{"ok":true,"question":{"id":21115,"question_uuid":"353ca967-82e8-41b3-97dc-8e54083bc5e8","job_id":3,"source_file":"人教版/七下/2026江苏七年级期末数学试卷+答案395.pdf","source_page_start":2,"source_page_end":2,"source_bbox":"[30.22, 577.09, 305.16, 598.42]","subject_code":"math","grade_level":"SENIOR","tree_code":"KT_SENIOR_MATH_STANDARD","question_type":"subjective","canonical_json":"{\"year\": null, \"blocks\": [{\"text\": \"若(2x + 1)^{2}+ |y −2| = 0，求√−3xy − 3√xy的值．\", \"type\": \"text\"}, {\"type\": \"answer\", \"blocks\": [{\"text\": \"√3 + 1\", \"type\": \"text\"}]}, {\"type\": \"solution\", \"blocks\": [{\"text\": \"由题意可知: 2x+ 1 = 0,y−2 = 0， ∴ x= −\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\frac{1}{2},y= 2\"}, {\"text\": \"所以√−3xy− 3√xy = √3 −(−1) = √3 + 1. 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AI智适化学案 学案ID:R10720395096 初一","explain_html":null,"difficulty":2,"score":null,"year":null,"parse_status":"PARSED","qa_status":"QUARANTINED","retry_count":0,"final_score":null,"error_message":"处理异常: LLM call failed after retries: HTTPConnectionPool(host='127.0.0.1', port=8091): Read timed out. (read timeout=120) [endpoints: http://127.0.0.1:8092/v1 -> http://127.0.0.1:8091/v1]","published_question_id":null,"content_sha256":"9b615cebe1e6eb538765cb0bbc847b0ea2abb5870e95180a488c5f1f3c6f5e1a","created_at":"2026-09-24T22:47:54","updated_at":"2026-09-24T23:09:47","answer_missing":false,"formula_fallback":false,"_number":"11","_section":"generic","_section_label":""},"assets":[],"knowledge":[],"audits":[{"id":415662,"import_question_id":21115,"audit_type":"STRUCTURE","auditor_name":"structure-auditor","status":"PASS","score":1.0,"input_snapshot":"若(2x + 1)^{2}+ |y −2| = 0，求√−3xy − 3√xy的值．","result_json":"{\"ok\": true, \"issues\": [], \"confidence\": 1.0}","created_at":"2026-09-24T23:04:12"},{"id":415663,"import_question_id":21115,"audit_type":"FORMULA","auditor_name":"formula-auditor","status":"PASS","score":1.0,"input_snapshot":"\\frac{1}{2},y= 2","result_json":"{\"risky\": 1, \"issues\": [], \"checked\": 1, \"invalid\": 0, \"visual_check\": \"delegated_to_question_vision\", \"invalid_details\": [], \"visually_verified\": 0}","created_at":"2026-09-24T23:04:12"},{"id":415664,"import_question_id":21115,"audit_type":"KNOWLEDGE","auditor_name":"knowledge-auditor","status":"WARN","score":0.0,"input_snapshot":"若(2x + 1)^{2}+ |y −2| = 0，求√−3xy − 3√xy的值．","result_json":"{\"picks\": [], \"tree_code\": \"KT_SENIOR_MATH_STANDARD\", \"candidates\": 0, \"classifier_version\": null}","created_at":"2026-09-24T23:04:12"},{"id":415670,"import_question_id":21115,"audit_type":"VISION","auditor_name":"vision-auditor","status":"PASS","score":0.95,"input_snapshot":"题干：\n若(2x + 1)^{2}+ |y −2| = 0，求√−3xy − 3√xy的值．\n答案：\n√3 + 1\n解析：\n由题意可知: 2x+ 1 = 0,y−2 = 0， ∴ x= −\\(\\frac{1}{2},y= 2\\)所以√−3xy− 3√xy = √3 −(−1) = √3 + 1. AI智适化学案 学案ID:R10720395096 初一","result_json":"{\"ok\": true, \"hard\": false, \"issues\": [], \"confidence\": 0.95, \"suggestions\": [\"解析中‘所以√−3xy− 3√xy = √3 −(−1) = √3 + 1’的推导步骤可更详细，例如说明√(−3×(−1))=√3，√(−1×2)=√(−2)需结合x,y符号判断实际为√(−3xy)=√3，³√(xy)=−1\"]}","created_at":"2026-09-24T23:04:51"},{"id":415685,"import_question_id":21115,"audit_type":"SOLVER","auditor_name":"blind-solver","status":"PASS","score":1.0,"input_snapshot":"若(2x + 1)^{2}+ |y −2| = 0，求√−3xy − 3√xy的值．","result_json":"{\"basis\": \"由 (2x+1)^2 ≥ 0 和 |y−2| ≥ 0 且和为0，得 2x+1=0 ⇒ x=−1/2，y−2=0 ⇒ y=2。代入：−3xy = −3*(−1/2)*2 = 3，故 √(−3xy) = √3；∛(xy) = ∛(−1) = −1，所以 −∛(xy) = 1。总和 √3 + 1。\", \"answer\": \"√3 + 1\", \"confidence\": 1.0, \"handout_chars\": 0}","created_at":"2026-09-24T23:05:46"},{"id":415686,"import_question_id":21115,"audit_type":"CRITIC","auditor_name":"critic","status":"PASS","score":1.0,"input_snapshot":"来源答案:√3 + 1 || 盲解:√3 + 1","result_json":"{\"ok\": true, \"issues\": [], \"merged\": true, \"confidence\": 1.0}","created_at":"2026-09-24T23:05:46"},{"id":415687,"import_question_id":21115,"audit_type":"SYMBOLIC","auditor_name":"symbolic-auditor","status":"PASS","score":1.0,"input_snapshot":"答案:√3 + 1 || 盲解:√3 + 1","result_json":"{\"checks\": [], \"detail\": {\"reason\": \"盲解与来源答案一致\"}, \"status\": \"PASS\", \"applicable\": true}","created_at":"2026-09-24T23:05:46"}]}