{"ok":true,"question":{"id":182439,"question_uuid":"ad8a1dbe-8dc6-4de3-84ea-16f86927fa74","job_id":10,"source_file":"冀教版/八下/薛豪Q_18952688822_355_检测.pdf","source_page_start":2,"source_page_end":2,"source_bbox":"[30.22, 756.05, 258.58, 796.95]","subject_code":"math","grade_level":"JUNIOR","tree_code":"KT_JUNIOR_MATH_STANDARD","question_type":"subjective","canonical_json":"{\"year\": null, \"blocks\": [{\"text\": \"已知y+ 1与x成正比例,当x= 3时,y=\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"5. \\\\frac{(1)}{(2)}\"}, {\"text\": \"求出y与x的函数关系式； 设点(a, −2)在这个函数的图象上, 求a的值;\", \"type\": \"text\"}, {\"type\": \"answer\", \"blocks\": [{\"text\": \"(1)y= 2x−1；(2)a= −\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\frac{1}{2}\"}]}, {\"type\": \"solution\", \"blocks\": [{\"text\": \"由题意,设y+ 1 =kx,∵ 当 x= 3时,y= 5,∴ 5 + 1 = 3k,∴ k= 2,∴ y+ 1 = 2x,即 y= 2x−1;\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\frac{(1)}{(2)}\"}, {\"text\": \"∵ 点(a, −2)在函数y= 2x−1的图象上,∴ −2 = 2a−1,∴ a= −\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\frac{1}{2}\"}]}], \"source\": {\"bbox\": [30.22, 756.05, 258.58, 796.95], \"file\": \"冀教版/八下/薛豪Q_18952688822_355_检测.pdf\", \"regions\": [{\"bbox\": [30.22, 756.05, 258.58, 796.95], \"page\": 2}], \"section\": \"generic\", \"page_end\": 2, \"page_start\": 2, \"section_label\": \"\", \"answer_regions\": [{\"bbox\": [43.99800109863281, 307.167236328125, 538.24169921875, 373.3424377441406], \"page\": 5}]}, \"version\": 1, \"grade_level\": \"JUNIOR\", \"number_label\": \"13\", \"subject_code\": \"math\", \"question_type\": \"subjective\", \"content_sha256\": \"c7381f7d55eb9f308f2eb2240931138eab1485c8970cc704f29e06b0f9668da7\"}","body_html":"<div>已知y+ 1与x成正比例,当x= 3时,y=\\(5. \\frac{(1)}{(2)}\\)求出y与x的函数关系式； 设点(a, −2)在这个函数的图象上, 求a的值;</div>","answer_html":"(1)y= 2x−1；(2)a= −\\(\\frac{1}{2}\\)","ways_html":"由题意,设y+ 1 =kx,∵ 当 x= 3时,y= 5,∴ 5 + 1 = 3k,∴ k= 2,∴ y+ 1 = 2x,即 y= 2x−1;\\(\\frac{(1)}{(2)}\\)∵ 点(a, −2)在函数y= 2x−1的图象上,∴ −2 = 2a−1,∴ a= −\\(\\frac{1}{2}\\)","explain_html":null,"difficulty":2,"score":null,"year":null,"parse_status":"PARSED","qa_status":"QUARANTINED","retry_count":0,"final_score":null,"error_message":"处理异常: LLM call failed after retries: HTTPConnectionPool(host='127.0.0.1', port=8091): Read timed out. (read timeout=120) [endpoints: http://127.0.0.1:8092/v1 -> http://127.0.0.1:8091/v1]","published_question_id":null,"content_sha256":"c7381f7d55eb9f308f2eb2240931138eab1485c8970cc704f29e06b0f9668da7","created_at":"2026-11-10T14:57:26","updated_at":"2026-11-10T15:23:47","answer_missing":false,"formula_fallback":false,"_number":"13","_section":"generic","_section_label":""},"assets":[],"knowledge":[],"audits":[{"id":9480035,"import_question_id":182439,"audit_type":"STRUCTURE","auditor_name":"structure-rule","status":"PASS","score":0.9,"input_snapshot":"已知y+ 1与x成正比例,当x= 3时,y= 5. \\frac{(1)}{(2)} 求出y与x的函数关系式； 设点(a, −2)在这个函数的图象上, 求a的值;","result_json":"{\"ok\": true, \"rule\": \"clean-override\", \"issues\": [], \"confidence\": 0.9}","created_at":"2026-11-10T15:18:38"},{"id":9480036,"import_question_id":182439,"audit_type":"FORMULA","auditor_name":"formula-auditor","status":"PASS","score":1.0,"input_snapshot":"5. \\frac{(1)}{(2)}; \\frac{1}{2}; \\frac{(1)}{(2)}; \\frac{1}{2}","result_json":"{\"risky\": 4, \"issues\": [], \"checked\": 4, \"invalid\": 0, \"visual_check\": \"delegated_to_question_vision\", \"invalid_details\": [], \"visually_verified\": 0}","created_at":"2026-11-10T15:18:38"},{"id":9480037,"import_question_id":182439,"audit_type":"KNOWLEDGE","auditor_name":"knowledge-auditor","status":"WARN","score":0.0,"input_snapshot":"已知y+ 1与x成正比例,当x= 3时,y= 5. \\frac{(1)}{(2)} 求出y与x的函数关系式； 设点(a, −2)在这个函数的图象上, 求a的值;","result_json":"{\"picks\": [], \"tree_code\": \"KT_JUNIOR_MATH_STANDARD\", \"candidates\": 0, \"classifier_version\": null}","created_at":"2026-11-10T15:18:38"},{"id":9480059,"import_question_id":182439,"audit_type":"VISION","auditor_name":"vision-auditor","status":"PASS","score":1.0,"input_snapshot":"题干：\n已知y+ 1与x成正比例,当x= 3时,y=\\(5. \\frac{(1)}{(2)}\\)求出y与x的函数关系式； 设点(a, −2)在这个函数的图象上, 求a的值;\n答案：\n(1)y= 2x−1；(2)a= −\\(\\frac{1}{2}\\)\n解析：\n由题意,设y+ 1 =kx,∵ 当 x= 3时,y= 5,∴ 5 + 1 = 3k,∴ k= 2,∴ y+ 1 = 2x,即 y= 2x−1;\\(\\frac{(1)}{(2)}\\)∵ 点(a, −2)在函数y= 2x−1的图象上,∴ −2 = 2a−1,∴ a= −\\(\\frac{1}{2}\\)","result_json":"{\"ok\": true, \"hard\": false, \"issues\": [], \"confidence\": 1.0, \"suggestions\": [\"题干中'求出y与x的函数关系式'可补充说明'并化简'，使表述更完整\"]}","created_at":"2026-11-10T15:19:17"},{"id":9482466,"import_question_id":182439,"audit_type":"SOLVER","auditor_name":"blind-solver","status":"PASS","score":1.0,"input_snapshot":"已知y+ 1与x成正比例,当x= 3时,y= 5. \\frac{(1)}{(2)} 求出y与x的函数关系式； 设点(a, −2)在这个函数的图象上, 求a的值;","result_json":"{\"basis\": \"由'y+1与x成正比例'设y+1=kx。代入x=3,y=5得5+1=3k⇒k=2，故y+1=2x，即y=2x-1。将点(a,-2)代入得-2=2a-1⇒2a=-1⇒a=-1/2。\", \"answer\": \"(1) y = 2x - 1; (2) a = -1/2\", \"confidence\": 1.0, \"handout_chars\": 0}","created_at":"2026-11-10T15:19:47"},{"id":9482467,"import_question_id":182439,"audit_type":"CRITIC","auditor_name":"critic","status":"PASS","score":1.0,"input_snapshot":"来源答案:(1)y= 2x−1；(2)a= −\\(\\frac{1}{2}\\) || 盲解:(1) y = 2x - 1; (2) a = -1/2","result_json":"{\"ok\": true, \"issues\": [], \"merged\": true, \"confidence\": 1.0}","created_at":"2026-11-10T15:19:47"},{"id":9482469,"import_question_id":182439,"audit_type":"SYMBOLIC","auditor_name":"symbolic-auditor","status":"WARN","score":0.55,"input_snapshot":"答案:(1)y= 2x−1；(2)a= −\\(\\frac{1}{2}\\) || 盲解:(1) y = 2x - 1; (2) a = -1/2","result_json":"{\"checks\": [], \"detail\": {\"reason\": \"盲解与来源答案存在字面差异，需 Critic 复核\"}, \"status\": \"WARN\", \"applicable\": true}","created_at":"2026-11-10T15:19:47"}]}