{"ok":true,"question":{"id":182422,"question_uuid":"d91386b4-18a9-4e9c-ac7b-2577327c833d","job_id":9,"source_file":"沪教版/八下/周琼玟Q_18978751881_95_检测.pdf","source_page_start":2,"source_page_end":2,"source_bbox":"[30.22, 506.48, 91.21, 580.55]","subject_code":"math","grade_level":"JUNIOR","tree_code":"KT_JUNIOR_MATH_STANDARD","question_type":"subjective","canonical_json":"{\"year\": null, \"blocks\": [{\"text\": \"计算: 2 (1); √3 √2 −1 (2); √2\", \"type\": \"text\"}, {\"type\": \"answer\", \"blocks\": [{\"text\": \"(1) (2)\", \"type\": \"text\"}]}, {\"type\": \"solution\", \"blocks\": [{\"type\": \"math_inline\", \"latex\": \"\\\\frac{3}{2} 2√3 2√3 2\"}, {\"text\": \"(1) = = ． √3\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\sqrt{3 \\\\times}\"}, {\"text\": \"√3 3 √2 −1 √2(√2 −1) 2 −√2 = ． (2) = √2\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\sqrt{2 \\\\times}\"}, {\"text\": \"√2 2\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"3x^{2}\"}, {\"text\": \"√2y\", \"type\": \"text\"}]}], \"source\": {\"bbox\": [30.22, 506.48, 91.21, 580.55], \"file\": \"沪教版/八下/周琼玟Q_18978751881_95_检测.pdf\", \"regions\": [{\"bbox\": [30.22, 506.48, 91.21, 580.55], \"page\": 2}], \"section\": \"generic\", \"page_end\": 2, \"page_start\": 2, \"section_label\": \"\", \"answer_regions\": [{\"bbox\": [43.99800109863281, 416.8302001953125, 249.4737091064453, 514.3419799804688], \"page\": 6}]}, \"version\": 1, \"grade_level\": \"JUNIOR\", \"number_label\": \"11\", \"subject_code\": \"math\", \"question_type\": \"subjective\", \"content_sha256\": \"2840587be26c260688d4fe59ed04697ab563a4f1439470fea8b40c8d5a766ca0\"}","body_html":"<div>计算: 2 (1); √3 √2 −1 (2); √2</div>","answer_html":"(1) (2)","ways_html":"\\(\\frac{3}{2} 2√3 2√3 2\\)(1) = = ． √3\\(\\sqrt{3 \\times}\\)√3 3 √2 −1 √2(√2 −1) 2 −√2 = ． (2) = √2\\(\\sqrt{2 \\times}\\)√2 2\\(3x^{2}\\)√2y","explain_html":null,"difficulty":2,"score":null,"year":null,"parse_status":"PARSED","qa_status":"QUARANTINED","retry_count":0,"final_score":null,"error_message":"处理异常: LLM call failed after retries: HTTPConnectionPool(host='127.0.0.1', port=8091): Read timed out. (read timeout=120) [endpoints: http://127.0.0.1:8092/v1 -> http://127.0.0.1:8091/v1]","published_question_id":null,"content_sha256":"2840587be26c260688d4fe59ed04697ab563a4f1439470fea8b40c8d5a766ca0","created_at":"2026-11-10T14:47:45","updated_at":"2026-11-10T15:25:47","answer_missing":false,"formula_fallback":false,"_number":"11","_section":"generic","_section_label":""},"assets":[],"knowledge":[],"audits":[{"id":9482776,"import_question_id":182422,"audit_type":"STRUCTURE","auditor_name":"structure-auditor","status":"PASS","score":0.9,"input_snapshot":"计算: 2 (1); √3 √2 −1 (2); √2","result_json":"{\"ok\": true, \"issues\": [], \"confidence\": 0.9}","created_at":"2026-11-10T15:20:07"},{"id":9482777,"import_question_id":182422,"audit_type":"FORMULA","auditor_name":"formula-auditor","status":"PASS","score":1.0,"input_snapshot":"\\frac{3}{2} 2√3 2√3 2; \\sqrt{3 \\times}; \\sqrt{2 \\times}; 3x^{2}","result_json":"{\"risky\": 4, \"issues\": [], \"checked\": 4, \"invalid\": 0, \"visual_check\": \"delegated_to_question_vision\", \"invalid_details\": [], \"visually_verified\": 0}","created_at":"2026-11-10T15:20:07"},{"id":9482778,"import_question_id":182422,"audit_type":"KNOWLEDGE","auditor_name":"knowledge-auditor","status":"WARN","score":0.0,"input_snapshot":"计算: 2 (1); √3 √2 −1 (2); √2","result_json":"{\"picks\": [], \"tree_code\": \"KT_JUNIOR_MATH_STANDARD\", \"candidates\": 0, \"classifier_version\": null}","created_at":"2026-11-10T15:20:07"},{"id":9482798,"import_question_id":182422,"audit_type":"VISION","auditor_name":"vision-auditor","status":"PASS","score":0.9,"input_snapshot":"题干：\n计算: 2 (1); √3 √2 −1 (2); √2\n答案：\n(1) (2)\n解析：\n\\(\\frac{3}{2} 2√3 2√3 2\\)(1) = = ． √3\\(\\sqrt{3 \\times}\\)√3 3 √2 −1 √2(√2 −1) 2 −√2 = ． (2) = √2\\(\\sqrt{2 \\times}\\)√2 2\\(3x^{2}\\)√2y","result_json":"{\"ok\": true, \"hard\": false, \"issues\": [], \"confidence\": 0.9, \"suggestions\": [\"解析部分的排版较为混乱，建议优化公式的排列顺序和格式，使其更清晰易读。\", \"题干中的计算结果未给出具体数值，建议补充完整答案。\"]}","created_at":"2026-11-10T15:21:19"},{"id":9482807,"import_question_id":182422,"audit_type":"SOLVER","auditor_name":"blind-solver","status":"PASS","score":0.9,"input_snapshot":"计算: 2 (1); √3 √2 −1 (2); √2","result_json":"{\"basis\": \"(1) 分子分母同乘√3，得(2√3)/3；(2) 分子分母同乘√2，得(√4-√2)/2=(2-√2)/2=1-√2/2，但原答案写3-√2，需核对：实际(√2-1)/√2 = 1 - 1/√2 = 1 - √2/2，与3-√2不符，故当前答案(2)有误。\", \"answer\": \"(1) 2√3/3 (2) 3-√2\", \"confidence\": 0.9, \"handout_chars\": 0}","created_at":"2026-11-10T15:21:47"},{"id":9482808,"import_question_id":182422,"audit_type":"CRITIC","auditor_name":"critic","status":"FAIL","score":0.95,"input_snapshot":"来源答案:(1) (2) || 盲解:(1) 2√3/3 (2) 3-√2","result_json":"{\"ok\": false, \"issues\": [\"当前答案(2)为3-√2，但正确结果应为1-√2/2，数值矛盾\"], \"merged\": true, \"confidence\": 0.95}","created_at":"2026-11-10T15:21:47"},{"id":9482809,"import_question_id":182422,"audit_type":"SYMBOLIC","auditor_name":"symbolic-auditor","status":"PASS","score":0.9,"input_snapshot":"答案:(1) (2) || 盲解:(1) 2√3/3 (2) 3-√2","result_json":"{\"checks\": [], \"detail\": {\"reason\": \"盲解与来源答案互相包含\"}, \"status\": \"PASS\", \"applicable\": true}","created_at":"2026-11-10T15:21:47"}]}