{"ok":true,"question":{"id":182440,"question_uuid":"8b08813b-435f-4d4a-9369-65d0a6bb7d28","job_id":10,"source_file":"冀教版/八下/薛豪Q_18952688822_355_检测.pdf","source_page_start":3,"source_page_end":3,"source_bbox":"[30.22, 243.64, 283.47, 284.03]","subject_code":"math","grade_level":"JUNIOR","tree_code":"KT_JUNIOR_MATH_STANDARD","question_type":"subjective","canonical_json":"{\"year\": null, \"blocks\": [{\"text\": \"已知y+ 2与x−1成正比例,且当x= 3时,y=\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"2. \\\\frac{(1)}{(2)}\"}, {\"text\": \"求y与x的函数解析式； 若点(2n −1, 6)在这个函数图象上, 求n的值.\", \"type\": \"text\"}, {\"type\": \"answer\", \"blocks\": [{\"text\": \"(1) y = 2x - 4(2) 3\", \"type\": \"text\"}]}, {\"type\": \"solution\", \"blocks\": [{\"text\": \"(1)∵ y+ 2与x−1成正比例,∴ 设函数解析式为y+ 2 =k(x−1),整理得 :y= kx− k−2,∵ 当x= 3时,y= 2,∴ 3k− k−2 = 2,解得k= 2,∴ y与x的函数解析式为y= 2x−4; (2)代入点(2n−1, 6)到y= 2x−4,得2(2n−1) −4 = 6,解得n= 3,∴ n的值为3.\", \"type\": \"text\"}]}], \"source\": {\"bbox\": [30.22, 243.64, 283.47, 284.03], \"file\": \"冀教版/八下/薛豪Q_18952688822_355_检测.pdf\", \"regions\": [{\"bbox\": [30.22, 243.64, 283.47, 284.03], \"page\": 3}], \"section\": \"generic\", \"page_end\": 3, \"page_start\": 3, \"section_label\": \"\", \"answer_regions\": [{\"bbox\": [43.99800109863281, 372.68853759765625, 517.9622802734375, 425.9110412597656], \"page\": 5}]}, \"version\": 1, \"grade_level\": \"JUNIOR\", \"number_label\": \"14\", \"subject_code\": \"math\", \"question_type\": \"subjective\", \"content_sha256\": \"733e3d2a990103d36ed4ac09fcb40570c993ab6844e430b9e92a6079552852e8\"}","body_html":"<div>已知y+ 2与x−1成正比例,且当x= 3时,y=\\(2. \\frac{(1)}{(2)}\\)求y与x的函数解析式； 若点(2n −1, 6)在这个函数图象上, 求n的值.</div>","answer_html":"(1) y = 2x - 4(2) 3","ways_html":"(1)∵ y+ 2与x−1成正比例,∴ 设函数解析式为y+ 2 =k(x−1),整理得 :y= kx− k−2,∵ 当x= 3时,y= 2,∴ 3k− k−2 = 2,解得k= 2,∴ y与x的函数解析式为y= 2x−4; (2)代入点(2n−1, 6)到y= 2x−4,得2(2n−1) −4 = 6,解得n= 3,∴ n的值为3.","explain_html":null,"difficulty":2,"score":null,"year":null,"parse_status":"PARSED","qa_status":"QUARANTINED","retry_count":0,"final_score":null,"error_message":"处理异常: LLM call failed after retries: HTTPConnectionPool(host='127.0.0.1', port=8092): Read timed out. (read timeout=120) [endpoints: http://127.0.0.1:8091/v1 -> http://127.0.0.1:8092/v1]","published_question_id":null,"content_sha256":"733e3d2a990103d36ed4ac09fcb40570c993ab6844e430b9e92a6079552852e8","created_at":"2026-11-10T14:57:26","updated_at":"2026-11-10T15:23:04","answer_missing":false,"formula_fallback":false,"_number":"14","_section":"generic","_section_label":""},"assets":[],"knowledge":[],"audits":[{"id":9479976,"import_question_id":182440,"audit_type":"STRUCTURE","auditor_name":"structure-rule","status":"PASS","score":0.9,"input_snapshot":"已知y+ 2与x−1成正比例,且当x= 3时,y= 2. \\frac{(1)}{(2)} 求y与x的函数解析式； 若点(2n −1, 6)在这个函数图象上, 求n的值.","result_json":"{\"ok\": true, \"rule\": \"clean-override\", \"issues\": [], \"confidence\": 0.9}","created_at":"2026-11-10T15:15:28"},{"id":9479977,"import_question_id":182440,"audit_type":"FORMULA","auditor_name":"formula-auditor","status":"PASS","score":1.0,"input_snapshot":"2. \\frac{(1)}{(2)}","result_json":"{\"risky\": 1, \"issues\": [], \"checked\": 1, \"invalid\": 0, \"visual_check\": \"delegated_to_question_vision\", \"invalid_details\": [], \"visually_verified\": 0}","created_at":"2026-11-10T15:15:28"},{"id":9479978,"import_question_id":182440,"audit_type":"KNOWLEDGE","auditor_name":"knowledge-auditor","status":"WARN","score":0.0,"input_snapshot":"已知y+ 2与x−1成正比例,且当x= 3时,y= 2. \\frac{(1)}{(2)} 求y与x的函数解析式； 若点(2n −1, 6)在这个函数图象上, 求n的值.","result_json":"{\"picks\": [], \"tree_code\": \"KT_JUNIOR_MATH_STANDARD\", \"candidates\": 0, \"classifier_version\": null}","created_at":"2026-11-10T15:15:28"},{"id":9480010,"import_question_id":182440,"audit_type":"VISION","auditor_name":"vision-auditor","status":"PASS","score":1.0,"input_snapshot":"题干：\n已知y+ 2与x−1成正比例,且当x= 3时,y=\\(2. \\frac{(1)}{(2)}\\)求y与x的函数解析式； 若点(2n −1, 6)在这个函数图象上, 求n的值.\n答案：\n(1) y = 2x - 4(2) 3\n解析：\n(1)∵ y+ 2与x−1成正比例,∴ 设函数解析式为y+ 2 =k(x−1),整理得 :y= kx− k−2,∵ 当x= 3时,y= 2,∴ 3k− k−2 = 2,解得k= 2,∴ y与x的函数解析式为y= 2x−4; (2)代入点(2n−1, 6)到y= 2x−4,得2(2n−1) −4 = 6,解得n= 3,∴ n的值为3.","result_json":"{\"ok\": true, \"hard\": false, \"issues\": [], \"confidence\": 1.0, \"suggestions\": [\"题干中'求y与x的函数解析式；若点(2n −1, 6)在这个函数图象上, 求n的值.'的标点符号和分号使用可优化，建议改为更清晰的表述，如'求y与x的函数解析式。若点(2n −1, 6)在这个函数图象上，求n的值。'以增强可读性。\"]}","created_at":"2026-11-10T15:17:24"},{"id":9480047,"import_question_id":182440,"audit_type":"SOLVER","auditor_name":"blind-solver","status":"PASS","score":1.0,"input_snapshot":"已知y+ 2与x−1成正比例,且当x= 3时,y= 2. \\frac{(1)}{(2)} 求y与x的函数解析式； 若点(2n −1, 6)在这个函数图象上, 求n的值.","result_json":"{\"basis\": \"由'y+2与x-1成正比例'设y+2=k(x-1).代入x=3,y=2得2+2=k(3-1),解得k=2,故y+2=2(x-1),即y=2x-4.将点(2n-1,6)代入y=2x-4得6=2(2n-1)-4,解得n=3.\", \"answer\": \"(1) y = 2x - 4; (2) n = 3\", \"confidence\": 1.0, \"handout_chars\": 0}","created_at":"2026-11-10T15:19:04"},{"id":9480048,"import_question_id":182440,"audit_type":"CRITIC","auditor_name":"critic","status":"PASS","score":1.0,"input_snapshot":"来源答案:(1) y = 2x - 4(2) 3 || 盲解:(1) y = 2x - 4; (2) n = 3","result_json":"{\"ok\": true, \"issues\": [], \"merged\": true, \"confidence\": 1.0}","created_at":"2026-11-10T15:19:04"},{"id":9480049,"import_question_id":182440,"audit_type":"SYMBOLIC","auditor_name":"symbolic-auditor","status":"WARN","score":0.55,"input_snapshot":"答案:(1) y = 2x - 4(2) 3 || 盲解:(1) y = 2x - 4; (2) n = 3","result_json":"{\"checks\": [], \"detail\": {\"reason\": \"盲解与来源答案存在字面差异，需 Critic 复核\"}, \"status\": \"WARN\", \"applicable\": true}","created_at":"2026-11-10T15:19:04"}]}