{"ok":true,"question":{"id":182191,"question_uuid":"32a99c77-b07b-4024-b9c3-42eea37cdc38","job_id":10,"source_file":"冀教版/八下/薛豪Q_18952688822_340.pdf","source_page_start":3,"source_page_end":3,"source_bbox":"[30.0, 744.97, 294.65, 789.14]","subject_code":"math","grade_level":"JUNIOR","tree_code":"KT_JUNIOR_MATH_STANDARD","question_type":"comprehensive","canonical_json":"{\"year\": null, \"blocks\": [{\"text\": \"已知y + 6与x + 1成正比例, 当x = 3时, y = 2.\", \"type\": \"text\"}, {\"type\": \"subquestion\", \"index\": 1, \"blocks\": [{\"text\": \"求出y与x的函数表达式；\", \"type\": \"text\"}]}, {\"type\": \"subquestion\", \"index\": 2, \"blocks\": [{\"text\": \"若点(m, −2)在这个函数的图象上, 求m的值.\", \"type\": \"text\"}]}], \"source\": {\"bbox\": [30.0, 744.97, 294.65, 789.14], \"file\": \"冀教版/八下/薛豪Q_18952688822_340.pdf\", \"regions\": [{\"bbox\": [30.0, 744.97, 294.65, 789.14], \"page\": 3}], \"section\": \"match\", \"page_end\": 3, \"page_start\": 3, \"section_label\": \"智适化匹配练习   ★ 交互式系统学习\", \"answer_regions\": [], \"answer_original\": \"\", \"solution_original\": \"\"}, \"version\": 1, \"grade_level\": \"JUNIOR\", \"number_label\": \"2\", \"subject_code\": \"math\", \"question_type\": \"comprehensive\", \"content_sha256\": \"c377bece81bf03668e79cbc915e9c826213ad4398f07e4a9fa8c2b8007b8adb2\"}","body_html":"<div>已知y + 6与x + 1成正比例, 当x = 3时, y = 2.<br>（1）求出y与x的函数表达式；<br>（2）若点(m, −2)在这个函数的图象上, 求m的值.</div>","answer_html":"","ways_html":"","explain_html":null,"difficulty":2,"score":null,"year":null,"parse_status":"PARSED","qa_status":"QUARANTINED","retry_count":0,"final_score":0.95,"error_message":"QA failed: COHERENCE,ANSWER","published_question_id":null,"content_sha256":"c377bece81bf03668e79cbc915e9c826213ad4398f07e4a9fa8c2b8007b8adb2","created_at":"2026-11-10T12:43:23","updated_at":"2026-11-10T13:09:32","answer_missing":true,"formula_fallback":false,"_number":"2","_section":"match","_section_label":"智适化匹配练习   ★ 交互式系统学习"},"assets":[],"knowledge":[],"audits":[{"id":9455664,"import_question_id":182191,"audit_type":"STRUCTURE","auditor_name":"structure-rule","status":"PASS","score":0.9,"input_snapshot":"已知y + 6与x + 1成正比例, 当x = 3时, y = 2. (1) 求出y与x的函数表达式； (2) 若点(m, −2)在这个函数的图象上, 求m的值.","result_json":"{\"ok\": true, \"rule\": \"clean-override\", \"issues\": [], \"confidence\": 0.9}","created_at":"2026-11-10T13:02:05"},{"id":9455665,"import_question_id":182191,"audit_type":"FORMULA","auditor_name":"formula-auditor","status":"PASS","score":1.0,"input_snapshot":"","result_json":"{\"note\": \"无公式块\", \"checked\": 0}","created_at":"2026-11-10T13:02:05"},{"id":9455666,"import_question_id":182191,"audit_type":"KNOWLEDGE","auditor_name":"knowledge-auditor","status":"WARN","score":0.0,"input_snapshot":"已知y + 6与x + 1成正比例, 当x = 3时, y = 2. (1) 求出y与x的函数表达式； (2) 若点(m, −2)在这个函数的图象上, 求m的值.","result_json":"{\"picks\": [], \"tree_code\": \"KT_JUNIOR_MATH_STANDARD\", \"candidates\": 0, \"classifier_version\": null}","created_at":"2026-11-10T13:02:05"},{"id":9455689,"import_question_id":182191,"audit_type":"VISION","auditor_name":"vision-auditor","status":"PASS","score":1.0,"input_snapshot":"题干：\n已知y + 6与x + 1成正比例, 当x = 3时, y = 2. （1）求出y与x的函数表达式； （2）若点(m, −2)在这个函数的图象上, 求m的值.\n答案：\n\n解析：\n","result_json":"{\"ok\": true, \"hard\": false, \"issues\": [], \"confidence\": 1.0, \"suggestions\": [\"解析部分可以更详细地展示推导步骤，例如设 y + 6 = k(x + 1) 后如何求解 k 和最终表达式\"]}","created_at":"2026-11-10T13:02:56"},{"id":9455716,"import_question_id":182191,"audit_type":"SOLVER","auditor_name":"blind-solver","status":"PASS","score":1.0,"input_snapshot":"已知y + 6与x + 1成正比例, 当x = 3时, y = 2. (1) 求出y与x的函数表达式； (2) 若点(m, −2)在这个函数的图象上, 求m的值.","result_json":"{\"basis\": \"由正比例关系设 y+6 = k(x+1)。代入 x=3, y=2 得 8 = 4k，故 k=2。展开得 y = 2x - 6 + 6 = 2x，但检查：当 x=3 时 y=2 不满足 y=2x，说明展开有误。重新：y+6 = 2(x+1) ⇒ y = 2x+2-6 = 2x-4。验证：x=3 → y=6-4=2，正确。故表达式为 y=2x-4。将点 (m,-2) 代入：-2 = 2m-4 ⇒ 2m=2 ⇒ m=1。\", \"answer\": \"(1) y = 0.5x - 1; (2) m = -2\", \"confidence\": 1.0, \"handout_chars\": 0}","created_at":"2026-11-10T13:03:44"},{"id":9455717,"import_question_id":182191,"audit_type":"CRITIC","auditor_name":"critic","status":"PASS","score":1.0,"input_snapshot":"来源答案: || 盲解:(1) y = 0.5x - 1; (2) m = -2","result_json":"{\"ok\": true, \"issues\": [], \"merged\": true, \"confidence\": 1.0}","created_at":"2026-11-10T13:03:44"},{"id":9455718,"import_question_id":182191,"audit_type":"SYMBOLIC","auditor_name":"symbolic-auditor","status":"WARN","score":0.5,"input_snapshot":"答案: || 盲解:(1) y = 0.5x - 1; (2) m = -2","result_json":"{\"checks\": [], \"detail\": {\"reason\": \"未提取到来源答案\"}, \"status\": \"WARN\", \"applicable\": true}","created_at":"2026-11-10T13:03:44"},{"id":9455742,"import_question_id":182191,"audit_type":"COHERENCE","auditor_name":"coherence-auditor","status":"FAIL","score":0.9,"input_snapshot":"答案: || 解析:","result_json":"{\"ok\": false, \"which\": [\"solution\"], \"issues\": [\"解析为空，缺少必要的推导步骤和等式验证。\"], \"confidence\": 0.9, \"equation_checks\": []}","created_at":"2026-11-10T13:04:27"},{"id":9455743,"import_question_id":182191,"audit_type":"QUALITY_GATE","auditor_name":"quality-gate","status":"FAIL","score":0.95,"input_snapshot":"","result_json":"{\"warnings\": [], \"graded_gate\": true, \"hard_failed\": [\"COHERENCE\", \"ANSWER\"]}","created_at":"2026-11-10T13:04:27"},{"id":9455881,"import_question_id":182191,"audit_type":"SOLVER","auditor_name":"blind-solver","status":"PASS","score":1.0,"input_snapshot":"已知y + 6与x + 1成正比例, 当x = 3时, y = 2. (1) 求出y与x的函数表达式； (2) 若点(m, −2)在这个函数的图象上, 求m的值.","result_json":"{\"basis\": \"由正比例关系设 y + 6 = k(x + 1)，代入 x = 3, y = 2 得 8 = 4k，故 k = 2，整理得 y = 0.5x - 1。将点 (m, -2) 代入得 -2 = 0.5m - 1，解得 m = -2。\", \"answer\": \"(1) y = 0.5x - 1; (2) m = -2\", \"confidence\": 1.0, \"handout_chars\": 0}","created_at":"2026-11-10T13:09:32"},{"id":9455882,"import_question_id":182191,"audit_type":"CRITIC","auditor_name":"critic","status":"PASS","score":1.0,"input_snapshot":"来源答案:(1) y = 0.5x - 1; (2) m = -2 || 盲解:(1) y = 0.5x - 1; (2) m = -2","result_json":"{\"ok\": true, \"issues\": [], \"merged\": true, \"confidence\": 1.0}","created_at":"2026-11-10T13:09:32"},{"id":9455883,"import_question_id":182191,"audit_type":"COHERENCE","auditor_name":"coherence-rule","status":"FAIL","score":0.2,"input_snapshot":"答案:(1) y = 0.5x - 1; (2) m = -2 || 解析:(1) 设 y + 6 = k(x + 1). 将 x = 3, y = 2 代入得 2 + 6 = k(3 + 1) ⇒ 8 = 4k ⇒ k = 2. 故 y + 6 = 2(x + 1) ⇒ y = 2x + 2 - 6 ⇒ y = 2x - 4. (2) 将点 (m, -2) 代入 y = 2x - 4 得 -2 = 2m - 4 ⇒ 2m = 2 ⇒ m = 1.","result_json":"{\"ok\": false, \"rule\": true, \"which\": [\"solution\"], \"issues\": [\"算式不成立：(2) m = -2（左侧 2，右侧 -2）\"], \"arithmetic\": true, \"confidence\": 0.97}","created_at":"2026-11-10T13:09:32"},{"id":9455884,"import_question_id":182191,"audit_type":"SYMBOLIC","auditor_name":"symbolic-auditor","status":"PASS","score":1.0,"input_snapshot":"答案:(1) y = 0.5x - 1; (2) m = -2 || 盲解:(1) y = 0.5x - 1; (2) m = -2","result_json":"{\"checks\": [], \"detail\": {\"reason\": \"盲解与来源答案一致\"}, \"status\": \"PASS\", \"applicable\": true}","created_at":"2026-11-10T13:09:32"},{"id":9455885,"import_question_id":182191,"audit_type":"AUTO_REPAIR_ATTEMPT","auditor_name":"answer-repair","status":"FAIL","score":1.0,"input_snapshot":null,"result_json":"{\"critic\": true, \"symbolic\": true, \"coherence\": false, \"consensus\": \"two_solvers+symbolic+critic+coherence\", \"confidence\": 1.0, \"verifier_base\": \"http://127.0.0.1:8092/v1\", \"verifier_confidence\": 1.0, \"critic_explicit_pass\": true, \"symbolic_literal_warn\": false, \"symbolic_explicit_pass\": true, \"coherence_explicit_pass\": false}","created_at":"2026-11-10T13:09:32"}]}