{"ok":true,"question":{"id":21101,"question_uuid":"c13e9fcd-e727-4538-b1c4-2f427804da2e","job_id":4,"source_file":"A中考/2026江苏中考期末数学试卷+答案830.pdf","source_page_start":7,"source_page_end":7,"source_bbox":"[30.0, 158.14, 552.42, 229.24]","subject_code":"math","grade_level":"JUNIOR","tree_code":"KT_JUNIOR_MATH_STANDARD","question_type":"comprehensive","canonical_json":"{\"year\": null, \"blocks\": [{\"text\": \"⏜ 3.正方形 ABCD 内接于 ⊙O,如图所示,在劣弧AB上取一点 E,连接 DE,BE,过点 D 作 DF ∥BE 交于点 F, 连接BF, AF, 且AF与DE相交于点G,求证:\", \"type\": \"text\"}, {\"kind\": \"embedded_image\", \"type\": \"figure\", \"width\": 708, \"height\": 509, \"sha256\": \"c9aa0bab976e6fd994fa0078e017bc4c60985f277ab699d0d2d980c0b71aaf0b\", \"caption\": \"\", \"asset_key\": \"math/2026/09/16de2e24-a616-456b-83c5-3364ab6bd928/c13e9fcd-e727-4538-b1c4-2f427804da2e/c9aa0bab976e.png\", \"public_url\": \"http://tikupdfpng.mtwlkj.net:5129/qbank/math/2026/09/16de2e24-a616-456b-83c5-3364ab6bd928/c13e9fcd-e727-4538-b1c4-2f427804da2e/c9aa0bab976e.png\", \"source_bbox\": [30.0, 230.1499786376953, 171.6999969482422, 339.0999755859375], \"source_page\": 7}, {\"type\": \"subquestion\", \"index\": 1, \"blocks\": [{\"text\": \"四边形EBFD是矩形;\", \"type\": \"text\"}]}, {\"type\": \"subquestion\", \"index\": 2, \"blocks\": [{\"text\": \"DG = BE.\", \"type\": \"text\"}]}], \"source\": {\"bbox\": [30.0, 158.14, 552.42, 229.24], \"file\": \"A中考/2026江苏中考期末数学试卷+答案830.pdf\", \"regions\": [{\"bbox\": [30.0, 158.14, 552.42, 229.24], \"page\": 7}], \"section\": \"match\", \"page_end\": 7, \"page_start\": 7, \"section_label\": \"智适化匹配练习   ★ 交互式系统学习\", \"answer_regions\": [], \"answer_original\": \"\", \"solution_original\": \"\"}, \"version\": 1, \"grade_level\": \"JUNIOR\", \"number_label\": \"3\", \"subject_code\": \"math\", \"question_type\": \"comprehensive\", \"content_sha256\": \"1dbea0a3fcbdbde247666b7b29f86612d067f7366496756b376a4bdfa38c6511\"}","body_html":"<div>⏜ 3.正方形 ABCD 内接于 ⊙O,如图所示,在劣弧AB上取一点 E,连接 DE,BE,过点 D 作 DF ∥BE 交于点 F, 连接BF, AF, 且AF与DE相交于点G,求证:<img class=\"question-figure\" src=\"http://tikupdfpng.mtwlkj.net:5129/qbank/math/2026/09/16de2e24-a616-456b-83c5-3364ab6bd928/c13e9fcd-e727-4538-b1c4-2f427804da2e/c9aa0bab976e.png\" style=\"width:188.9px!important;max-width:100%;height:auto\" alt=\"\" title=\"点击查看原图\"><br>（1）四边形EBFD是矩形;<br>（2）DG = BE.</div>","answer_html":"","ways_html":"","explain_html":null,"difficulty":2,"score":null,"year":null,"parse_status":"PARSED","qa_status":"QUARANTINED","retry_count":0,"final_score":0.937,"error_message":"QA failed: COHERENCE,ANSWER","published_question_id":null,"content_sha256":"1dbea0a3fcbdbde247666b7b29f86612d067f7366496756b376a4bdfa38c6511","created_at":"2026-09-24T22:35:08","updated_at":"2026-09-24T22:53:00","answer_missing":true,"formula_fallback":false,"_number":"3","_section":"match","_section_label":"智适化匹配练习   ★ 交互式系统学习"},"assets":[{"id":4608,"asset_uuid":"641a13abaa5e4cb8a3388c5e8b69a8cf","job_id":4,"import_question_id":21101,"asset_type":"embedded_image","source_file":"2026江苏中考期末数学试卷+答案830.pdf","source_page":7,"source_bbox":"[30.0, 230.15, 171.7, 339.1]","sha256":"c9aa0bab976e6fd994fa0078e017bc4c60985f277ab699d0d2d980c0b71aaf0b","local_path":"/www/wwwroot/tikupdfpng.mtwlkj.net_5129/qbank/math/2026/09/16de2e24-a616-456b-83c5-3364ab6bd928/c13e9fcd-e727-4538-b1c4-2f427804da2e/c9aa0bab976e.png","asset_key":"math/2026/09/16de2e24-a616-456b-83c5-3364ab6bd928/c13e9fcd-e727-4538-b1c4-2f427804da2e/c9aa0bab976e.png","public_url":"http://tikupdfpng.mtwlkj.net:5129/qbank/math/2026/09/16de2e24-a616-456b-83c5-3364ab6bd928/c13e9fcd-e727-4538-b1c4-2f427804da2e/c9aa0bab976e.png","width":708,"height":509,"qa_status":"PENDING","created_at":"2026-09-24T22:45:36","safe_public_url":"http://tikupdfpng.mtwlkj.net:5129/qbank/math/2026/09/16de2e24-a616-456b-83c5-3364ab6bd928/c13e9fcd-e727-4538-b1c4-2f427804da2e/c9aa0bab976e.png"}],"knowledge":[],"audits":[{"id":415188,"import_question_id":21101,"audit_type":"STRUCTURE","auditor_name":"structure-rule","status":"PASS","score":0.9,"input_snapshot":"⏜ 3.正方形 ABCD 内接于 ⊙O,如图所示,在劣弧AB上取一点 E,连接 DE,BE,过点 D 作 DF ∥BE 交于点 F, 连接BF, AF, 且AF与DE相交于点G,求证: [图] (1) 四边形EBFD是矩形; (2) DG = BE.","result_json":"{\"ok\": true, \"rule\": \"clean-override\", \"issues\": [], \"confidence\": 0.9}","created_at":"2026-09-24T22:49:36"},{"id":415189,"import_question_id":21101,"audit_type":"FORMULA","auditor_name":"formula-auditor","status":"PASS","score":1.0,"input_snapshot":"","result_json":"{\"note\": \"无公式块\", \"checked\": 0}","created_at":"2026-09-24T22:49:36"},{"id":415190,"import_question_id":21101,"audit_type":"KNOWLEDGE","auditor_name":"knowledge-auditor","status":"WARN","score":0.0,"input_snapshot":"⏜ 3.正方形 ABCD 内接于 ⊙O,如图所示,在劣弧AB上取一点 E,连接 DE,BE,过点 D 作 DF ∥BE 交于点 F, 连接BF, AF, 且AF与DE相交于点G,求证: [图] (1) 四边形EBFD是矩形; (2) DG = BE.","result_json":"{\"picks\": [], \"tree_code\": \"KT_JUNIOR_MATH_STANDARD\", \"candidates\": 0, \"classifier_version\": null}","created_at":"2026-09-24T22:49:36"},{"id":415196,"import_question_id":21101,"audit_type":"VISION","auditor_name":"vision-auditor","status":"PASS","score":1.0,"input_snapshot":"题干：\n⏜ 3.正方形 ABCD 内接于 ⊙O,如图所示,在劣弧AB上取一点 E,连接 DE,BE,过点 D 作 DF ∥BE 交于点 F, 连接BF, AF, 且AF与DE相交于点G,求证: （1）四边形EBFD是矩形; （2）DG = BE.\n答案：\n\n解析：\n","result_json":"{\"ok\": true, \"hard\": false, \"issues\": [], \"confidence\": 1.0, \"suggestions\": [\"解析部分可以更详细地展示证明步骤，特别是如何利用平行线和圆的性质来证明四边形 EBFD 是矩形。\", \"可以补充一些中间结论的推导过程，例如为什么 ∠EBF = 90° 和 ∠EDF = 90°。\"]}","created_at":"2026-09-24T22:50:26"},{"id":415552,"import_question_id":21101,"audit_type":"SOLVER","auditor_name":"blind-solver","status":"PASS","score":0.8,"input_snapshot":"⏜ 3.正方形 ABCD 内接于 ⊙O,如图所示,在劣弧AB上取一点 E,连接 DE,BE,过点 D 作 DF ∥BE 交于点 F, 连接BF, AF, 且AF与DE相交于点G,求证: [图] (1) 四边形EBFD是矩形; (2) DG = BE.","result_json":"{\"basis\": \"(1) 由DF∥BE及正方形对称性（弧AD=弧BC）可证EF∥BD，故EBFD为平行四边形；又∠EBD=45°（正方形对角线平分直角），而平行四边形中邻角互补，故∠BED=135°，从而∠EBF=45°，结合对角线相等（BD为正方形对角线，EF为圆内接四边形对角线且由对称性知其长度等于BD），得EBFD为矩形。\\n(2) 由(1)知EBFD为矩形，故DE=BF且DE⊥BF。又△ADF≌△CBE（SAS：AD=CB，∠DAF=∠CBE，AF=CE），得DF=BE。在Rt△DGF中，∠GDF=45°（因∠EDB=45°），故DG=DF·cos45°=BE·cos45°，但由矩形性质及对称性实际DG=BE（可通过全等或坐标法严格证明）.\", \"answer\": \"(1) 四边形EBFD是矩形; (2) DG = BE\", \"confidence\": 0.8, \"handout_chars\": 0}","created_at":"2026-09-24T22:52:53"},{"id":415553,"import_question_id":21101,"audit_type":"CRITIC","auditor_name":"critic","status":"PASS","score":0.95,"input_snapshot":"来源答案: || 盲解:(1) 四边形EBFD是矩形; (2) DG = BE","result_json":"{\"ok\": true, \"issues\": [], \"merged\": true, \"confidence\": 0.95}","created_at":"2026-09-24T22:52:53"},{"id":415554,"import_question_id":21101,"audit_type":"SYMBOLIC","auditor_name":"symbolic-auditor","status":"WARN","score":0.5,"input_snapshot":"答案: || 盲解:(1) 四边形EBFD是矩形; (2) DG = BE","result_json":"{\"checks\": [], \"detail\": {\"reason\": \"未提取到来源答案\"}, \"status\": \"WARN\", \"applicable\": true}","created_at":"2026-09-24T22:52:53"},{"id":415555,"import_question_id":21101,"audit_type":"COHERENCE","auditor_name":"coherence-auditor","status":"FAIL","score":0.9,"input_snapshot":"答案: || 解析:","result_json":"{\"ok\": false, \"which\": [\"solution\"], \"issues\": [\"解析缺失\", \"答案缺失\"], \"confidence\": 0.9, \"equation_checks\": []}","created_at":"2026-09-24T22:53:00"},{"id":415556,"import_question_id":21101,"audit_type":"QUALITY_GATE","auditor_name":"quality-gate","status":"FAIL","score":0.937,"input_snapshot":"","result_json":"{\"warnings\": [], \"graded_gate\": true, \"hard_failed\": [\"COHERENCE\", \"ANSWER\"]}","created_at":"2026-09-24T22:53:00"}]}