{"ok":true,"question":{"id":182330,"question_uuid":"c932a656-30b5-4fcc-aaa5-22c6cd67536a","job_id":11,"source_file":"青岛版/七上/杜辉Q_18951362233_315_检测.pdf","source_page_start":3,"source_page_end":5,"source_bbox":"[30.22, 536.59, 564.07, 61.64]","subject_code":"math","grade_level":"JUNIOR","tree_code":"KT_JUNIOR_MATH_STANDARD","question_type":"comprehensive","canonical_json":"{\"year\": null, \"blocks\": [{\"text\": \"计算(1)(−5) + (−2)；\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\frac{(2)}{(3)} (+4) + (−8)\"}, {\"text\": \"； 0 + (−6)；\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\frac{(4)}{(5)} (+13) + (−2)\"}, {\"text\": \"； (−\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\frac{1}{2}\"}, {\"text\": \") + (+\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\frac{1}{4}\"}, {\"text\": \")； AI智适化学案 学案ID:D10710315089\", \"type\": \"text\"}, {\"type\": \"subquestion\", \"index\": 1, \"blocks\": [{\"text\": \"(−\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\frac{1}{3}\"}, {\"text\": \") + (−\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\frac{1}{3}\"}, {\"text\": \")．\", \"type\": \"text\"}]}, {\"type\": \"answer\", \"blocks\": [{\"text\": \"原式= −(5 + 2) = −7；\", \"type\": \"text\"}]}, {\"type\": \"solution\", \"blocks\": [{\"type\": \"math_inline\", \"latex\": \"\\\\frac{(1)}{(2)}\"}, {\"text\": \"原式= −(8 −4) = −4;\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\frac{(3)}{(4)}\"}, {\"text\": \"原式= −6； 原式= +(13 −2) = 11； (5)原式 = −(\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\frac{1}{2}\"}, {\"text\": \"−\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\frac{1}{4}\"}, {\"text\": \") = −\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\frac{1}{4}\"}, {\"text\": \"； (6)原式 = −（\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\frac{1}{3} + \\\\frac{1}{3}） =\"}, {\"text\": \"−\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\frac{2}{3}\"}]}], \"source\": {\"bbox\": [30.22, 536.59, 564.07, 61.64], \"file\": \"青岛版/七上/杜辉Q_18951362233_315_检测.pdf\", \"regions\": [{\"bbox\": [30.22, 536.59, 158.82, 643.84], \"page\": 3}, {\"bbox\": [244.85, 33.12, 564.07, 61.64], \"page\": 5}], \"section\": \"generic\", \"page_end\": 5, \"page_start\": 3, \"section_label\": \"\", \"answer_regions\": [{\"bbox\": [43.99800109863281, 297.7362976074219, 200.6053009033203, 404.4754943847656], \"page\": 6}]}, \"version\": 1, \"grade_level\": \"JUNIOR\", \"number_label\": \"15\", \"subject_code\": \"math\", \"question_type\": \"comprehensive\", \"content_sha256\": \"14cae8d3c9d9446e14d20d61d816be5d8fd3ef41f5575012f6b70193d75fc36a\"}","body_html":"<div>计算(1)(−5) + (−2)；\\(\\frac{(2)}{(3)} (+4) + (−8)\\)； 0 + (−6)；\\(\\frac{(4)}{(5)} (+13) + (−2)\\)； (−\\(\\frac{1}{2}\\)) + (+\\(\\frac{1}{4}\\))； AI智适化学案 学案ID:D10710315089<br>（1）(−\\(\\frac{1}{3}\\)) + (−\\(\\frac{1}{3}\\))．</div>","answer_html":"原式= −(5 + 2) = −7；","ways_html":"\\(\\frac{(1)}{(2)}\\)原式= −(8 −4) = −4;\\(\\frac{(3)}{(4)}\\)原式= −6； 原式= +(13 −2) = 11； (5)原式 = −(\\(\\frac{1}{2}\\)−\\(\\frac{1}{4}\\)) = −\\(\\frac{1}{4}\\)； (6)原式 = −（\\(\\frac{1}{3} + \\frac{1}{3}） =\\)−\\(\\frac{2}{3}\\)","explain_html":null,"difficulty":2,"score":null,"year":null,"parse_status":"PARSED","qa_status":"QUARANTINED","retry_count":0,"final_score":null,"error_message":"处理异常: LLM call failed after retries: HTTPConnectionPool(host='127.0.0.1', port=8092): Read timed out. (read timeout=120) [endpoints: http://127.0.0.1:8091/v1 -> http://127.0.0.1:8092/v1]","published_question_id":null,"content_sha256":"14cae8d3c9d9446e14d20d61d816be5d8fd3ef41f5575012f6b70193d75fc36a","created_at":"2026-11-10T13:43:25","updated_at":"2026-11-10T14:26:08","answer_missing":false,"formula_fallback":false,"_number":"15","_section":"generic","_section_label":""},"assets":[],"knowledge":[],"audits":[{"id":9470944,"import_question_id":182330,"audit_type":"STRUCTURE","auditor_name":"structure-rule","status":"PASS","score":0.9,"input_snapshot":"计算(1)(−5) + (−2)； \\frac{(2)}{(3)} (+4) + (−8) ； 0 + (−6)； \\frac{(4)}{(5)} (+13) + (−2) ； (− \\frac{1}{2} ) + (+ \\frac{1}{4} )； AI智适化学案 学案ID:D10710315089 (1) (− \\frac{1}{3} ) + (− \\frac{1}{3} )．","result_json":"{\"ok\": true, \"rule\": \"clean-override\", \"issues\": [], \"confidence\": 0.9}","created_at":"2026-11-10T14:20:35"},{"id":9470945,"import_question_id":182330,"audit_type":"FORMULA","auditor_name":"formula-auditor","status":"PASS","score":1.0,"input_snapshot":"\\frac{(2)}{(3)} (+4) + (−8); \\frac{(4)}{(5)} (+13) + (−2); \\frac{1}{2}; \\frac{1}{4}; \\frac{1}{3}","result_json":"{\"risky\": 13, \"issues\": [], \"checked\": 13, \"invalid\": 0, \"visual_check\": \"delegated_to_question_vision\", \"invalid_details\": [], \"visually_verified\": 0}","created_at":"2026-11-10T14:20:35"},{"id":9470946,"import_question_id":182330,"audit_type":"KNOWLEDGE","auditor_name":"knowledge-auditor","status":"WARN","score":0.0,"input_snapshot":"计算(1)(−5) + (−2)； \\frac{(2)}{(3)} (+4) + (−8) ； 0 + (−6)； \\frac{(4)}{(5)} (+13) + (−2) ； (− \\frac{1}{2} ) + (+ \\frac{1}{4} )； AI智适化学案 学案ID:D10710315089 (1) (− \\frac{1}{3} ) + (− \\frac{1}{3} )．","result_json":"{\"picks\": [], \"tree_code\": \"KT_JUNIOR_MATH_STANDARD\", \"candidates\": 0, \"classifier_version\": null}","created_at":"2026-11-10T14:20:35"},{"id":9470977,"import_question_id":182330,"audit_type":"VISION","auditor_name":"vision-auditor","status":"WARN","score":0.2,"input_snapshot":"题干：\n计算(1)(−5) + (−2)；\\(\\frac{(2)}{(3)} (+4) + (−8)\\)； 0 + (−6)；\\(\\frac{(4)}{(5)} (+13) + (−2)\\)； (−\\(\\frac{1}{2}\\)) + (+\\(\\frac{1}{4}\\))； AI智适化学案 学案ID:D10710315089 （1）(−\\(\\frac{1}{3}\\)) + (−\\(\\frac{1}{3}\\))．\n答案：\n原式= −(5 + 2) = −7；\n解析：\n\\(\\frac{(1)}{(2)}\\)原式= −(8 −4) = −4;\\(\\frac{(3)}{(4)}\\)原式= −6； 原式= +(13 −2) = 11； (5)原式 = −(\\(\\frac{1}{2}\\)−\\(\\frac{1}{4}\\)) = −\\(\\frac{1}{4}\\)； (6)原式 = −（\\(\\frac{1}{3} + \\frac{1}{3}） =\\)−\\(\\frac{2}{3}\\)","result_json":"{\"note\": \"视觉比对不可用\", \"error\": \"invalid_json_root\", \"unavailable\": true}","created_at":"2026-11-10T14:21:57"},{"id":9470980,"import_question_id":182330,"audit_type":"SOLVER","auditor_name":"blind-solver","status":"PASS","score":1.0,"input_snapshot":"计算(1)(−5) + (−2)； \\frac{(2)}{(3)} (+4) + (−8) ； 0 + (−6)； \\frac{(4)}{(5)} (+13) + (−2) ； (− \\frac{1}{2} ) + (+ \\frac{1}{4} )； AI智适化学案 学案ID:D10710315089 (1) (− \\frac{1}{3} ) + (− \\frac{1}{3} )．","result_json":"{\"basis\": \"有理数加法法则：同号相加取相同符号并相加绝对值；异号相加取绝对值较大数的符号，并用较大绝对值减去较小绝对值；任何数加0仍得原数。\", \"answer\": \"(1) -7; (2) -4; (3) -6; (4) 11; (5) -1/4; (6) -2/3\", \"confidence\": 1.0, \"handout_chars\": 0}","created_at":"2026-11-10T14:22:08"},{"id":9470981,"import_question_id":182330,"audit_type":"CRITIC","auditor_name":"critic","status":"PASS","score":1.0,"input_snapshot":"来源答案:原式= −(5 + 2) = −7； || 盲解:(1) -7; (2) -4; (3) -6; (4) 11; (5) -1/4; (6) -2/3","result_json":"{\"ok\": true, \"issues\": [], \"merged\": true, \"confidence\": 1.0}","created_at":"2026-11-10T14:22:08"},{"id":9470982,"import_question_id":182330,"audit_type":"SYMBOLIC","auditor_name":"symbolic-auditor","status":"WARN","score":0.55,"input_snapshot":"答案:原式= −(5 + 2) = −7； || 盲解:(1) -7; (2) -4; (3) -6; (4) 11; (5) -1/4; (6) -2/3","result_json":"{\"checks\": [], \"detail\": {\"reason\": \"盲解与来源答案存在字面差异，需 Critic 复核\"}, \"status\": \"WARN\", \"applicable\": true}","created_at":"2026-11-10T14:22:08"}]}