{"ok":true,"question":{"id":21009,"question_uuid":"d6a8e953-17de-4990-be6c-b094a74897a6","job_id":4,"source_file":"A中考/2026江苏中考期末数学试卷+答案820.pdf","source_page_start":6,"source_page_end":6,"source_bbox":"[31.56, 284.2, 391.63, 537.45]","subject_code":"math","grade_level":"JUNIOR","tree_code":"KT_JUNIOR_MATH_STANDARD","question_type":"single_choice","canonical_json":"{\"year\": null, \"blocks\": [{\"text\": \"[小试2] 如图，⊙O是△ABC的内切圆，若∠A = 80°, 则∠BOC的度数为( ).\", \"type\": \"text\"}, {\"kind\": \"embedded_image\", \"type\": \"figure\", \"width\": 708, \"height\": 598, \"sha256\": \"c209ec6da2e0a55b909c566fd01801d2369b1f32d0e2a0676f082d1118833e63\", \"caption\": \"\", \"asset_key\": \"math/2026/09/16de2e24-a616-456b-83c5-3364ab6bd928/d6a8e953-17de-4990-be6c-b094a74897a6/c209ec6da2e0.png\", \"public_url\": \"http://tikupdfpng.mtwlkj.net:5129/qbank/math/2026/09/16de2e24-a616-456b-83c5-3364ab6bd928/d6a8e953-17de-4990-be6c-b094a74897a6/c209ec6da2e0.png\", \"source_bbox\": [31.5, 313.3199768066406, 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\"label\": \"C\", \"blocks\": [{\"text\": \"130∘\", \"type\": \"text\"}], \"source_bbox\": [31.56, 508.11, 91.82, 521.85], \"source_page\": 6}, {\"type\": \"option\", \"label\": \"D\", \"blocks\": [{\"text\": \"60∘\", \"type\": \"text\"}], \"source_bbox\": [31.56, 523.71, 85.1, 537.45], \"source_page\": 6}, {\"type\": \"answer\", \"blocks\": [{\"text\": \"C\", \"type\": \"text\"}]}, {\"type\": \"solution\", \"blocks\": [{\"text\": \"因为∠A = 80∘, ∴∠ABC + ∠ACB = 180∘−∠A = 100∘, ∵⊙O是\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\Delta{}ABC\"}, {\"text\": \"的内切圆, 所以 OB、OC 分别平分∠ABC、∠ACB, ∴∠OBC = 1\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"1 _{2}\"}, {\"text\": \"∠ABC,∠OCB= _{2}∠ACB, 所以∠OBC + ∠OCB = 1\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"1 _{2}\"}, {\"text\": \"∠ABC + _{2}∠ACB = 50∘, 所以∠BOC= 180∘−∠OBC −∠OCB = 130.\", \"type\": \"text\"}]}], \"source\": {\"bbox\": [31.56, 284.2, 391.63, 537.45], \"file\": \"A中考/2026江苏中考期末数学试卷+答案820.pdf\", \"regions\": [{\"bbox\": [31.56, 284.2, 391.63, 537.45], \"page\": 6}], \"section\": \"quiz\", \"page_end\": 6, \"page_start\": 6, \"section_label\": \"小试牛刀   ★ 独立完成，见证实力！\", \"answer_regions\": [{\"bbox\": [30.0, 263.1, 516.42, 367.63], \"page\": 10}], \"answer_original\": \"C\", \"solution_original\": \"因为∠A = 80∘, ∴∠ABC + ∠ACB = 180∘−∠A = 100∘, ∵⊙O是ΔABC的内切圆, 所以 OB、OC 分别平分∠ABC、∠ACB, ∴∠OBC = 1 1 _{2}∠ABC,∠OCB= _{2}∠ACB, 所以∠OBC + ∠OCB = 1 1 _{2}∠ABC + _{2}∠ACB = 50∘, 所以∠BOC= 180∘−∠OBC −∠OCB = 130.\"}, \"version\": 1, \"grade_level\": \"JUNIOR\", \"number_label\": \"2\", \"subject_code\": \"math\", \"question_type\": \"single_choice\", \"content_sha256\": \"ae076ad730a08157cb616689d2f76430ac0ee23ce623bf4dcdb0bd877b707f7c\"}","body_html":"<div>[小试2] 如图，⊙O是△ABC的内切圆，若∠A = 80°, 则∠BOC的度数为( ).<img class=\"question-figure\" src=\"http://tikupdfpng.mtwlkj.net:5129/qbank/math/2026/09/16de2e24-a616-456b-83c5-3364ab6bd928/d6a8e953-17de-4990-be6c-b094a74897a6/c209ec6da2e0.png\" style=\"width:188.9px!important;max-width:100%;height:auto\" alt=\"\" title=\"点击查看原图\"><img class=\"question-figure\" src=\"http://tikupdfpng.mtwlkj.net:5129/qbank/math/2026/09/16de2e24-a616-456b-83c5-3364ab6bd928/d6a8e953-17de-4990-be6c-b094a74897a6/529a1a20a8b3.png\" style=\"width:54.9px!important;max-width:100%;height:auto\" alt=\"\" title=\"点击查看原图\"><br>A. 40∘<br>B. 150∘<br>C. 130∘<br>D. 60∘</div>","answer_html":"C","ways_html":"因为∠A = 80∘, ∴∠ABC + ∠ACB = 180∘−∠A = 100∘, ∵⊙O是\\(\\Delta{}ABC\\)的内切圆, 所以 OB、OC 分别平分∠ABC、∠ACB, ∴∠OBC = 1\\(1 _{2}\\)∠ABC,∠OCB= _{2}∠ACB, 所以∠OBC + ∠OCB = 1\\(1 _{2}\\)∠ABC + _{2}∠ACB = 50∘, 所以∠BOC= 180∘−∠OBC −∠OCB = 130.","explain_html":null,"difficulty":2,"score":null,"year":null,"parse_status":"PARSED","qa_status":"QUARANTINED","retry_count":0,"final_score":0.75,"error_message":"QA failed: 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[图] [图] A. 40∘ B. 150∘ C. 130∘ D. 60∘","result_json":"{\"picks\": [], \"tree_code\": \"KT_JUNIOR_MATH_STANDARD\", \"candidates\": 0, \"classifier_version\": null}","created_at":"2026-09-24T21:59:20"},{"id":413387,"import_question_id":21009,"audit_type":"VISION","auditor_name":"vision-auditor","status":"WARN","score":0.2,"input_snapshot":"题干：\n[小试2] 如图，⊙O是△ABC的内切圆，若∠A = 80°, 则∠BOC的度数为( ). A. 40∘ B. 150∘ C. 130∘ D. 60∘\n答案：\nC\n解析：\n因为∠A = 80∘, ∴∠ABC + ∠ACB = 180∘−∠A = 100∘, ∵⊙O是\\(\\Delta{}ABC\\)的内切圆, 所以 OB、OC 分别平分∠ABC、∠ACB, ∴∠OBC = 1\\(1 _{2}\\)∠ABC,∠OCB= _{2}∠ACB, 所以∠OBC + ∠OCB = 1\\(1 _{2}\\)∠ABC + _{2}∠ACB = 50∘, 所以∠BOC= 180∘−∠OBC −∠OCB = 130.","result_json":"{\"note\": \"视觉比对不可用\", \"error\": \"invalid_json_root\", \"unavailable\": true}","created_at":"2026-09-24T22:00:30"},{"id":413391,"import_question_id":21009,"audit_type":"SOLVER","auditor_name":"blind-solver","status":"PASS","score":1.0,"input_snapshot":"[小试2] 如图，⊙O是△ABC的内切圆，若∠A = 80°, 则∠BOC的度数为( ). [图] [图] A. 40∘ B. 150∘ C. 130∘ D. 60∘","result_json":"{\"basis\": \"因为⊙O是△ABC的内切圆，所以O是内心，OB、OC分别平分∠ABC和∠ACB。在△ABC中，∠A=80°，则∠ABC+∠ACB=180°-80°=100°。因此，∠OBC+∠OCB = 1/2(∠ABC+∠ACB) = 50°。在△BOC中，∠BOC = 180° - (∠OBC+∠OCB) = 180° - 50° = 130°。\", \"answer\": \"C\", \"confidence\": 1.0, \"handout_chars\": 0}","created_at":"2026-09-24T22:00:42"},{"id":413392,"import_question_id":21009,"audit_type":"CRITIC","auditor_name":"critic","status":"PASS","score":1.0,"input_snapshot":"来源答案:C || 盲解:C","result_json":"{\"ok\": true, \"issues\": [], \"merged\": true, \"confidence\": 1.0}","created_at":"2026-09-24T22:00:42"},{"id":413393,"import_question_id":21009,"audit_type":"SYMBOLIC","auditor_name":"symbolic-auditor","status":"PASS","score":1.0,"input_snapshot":"答案:C || 盲解:C","result_json":"{\"checks\": [], \"detail\": {\"reason\": \"盲解与来源答案一致\"}, \"status\": \"PASS\", \"applicable\": true}","created_at":"2026-09-24T22:00:42"},{"id":413408,"import_question_id":21009,"audit_type":"COHERENCE","auditor_name":"coherence-auditor","status":"PASS","score":0.9,"input_snapshot":"答案:C || 解析:因为∠A = 80∘, ∴∠ABC + ∠ACB = 180∘−∠A = 100∘, ∵⊙O是\\(\\Delta{}ABC\\)的内切圆, 所以 OB、OC 分别平分∠ABC、∠ACB, ∴∠OBC = 1\\(1 _{2}\\)∠ABC,∠OCB= _{2}∠ACB, 所以∠OBC + ∠OCB = 1\\(1 _{2}\\)∠ABC + _{2}∠ACB = 50∘, 所以∠BOC= 180∘−∠OBC ","result_json":"{\"ok\": true, \"which\": [], \"issues\": [], \"confidence\": 0.9, \"equation_checks\": []}","created_at":"2026-09-24T22:01:56"},{"id":413409,"import_question_id":21009,"audit_type":"QUALITY_GATE","auditor_name":"quality-gate","status":"FAIL","score":0.75,"input_snapshot":"","result_json":"{\"warnings\": [], \"graded_gate\": true, \"hard_failed\": [\"VISION\"]}","created_at":"2026-09-24T22:01:56"}]}