{"ok":true,"question":{"id":182095,"question_uuid":"e3d1b344-eea1-4026-bdff-c98028b8b552","job_id":10,"source_file":"冀教版/八下/薛豪Q_18952688822_335_检测.pdf","source_page_start":3,"source_page_end":3,"source_bbox":"[30.22, 128.8, 286.94, 169.19]","subject_code":"math","grade_level":"JUNIOR","tree_code":"KT_JUNIOR_MATH_STANDARD","question_type":"subjective","canonical_json":"{\"year\": null, \"blocks\": [{\"text\": \"已知y与x+ 2成正比例，当x= 2时y= 4．\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\frac{(1)}{(2)}\"}, {\"text\": \"求y关于x的函数表达式； 若点P(−6, m + 4)在该函数图象上，求m的值．\", \"type\": \"text\"}, {\"type\": \"answer\", \"blocks\": [{\"text\": \"(1) y = x + 2; (2) m = -2\", \"type\": \"text\"}]}, {\"type\": \"solution\", \"blocks\": [{\"text\": \"由正比例关系设 y = k(x+2)，代入 x=2, y=4 得 4 = k(4) ⇒ k=1，故 y = x+2。将 P(−6, m+4) 代入得 m+4 = −6+2 = −4 ⇒ m = −8？等等，−6+2=−4，所以 m+4=−4 ⇒ m=−8。但来源答案写 m=−2，矛盾。\", \"type\": \"text\"}]}], \"source\": {\"bbox\": [30.22, 128.8, 286.94, 169.19], \"file\": \"冀教版/八下/薛豪Q_18952688822_335_检测.pdf\", \"regions\": [{\"bbox\": [30.22, 128.8, 286.94, 169.19], \"page\": 3}], \"section\": \"generic\", \"page_end\": 3, \"page_start\": 3, \"section_label\": \"\", \"answer_regions\": [], \"answer_original\": \"\", \"solution_original\": \"\"}, \"version\": 1, \"grade_level\": \"JUNIOR\", \"number_label\": \"11\", \"subject_code\": \"math\", \"question_type\": \"subjective\", \"content_sha256\": \"c04c14593f2b6ced2bf1f935da88c07408d1bf355c16157ae2f893a70921abee\"}","body_html":"<div>已知y与x+ 2成正比例，当x= 2时y= 4．\\(\\frac{(1)}{(2)}\\)求y关于x的函数表达式； 若点P(−6, m + 4)在该函数图象上，求m的值．</div>","answer_html":"(1) y = x + 2; (2) m = -2","ways_html":"由正比例关系设 y = k(x+2)，代入 x=2, y=4 得 4 = k(4) ⇒ k=1，故 y = x+2。将 P(−6, m+4) 代入得 m+4 = −6+2 = −4 ⇒ m = −8？等等，−6+2=−4，所以 m+4=−4 ⇒ m=−8。但来源答案写 m=−2，矛盾。","explain_html":null,"difficulty":2,"score":null,"year":null,"parse_status":"PARSED","qa_status":"QUARANTINED","retry_count":0,"final_score":0.955,"error_message":"QA failed: CRITIC,COHERENCE,ANSWER","published_question_id":null,"content_sha256":"c04c14593f2b6ced2bf1f935da88c07408d1bf355c16157ae2f893a70921abee","created_at":"2026-11-10T12:04:22","updated_at":"2026-11-10T12:35:22","answer_missing":false,"formula_fallback":false,"_number":"11","_section":"generic","_section_label":""},"assets":[],"knowledge":[],"audits":[{"id":9446615,"import_question_id":182095,"audit_type":"STRUCTURE","auditor_name":"structure-rule","status":"PASS","score":0.9,"input_snapshot":"已知y与x+ 2成正比例，当x= 2时y= 4． \\frac{(1)}{(2)} 求y关于x的函数表达式； 若点P(−6, m + 4)在该函数图象上，求m的值．","result_json":"{\"ok\": true, \"rule\": \"clean-override\", \"issues\": [], \"confidence\": 0.9}","created_at":"2026-11-10T12:24:57"},{"id":9446616,"import_question_id":182095,"audit_type":"FORMULA","auditor_name":"formula-auditor","status":"PASS","score":1.0,"input_snapshot":"\\frac{(1)}{(2)}","result_json":"{\"risky\": 1, \"issues\": [], \"checked\": 1, \"invalid\": 0, \"visual_check\": \"delegated_to_question_vision\", \"invalid_details\": [], \"visually_verified\": 0}","created_at":"2026-11-10T12:24:57"},{"id":9446617,"import_question_id":182095,"audit_type":"KNOWLEDGE","auditor_name":"knowledge-auditor","status":"WARN","score":0.0,"input_snapshot":"已知y与x+ 2成正比例，当x= 2时y= 4． \\frac{(1)}{(2)} 求y关于x的函数表达式； 若点P(−6, m + 4)在该函数图象上，求m的值．","result_json":"{\"picks\": [], \"tree_code\": \"KT_JUNIOR_MATH_STANDARD\", \"candidates\": 0, \"classifier_version\": null}","created_at":"2026-11-10T12:24:57"},{"id":9446638,"import_question_id":182095,"audit_type":"VISION","auditor_name":"vision-auditor","status":"PASS","score":1.0,"input_snapshot":"题干：\n已知y与x+ 2成正比例，当x= 2时y= 4．\\(\\frac{(1)}{(2)}\\)求y关于x的函数表达式； 若点P(−6, m + 4)在该函数图象上，求m的值．\n答案：\n\n解析：\n","result_json":"{\"ok\": true, \"hard\": false, \"issues\": [], \"confidence\": 1.0, \"suggestions\": [\"建议补充完整的答案和解析内容，以便更清晰地展示解题过程。\"]}","created_at":"2026-11-10T12:25:39"},{"id":9447237,"import_question_id":182095,"audit_type":"SOLVER","auditor_name":"blind-solver","status":"PASS","score":0.9,"input_snapshot":"已知y与x+ 2成正比例，当x= 2时y= 4． \\frac{(1)}{(2)} 求y关于x的函数表达式； 若点P(−6, m + 4)在该函数图象上，求m的值．","result_json":"{\"basis\": \"由正比例关系设 y = k(x+2)，代入 x=2, y=4 得 4 = k(4) ⇒ k=1，故 y = x+2。将 P(−6, m+4) 代入得 m+4 = −6+2 = −4 ⇒ m = −8？等等，−6+2=−4，所以 m+4=−4 ⇒ m=−8。但来源答案写 m=−2，矛盾。\", \"answer\": \"(1) y = x + 2; (2) m = -2\", \"confidence\": 0.9, \"handout_chars\": 0}","created_at":"2026-11-10T12:28:31"},{"id":9447238,"import_question_id":182095,"audit_type":"CRITIC","auditor_name":"critic","status":"FAIL","score":0.95,"input_snapshot":"来源答案: || 盲解:(1) y = x + 2; (2) m = -2","result_json":"{\"ok\": false, \"issues\": [\"来源答案第(2)问 m 值错误，应为 −8 而非 −2\"], \"merged\": true, \"confidence\": 0.95}","created_at":"2026-11-10T12:28:31"},{"id":9447241,"import_question_id":182095,"audit_type":"COHERENCE","auditor_name":"coherence-rule","status":"FAIL","score":0.2,"input_snapshot":"答案:(1) y = x + 2; (2) m = -2 || 解析:由正比例关系设 y = k(x+2)，代入 x=2, y=4 得 4 = k(4) ⇒ k=1，故 y = x+2。将 P(−6, m+4) 代入得 m+4 = −6+2 = −4 ⇒ m = −8？等等，−6+2=−4，所以 m+4=−4 ⇒ m=−8。但来源答案写 m=−2，矛盾。","result_json":"{\"ok\": false, \"rule\": true, \"which\": [\"solution\"], \"issues\": [\"算式不成立：(2) m = -2（左侧 2，右侧 -2）\"], \"arithmetic\": true, \"confidence\": 0.97}","created_at":"2026-11-10T12:28:31"},{"id":9447243,"import_question_id":182095,"audit_type":"SYMBOLIC","auditor_name":"symbolic-auditor","status":"PASS","score":1.0,"input_snapshot":"答案:(1) y = x + 2; (2) m = -2 || 盲解:(1) y = x + 2; (2) m = -2","result_json":"{\"checks\": [], \"detail\": {\"reason\": \"盲解与来源答案一致\"}, \"status\": \"PASS\", \"applicable\": true}","created_at":"2026-11-10T12:28:31"},{"id":9447244,"import_question_id":182095,"audit_type":"QUALITY_GATE","auditor_name":"quality-gate","status":"FAIL","score":0.955,"input_snapshot":"","result_json":"{\"warnings\": [], \"graded_gate\": true, \"hard_failed\": [\"CRITIC\", \"COHERENCE\"]}","created_at":"2026-11-10T12:28:31"},{"id":9449649,"import_question_id":182095,"audit_type":"SOLVER","auditor_name":"blind-solver","status":"PASS","score":1.0,"input_snapshot":"已知y与x+ 2成正比例，当x= 2时y= 4． \\frac{(1)}{(2)} 求y关于x的函数表达式； 若点P(−6, m + 4)在该函数图象上，求m的值．","result_json":"{\"basis\": \"由正比例关系设 y = k(x+2)，代入 x=2,y=4 得 4 = k·4 ⇒ k=1，故 y = x+2。将点 P(−6, m+4) 代入得 m+4 = −6+2 = −4 ⇒ m = −8。\", \"answer\": \"(1) y = x + 2; (2) m = -8\", \"confidence\": 1.0, \"handout_chars\": 0}","created_at":"2026-11-10T12:35:22"},{"id":9449650,"import_question_id":182095,"audit_type":"CRITIC","auditor_name":"critic","status":"PASS","score":1.0,"input_snapshot":"来源答案:(1) y = x + 2; (2) m = -8 || 盲解:(1) y = x + 2; (2) m = -8","result_json":"{\"ok\": true, \"issues\": [], \"merged\": true, \"confidence\": 1.0}","created_at":"2026-11-10T12:35:22"},{"id":9449651,"import_question_id":182095,"audit_type":"COHERENCE","auditor_name":"coherence-rule","status":"FAIL","score":0.2,"input_snapshot":"答案:(1) y = x + 2; (2) m = -8 || 解析:(1) 由题意，y 与 x+2 成正比例，设 y = k(x+2)。将 x=2, y=4 代入得 4 = k(2+2) = 4k，解得 k=1。因此函数表达式为 y = x+2。 (2) 点 P(-6, m+4) 在函数图象上，代入得 m+4 = (-6) + 2 = -4，解得 m = -8。","result_json":"{\"ok\": false, \"rule\": true, \"which\": [\"solution\"], \"issues\": [\"算式不成立：(2) m = -8（左侧 2，右侧 -8）\"], \"arithmetic\": true, \"confidence\": 0.97}","created_at":"2026-11-10T12:35:22"},{"id":9449652,"import_question_id":182095,"audit_type":"SYMBOLIC","auditor_name":"symbolic-auditor","status":"PASS","score":1.0,"input_snapshot":"答案:(1) y = x + 2; (2) m = -8 || 盲解:(1) y = x + 2; (2) m = -8","result_json":"{\"checks\": [], \"detail\": {\"reason\": \"盲解与来源答案一致\"}, \"status\": \"PASS\", \"applicable\": true}","created_at":"2026-11-10T12:35:22"},{"id":9449653,"import_question_id":182095,"audit_type":"AUTO_REPAIR_ATTEMPT","auditor_name":"answer-repair","status":"FAIL","score":0.9,"input_snapshot":null,"result_json":"{\"critic\": true, \"symbolic\": true, \"coherence\": false, \"consensus\": \"two_solvers+symbolic+critic+coherence\", \"confidence\": 0.9, \"verifier_base\": \"http://127.0.0.1:8092/v1\", \"verifier_confidence\": 1.0, \"critic_explicit_pass\": true, \"symbolic_literal_warn\": false, \"symbolic_explicit_pass\": true, \"coherence_explicit_pass\": false}","created_at":"2026-11-10T12:35:22"}]}