_choice","canonical_json":"{\"year\": null, \"blocks\": [{\"text\": \"若y−1与2x+ 3成正比例，且x= 2时，y= 15，则y关于x的函数解析式为(       )\", \"type\": \"text\"}, {\"type\": \"option\", \"label\": \"A\", \"blocks\": [{\"text\": \"y = 2x + 3\", \"type\": \"text\"}], \"source_bbox\": [47.57, 172.11, 101.07, 183.99], \"source_page\": 1}, {\"type\": \"option\", \"label\": \"B\", \"blocks\": [{\"text\": \"y = 4x + 7\", \"type\": \"text\"}], \"source_bbox\": [47.57, 185.89, 101.07, 197.77], \"source_page\": 1}, {\"type\": \"option\", \"label\": \"C\", \"blocks\": [{\"text\": \"y = 2x + 2\", \"type\": \"text\"}], \"source_bbox\": [47.57, 199.67, 101.07, 211.55], \"source_page\": 1}, {\"type\": \"option\", \"label\": \"D\", \"blocks\": [{\"text\": \"y = 2x + 15\", \"type\": \"text\"}], \"source_bbox\": [47.57, 213.45, 106.85, 225.33], \"source_page\": 1}, {\"type\": \"answer\", \"blocks\": [{\"text\": \"B\", \"type\": \"text\"}]}, {\"type\": \"solution\", \"blocks\": [{\"text\": \"由题意，设y−1 =k(2x+ 3)， ∵ x= 2时,y= 15,∴ 15 −1 =k(\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"2\\\\times 2 + 3\"}, {\"text\": \"),解 得：k = 2；∴y −1 = 2(2x + 3), ∴y = 4x + 7; 故选B．\", \"type\": \"text\"}]}], \"source\": {\"bbox\": [30.22, 144.62, 444.2, 225.33], \"file\": \"冀教版/八下/薛豪Q_18952688822_335_检测.pdf\", \"regions\": [{\"bbox\": [30.22, 144.62, 444.2, 225.33], \"page\": 1}], \"section\": \"generic\", \"page_end\": 1, \"page_start\": 1, \"section_label\": \"\", \"answer_regions\": [{\"bbox\": [43.99800109863281, 141.9988555908203, 426.4542236328125, 180.4205780029297], \"page\": 5}]}, \"version\": 1, \"grade_level\": \"JUNIOR\", \"number_label\": \"1\", \"subject_code\": \"math\", \"question_type\": \"single_choice\", \"content_sha256\": \"85481b1ca2ecdff97c84f115372b50f0ec1a55a67325eaf62e434a7dfa6d729a\"}","body_html":"<div>若y−1与2x+ 3成正比例，且x= 2时，y= 15，则y关于x的函数解析式为(       )<br>A. y = 2x + 3<br>B. y = 4x + 7<br>C. y = 2x + 2<br>D. y = 2x + 15</div>","answer_html":"B","ways_html":"由题意，设y−1 =k(2x+ 3)， ∵ x= 2时,y= 15,∴ 15 −1 =k(\\(2\\times 2 + 3\\)),解 得：k = 2；∴y −1 = 2(2x + 3), ∴y = 4x + 7; 故选B．","explain_html":null,"difficulty":2,"score":null,"year":null,"parse_status":"PARSED","qa_status":"QUARANTINED","retry_count":0,"final_score":null,"error_message":"处理异常: LLM call failed after retries: HTTPConnectionPool(host='127.0.0.1', port=8091): Read timed out. (read timeout=120) [endpoints: http://127.0.0.1:8092/v1 -> http://127.0.0.1:8091/v1]","published_question_id":null,"content_sha256":"85481b1ca2ecdff97c84f115372b50f0ec1a55a67325eaf62e434a7dfa6d729a","created_at":"2026-11-10T12:04:22","updated_at":"2026-11-10T12:34:19","answer_missing":false,"formula_fallback":false,"_number":"1","_section":"generic","_section_label":""},"assets":[],"knowledge":[],"audits":[{"id":9446719,"import_question_id":182085,"audit_type":"STRUCTURE","auditor_name":"structure-rule","status":"PASS","score":0.9,"input_snapshot":"若y−1与2x+ 3成正比例，且x= 2时，y= 15，则y关于x的函数解析式为( ) A. y = 2x + 3 B. y = 4x + 7 C. y = 2x + 2 D. y = 2x + 15","result_json":"{\"ok\": true, \"rule\": \"clean-override\", \"issues\": [], \"confidence\": 0.9}","created_at":"2026-11-10T12:28:24"},{"id":9446720,"import_question_id":182085,"audit_type":"FORMULA","auditor_name":"formula-auditor","status":"PASS","score":1.0,"input_snapshot":"2\\times 2 + 3","result_json":"{\"risky\": 1, \"issues\": [], \"checked\": 1, \"invalid\": 0, \"visual_check\": \"delegated_to_question_vision\", \"invalid_details\": [], \"visually_verified\": 0}","created_at":"2026-11-10T12:28:24"},{"id":9446721,"import_question_id":182085,"audit_type":"KNOWLEDGE","auditor_name":"knowledge-auditor","status":"WARN","score":0.0,"input_snapshot":"若y−1与2x+ 3成正比例，且x= 2时，y= 15，则y关于x的函数解析式为( ) A. y = 2x + 3 B. y = 4x + 7 C. y = 2x + 2 D. y = 2x + 15","result_json":"{\"picks\": [], \"tree_code\": \"KT_JUNIOR_MATH_STANDARD\", \"candidates\": 0, \"classifier_version\": null}","created_at":"2026-11-10T12:28:24"},{"id":9449472,"import_question_id":182085,"audit_type":"VISION","auditor_name":"vision-auditor","status":"PASS","score":1.0,"input_snapshot":"题干：\n若y−1与2x+ 3成正比例，且x= 2时，y= 15，则y关于x的函数解析式为( ) A. y = 2x + 3 B. y = 4x + 7 C. y = 2x + 2 D. y = 2x + 15\n答案：\nB\n解析：\n由题意，设y−1 =k(2x+ 3)， ∵ x= 2时,y= 15,∴ 15 −1 =k(\\(2\\times 2 + 3\\)),解 得：k = 2；∴y −1 = 2(2x + 3), ∴y = 4x + 7; 故选B．","result_json":"{\"ok\": true, \"hard\": false, \"issues\": [], \"confidence\": 1.0, \"suggestions\": []}","created_at":"2026-11-10T12:29:58"},{"id":9449480,"import_question_id":182085,"audit_type":"SOLVER","auditor_name":"blind-solver","status":"PASS","score":1.0,"input_snapshot":"若y−1与2x+ 3成正比例，且x= 2时，y= 15，则y关于x的函数解析式为( ) A. y = 2x + 3 B. y = 4x + 7 C. y = 2x + 2 D. y = 2x + 15","result_json":"{\"basis\": \"由正比例关系设 y−1 = k(2x+3)。代入 x=2, y=15 得 14 = k·7 ⇒ k=2。因此 y−1 = 2(2x+3) = 4x+6，即 y = 4x+7。\", \"answer\": \"B\", \"confidence\": 1.0, \"handout_chars\": 0}","created_at":"2026-11-10T12:30:18"},{"id":9449481,"import_question_id":182085,"audit_type":"CRITIC","auditor_name":"critic","status":"PASS","score":1.0,"input_snapshot":"来源答案:B || 盲解:B","result_json":"{\"ok\": true, \"issues\": [], \"merged\": true, \"confidence\": 1.0}","created_at":"2026-11-10T12:30:18"},{"id":9449482,"import_question_id":182085,"audit_type":"SYMBOLIC","auditor_name":"symbolic-auditor","status":"PASS","score":1.0,"input_snapshot":"答案:B || 盲解:B","result_json":"{\"checks\": [], \"detail\": {\"reason\": \"盲解与来源答案一致\"}, \"status\": \"PASS\", \"applicable\": true}","created_at":"2026-11-10T12:30:18"}]}