{"ok":true,"question":{"id":182186,"question_uuid":"2e8f368b-eaf8-4e81-b5be-d09a819115fe","job_id":10,"source_file":"冀教版/八下/薛豪Q_18952688822_340.pdf","source_page_start":2,"source_page_end":2,"source_bbox":"[31.5, 310.63, 233.04, 344.1]","subject_code":"math","grade_level":"JUNIOR","tree_code":"KT_JUNIOR_MATH_STANDARD","question_type":"subjective","canonical_json":"{\"year\": null, \"blocks\": [{\"text\": \"若\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"y\"}, {\"text\": \"与\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"x-2\"}, {\"text\": \"成正比例，且\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"x=4\"}, {\"text\": \"时，\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"y=-2\"}, {\"text\": \"，求\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"y\"}, {\"text\": \"与\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"x\"}, {\"text\": \"之间的函数表达式．\", \"type\": \"text\"}, {\"type\": \"solution\", \"blocks\": [{\"text\": \" 与x − 2成正比例,设y = (− 2)(k为常数,\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\frac{y}{k} \\\\frac{kx}{代入上式得}\"}, {\"text\": \"且  0).将x = 4, y = −2, − 2 = k(4 − 2), 即− 2 = 2,解得k = − 将k = −1代入y = k(x − 2),\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\frac{k}{1(} 1.\"}, {\"text\": \" 得 = − x − 2) =\", \"type\": \"text\"}, {\"text\": \"−+\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"x \\\\frac{y}{y} 2\"}, {\"text\": \".  与之间的函数表达式为xy = −+x 2.\", \"type\": \"text\"}]}], \"source\": {\"bbox\": [31.5, 310.63, 233.04, 344.1], \"file\": \"冀教版/八下/薛豪Q_18952688822_340.pdf\", \"regions\": [{\"bbox\": [31.5, 310.63, 233.04, 344.1], \"page\": 2}], \"section\": \"example\", \"page_end\": 2, \"page_start\": 2, \"section_label\": \"跟我学        常考关键母题各个击破！\", \"answer_regions\": [{\"bbox\": [29.81595802307129, 503.8765869140625, 278.25421142578125, 593.3078002929688], \"page\": 2}]}, \"version\": 1, \"grade_level\": \"JUNIOR\", \"number_label\": \"1\", \"subject_code\": \"math\", \"question_type\": \"subjective\", \"content_sha256\": \"d22ad713c679bc437f71af76be75837a6e430ec81669b35803ee9364e94b961a\"}","body_html":"<div>若\\(y\\)与\\(x-2\\)成正比例，且\\(x=4\\)时，\\(y=-2\\)，求\\(y\\)与\\(x\\)之间的函数表达式．</div>","answer_html":"","ways_html":" 与x − 2成正比例,设y = (− 2)(k为常数,\\(\\frac{y}{k} \\frac{kx}{代入上式得}\\)且  0).将x = 4, y = −2, − 2 = k(4 − 2), 即− 2 = 2,解得k = − 将k = −1代入y = k(x − 2),<span class=\"formula-fallback\">frack1( 1.</span> 得 = − x − 2) =−+\\(x \\frac{y}{y} 2\\).  与之间的函数表达式为xy = −+x 2.","explain_html":null,"difficulty":2,"score":null,"year":null,"parse_status":"PARSED","qa_status":"QUARANTINED","retry_count":0,"final_score":null,"error_message":"处理异常: LLM call failed after retries: HTTPConnectionPool(host='127.0.0.1', port=8092): Read timed out. (read timeout=120) [endpoints: http://127.0.0.1:8091/v1 -> http://127.0.0.1:8092/v1]","published_question_id":null,"content_sha256":"d22ad713c679bc437f71af76be75837a6e430ec81669b35803ee9364e94b961a","created_at":"2026-11-10T12:43:23","updated_at":"2026-11-10T13:10:57","answer_missing":true,"formula_fallback":true,"_number":"1","_section":"example","_section_label":"跟我学        常考关键母题各个击破！"},"assets":[],"knowledge":[],"audits":[{"id":9455758,"import_question_id":182186,"audit_type":"STRUCTURE","auditor_name":"structure-auditor","status":"PASS","score":1.0,"input_snapshot":"若 y 与 x-2 成正比例，且 x=4 时， y=-2 ，求 y 与 x 之间的函数表达式．","result_json":"{\"ok\": true, \"issues\": [], \"confidence\": 1.0}","created_at":"2026-11-10T13:05:25"},{"id":9455759,"import_question_id":182186,"audit_type":"FORMULA","auditor_name":"formula-auditor","status":"FAIL","score":1.0,"input_snapshot":"y; x-2; x=4; y=-2; y","result_json":"{\"risky\": 3, \"issues\": [\"非法 LaTeX #8: unbalanced delimiters\"], \"checked\": 9, \"invalid\": 1, \"visual_check\": \"delegated_to_question_vision\", \"invalid_details\": [{\"index\": 7, \"latex\": \"\\\\frac{k}{1(} 1.\", \"issues\": [\"unbalanced delimiters\"]}], \"visually_verified\": 0}","created_at":"2026-11-10T13:05:25"},{"id":9455760,"import_question_id":182186,"audit_type":"KNOWLEDGE","auditor_name":"knowledge-auditor","status":"WARN","score":0.0,"input_snapshot":"若 y 与 x-2 成正比例，且 x=4 时， y=-2 ，求 y 与 x 之间的函数表达式．","result_json":"{\"picks\": [], \"tree_code\": \"KT_JUNIOR_MATH_STANDARD\", \"candidates\": 0, \"classifier_version\": null}","created_at":"2026-11-10T13:05:25"},{"id":9455786,"import_question_id":182186,"audit_type":"VISION","auditor_name":"vision-auditor","status":"PASS","score":0.9,"input_snapshot":"题干：\n若\\(y\\)与\\(x-2\\)成正比例，且\\(x=4\\)时，\\(y=-2\\)，求\\(y\\)与\\(x\\)之间的函数表达式．\n答案：\n\n解析：\n 与x − 2成正比例,设y = (− 2)(k为常数,\\(\\frac{y}{k} \\frac{kx}{代入上式得}\\)且  0).将x = 4, y = −2, − 2 = k(4 − 2), 即− 2 = 2,解得k = − 将k = −1代入y = k(x − 2), frack1( 1. 得 = − x − 2) =−+\\(x \\frac{y}{y} 2\\).  与之间的函数表达式为xy = −+x 2.","result_json":"{\"ok\": true, \"hard\": false, \"issues\": [], \"confidence\": 0.9, \"suggestions\": [\"解析中的排版较为混乱，建议优化公式的呈现方式以提高可读性。\"]}","created_at":"2026-11-10T13:06:37"},{"id":9455802,"import_question_id":182186,"audit_type":"SOLVER","auditor_name":"blind-solver","status":"PASS","score":1.0,"input_snapshot":"若 y 与 x-2 成正比例，且 x=4 时， y=-2 ，求 y 与 x 之间的函数表达式．","result_json":"{\"basis\": \"设 y = k(x - 2)，代入 x = 4, y = -2 得 -2 = k(4 - 2) ⇒ k = -1，故 y = -1·(x - 2) = -x + 2。\", \"answer\": \"y = -x + 2\", \"confidence\": 1.0, \"handout_chars\": 0}","created_at":"2026-11-10T13:06:56"},{"id":9455804,"import_question_id":182186,"audit_type":"CRITIC","auditor_name":"critic","status":"PASS","score":1.0,"input_snapshot":"来源答案: || 盲解:y = -x + 2","result_json":"{\"ok\": true, \"issues\": [], \"merged\": true, \"confidence\": 1.0}","created_at":"2026-11-10T13:06:56"},{"id":9455805,"import_question_id":182186,"audit_type":"SYMBOLIC","auditor_name":"symbolic-auditor","status":"WARN","score":0.5,"input_snapshot":"答案: || 盲解:y = -x + 2","result_json":"{\"checks\": [], \"detail\": {\"reason\": \"未提取到来源答案\"}, \"status\": \"WARN\", \"applicable\": true}","created_at":"2026-11-10T13:06:56"}]}