{"ok":true,"question":{"id":182441,"question_uuid":"7b55eeef-6735-485d-9b02-cee5b4e6651e","job_id":10,"source_file":"冀教版/八下/薛豪Q_18952688822_355_检测.pdf","source_page_start":3,"source_page_end":3,"source_bbox":"[30.22, 425.33, 261.6, 480.01]","subject_code":"math","grade_level":"JUNIOR","tree_code":"KT_JUNIOR_MATH_STANDARD","question_type":"subjective","canonical_json":"{\"year\": null, \"blocks\": [{\"text\": \"已知y−4与x成正比，当x= 1时，y= 2．\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\frac{(1)}{(2)}\"}, {\"text\": \"求y与x之间的函数关系式； 当x= −\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\frac{1}{2}\"}, {\"text\": \"时，求函数y的值．\", \"type\": \"text\"}, {\"type\": \"answer\", \"blocks\": [{\"text\": \"(1)y = −2x + 4(2)5\", \"type\": \"text\"}]}, {\"type\": \"solution\", \"blocks\": [{\"text\": \"(1)设y−4 =kx∵ 当x= 1时，y= 2∴ 2 −4 =k，解得k= −2∴ y−4= −2x, y与x之间的函数关系式为y = −2x + 4； (2)当x= −\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\frac{1}{2}\"}, {\"text\": \"时，y= −\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"2 \\\\times (− \\\\frac{1}{2}) + 4 = 5．\"}]}], \"source\": {\"bbox\": [30.22, 425.33, 261.6, 480.01], \"file\": \"冀教版/八下/薛豪Q_18952688822_355_检测.pdf\", \"regions\": [{\"bbox\": [30.22, 425.33, 261.6, 480.01], \"page\": 3}], \"section\": \"generic\", \"page_end\": 3, \"page_start\": 3, \"section_label\": \"\", \"answer_regions\": [{\"bbox\": [43.99800109863281, 427.8088989257813, 407.9202880859375, 494.8116760253906], \"page\": 5}]}, \"version\": 1, \"grade_level\": \"JUNIOR\", \"number_label\": \"15\", \"subject_code\": \"math\", \"question_type\": \"subjective\", \"content_sha256\": \"aa9cdd237e0adb5e8b0f97c035287340bc67172030662b04699f09d64140ee0b\"}","body_html":"<div>已知y−4与x成正比，当x= 1时，y= 2．\\(\\frac{(1)}{(2)}\\)求y与x之间的函数关系式； 当x= −\\(\\frac{1}{2}\\)时，求函数y的值．</div>","answer_html":"(1)y = −2x + 4(2)5","ways_html":"(1)设y−4 =kx∵ 当x= 1时，y= 2∴ 2 −4 =k，解得k= −2∴ y−4= −2x, y与x之间的函数关系式为y = −2x + 4； (2)当x= −\\(\\frac{1}{2}\\)时，y= −\\(2 \\times (− \\frac{1}{2}) + 4 = 5．\\)","explain_html":null,"difficulty":2,"score":null,"year":null,"parse_status":"PARSED","qa_status":"QUARANTINED","retry_count":0,"final_score":null,"error_message":"处理异常: LLM call failed after retries: HTTPConnectionPool(host='127.0.0.1', port=8091): Read timed out. (read timeout=120) [endpoints: http://127.0.0.1:8092/v1 -> http://127.0.0.1:8091/v1]","published_question_id":null,"content_sha256":"aa9cdd237e0adb5e8b0f97c035287340bc67172030662b04699f09d64140ee0b","created_at":"2026-11-10T14:57:26","updated_at":"2026-11-10T15:24:20","answer_missing":false,"formula_fallback":false,"_number":"15","_section":"generic","_section_label":""},"assets":[],"knowledge":[],"audits":[{"id":9480050,"import_question_id":182441,"audit_type":"STRUCTURE","auditor_name":"structure-rule","status":"PASS","score":0.9,"input_snapshot":"已知y−4与x成正比，当x= 1时，y= 2． \\frac{(1)}{(2)} 求y与x之间的函数关系式； 当x= − \\frac{1}{2} 时，求函数y的值．","result_json":"{\"ok\": true, \"rule\": \"clean-override\", \"issues\": [], \"confidence\": 0.9}","created_at":"2026-11-10T15:19:05"},{"id":9480051,"import_question_id":182441,"audit_type":"FORMULA","auditor_name":"formula-auditor","status":"PASS","score":1.0,"input_snapshot":"\\frac{(1)}{(2)}; \\frac{1}{2}; \\frac{1}{2}; 2 \\times (− \\frac{1}{2}) + 4 = 5．","result_json":"{\"risky\": 4, \"issues\": [], \"checked\": 4, \"invalid\": 0, \"visual_check\": \"delegated_to_question_vision\", \"invalid_details\": [], \"visually_verified\": 0}","created_at":"2026-11-10T15:19:05"},{"id":9480052,"import_question_id":182441,"audit_type":"KNOWLEDGE","auditor_name":"knowledge-auditor","status":"WARN","score":0.0,"input_snapshot":"已知y−4与x成正比，当x= 1时，y= 2． \\frac{(1)}{(2)} 求y与x之间的函数关系式； 当x= − \\frac{1}{2} 时，求函数y的值．","result_json":"{\"picks\": [], \"tree_code\": \"KT_JUNIOR_MATH_STANDARD\", \"candidates\": 0, \"classifier_version\": null}","created_at":"2026-11-10T15:19:05"},{"id":9482770,"import_question_id":182441,"audit_type":"VISION","auditor_name":"vision-auditor","status":"PASS","score":1.0,"input_snapshot":"题干：\n已知y−4与x成正比，当x= 1时，y= 2．\\(\\frac{(1)}{(2)}\\)求y与x之间的函数关系式； 当x= −\\(\\frac{1}{2}\\)时，求函数y的值．\n答案：\n(1)y = −2x + 4(2)5\n解析：\n(1)设y−4 =kx∵ 当x= 1时，y= 2∴ 2 −4 =k，解得k= −2∴ y−4= −2x, y与x之间的函数关系式为y = −2x + 4； (2)当x= −\\(\\frac{1}{2}\\)时，y= −\\(2 \\times (− \\frac{1}{2}) + 4 = 5．\\)","result_json":"{\"ok\": true, \"hard\": false, \"issues\": [], \"confidence\": 1.0, \"suggestions\": [\"题干中“求y与x之间的函数关系式”可补充为“求y关于x的函数关系式”，表述更规范\"]}","created_at":"2026-11-10T15:19:54"},{"id":9482779,"import_question_id":182441,"audit_type":"SOLVER","auditor_name":"blind-solver","status":"PASS","score":1.0,"input_snapshot":"已知y−4与x成正比，当x= 1时，y= 2． \\frac{(1)}{(2)} 求y与x之间的函数关系式； 当x= − \\frac{1}{2} 时，求函数y的值．","result_json":"{\"basis\": \"由'y−4与x成正比'设y−4=kx。代入x=1,y=2得2−4=k·1，故k=−2。因此y−4=−2x，即y=−2x+4。当x=−1/2时，y=−2·(−1/2)+4=1+4=5。\", \"answer\": \"(1) y = -2x + 4; (2) 5\", \"confidence\": 1.0, \"handout_chars\": 0}","created_at":"2026-11-10T15:20:20"},{"id":9482780,"import_question_id":182441,"audit_type":"CRITIC","auditor_name":"critic","status":"PASS","score":1.0,"input_snapshot":"来源答案:(1)y = −2x + 4(2)5 || 盲解:(1) y = -2x + 4; (2) 5","result_json":"{\"ok\": true, \"issues\": [], \"merged\": true, \"confidence\": 1.0}","created_at":"2026-11-10T15:20:20"},{"id":9482781,"import_question_id":182441,"audit_type":"SYMBOLIC","auditor_name":"symbolic-auditor","status":"WARN","score":0.55,"input_snapshot":"答案:(1)y = −2x + 4(2)5 || 盲解:(1) y = -2x + 4; (2) 5","result_json":"{\"checks\": [], \"detail\": {\"reason\": \"盲解与来源答案存在字面差异，需 Critic 复核\"}, \"status\": \"WARN\", \"applicable\": true}","created_at":"2026-11-10T15:20:20"}]}