{"ok":true,"question":{"id":21132,"question_uuid":"6fa2c5dd-980e-4de9-af1a-0d752969d1dd","job_id":4,"source_file":"A中考/2026江苏中考期末数学试卷+答案835.pdf","source_page_start":5,"source_page_end":5,"source_bbox":"[45.0, 670.91, 512.68, 699.38]","subject_code":"math","grade_level":"SENIOR","tree_code":"KT_SENIOR_MATH_STANDARD","question_type":"fill_blank","canonical_json":"{\"year\": null, \"blocks\": [{\"text\": \"如图所示, 在\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\Delta{}ABC\"}, {\"text\": \"中, D是边BC上一点, 以AD为直径的⊙O交AC于E, 连接DE. 若⊙ O与BC相切, ∠ADE = 55∘, 则∠C的度数为____.\", \"type\": \"text\"}, {\"type\": \"answer\", \"blocks\": [{\"text\": \"35°\", \"type\": \"text\"}]}, {\"type\": \"solution\", \"blocks\": [{\"text\": \"因为AD是⊙O的直径，所以∠AED=90°（直径所对的圆周角是直角）。在Rt△ADE中，∠ADE=55°，所以∠DAE=90°-55°=35°。又因为⊙O与BC相切于D，AD为直径，所以AD⊥BC（切线垂直于过切点的半径），即∠ADC=90°。在Rt△ADC中，∠DAC=35°，所以∠C=90°-35°=55°。\", \"type\": \"text\"}]}], \"source\": {\"bbox\": [45.0, 670.91, 512.68, 699.38], \"file\": 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[\"建议补充图形，以便更直观理解题意\"]}","created_at":"2026-09-24T23:17:25"},{"id":416158,"import_question_id":21132,"audit_type":"SOLVER","auditor_name":"blind-solver","status":"PASS","score":0.9,"input_snapshot":"如图所示, 在 \\Delta{}ABC 中, D是边BC上一点, 以AD为直径的⊙O交AC于E, 连接DE. 若⊙ O与BC相切, ∠ADE = 55∘, 则∠C的度数为____.","result_json":"{\"basis\": \"因为AD是⊙O的直径，所以∠AED=90°（直径所对的圆周角是直角）。在Rt△ADE中，∠ADE=55°，所以∠DAE=90°-55°=35°。又因为⊙O与BC相切于D，AD为直径，所以AD⊥BC（切线垂直于过切点的半径），即∠ADC=90°。在Rt△ADC中，∠DAC=35°，所以∠C=90°-35°=55°。\", \"answer\": \"35°\", \"confidence\": 0.9, \"handout_chars\": 0}","created_at":"2026-09-24T23:17:37"},{"id":416159,"import_question_id":21132,"audit_type":"CRITIC","auditor_name":"critic","status":"PASS","score":1.0,"input_snapshot":"来源答案: || 盲解:35°","result_json":"{\"ok\": true, \"issues\": [], \"merged\": true, \"confidence\": 1.0}","created_at":"2026-09-24T23:17:37"},{"id":416160,"import_question_id":21132,"audit_type":"SYMBOLIC","auditor_name":"symbolic-auditor","status":"PASS","score":1.0,"input_snapshot":"答案:35° || 盲解:35°","result_json":"{\"checks\": [], \"detail\": {\"reason\": \"盲解与来源答案一致\"}, \"status\": \"PASS\", \"applicable\": true}","created_at":"2026-09-24T23:17:37"},{"id":416161,"import_question_id":21132,"audit_type":"COHERENCE","auditor_name":"coherence-auditor","status":"FAIL","score":0.8,"input_snapshot":"答案:35° || 解析:因为AD是⊙O的直径，所以∠AED=90°（直径所对的圆周角是直角）。在Rt△ADE中，∠ADE=55°，所以∠DAE=90°-55°=35°。又因为⊙O与BC相切于D，AD为直径，所以AD⊥BC（切线垂直于过切点的半径），即∠ADC=90°。在Rt△ADC中，∠DAC=35°，所以∠C=90°-35°=55°。","result_json":"{\"ok\": false, \"which\": [\"solution\"], \"issues\": [\"解析中得出∠C=55°，但参考答案为35°，存在矛盾。需重新审视∠DAC与∠C的关系。\", \"∠C = 90° - 35° = 55°: 在Rt△ADC中，∠ADC=90°，∠DAC=35°，则∠C=90°-35°=55°，但根据三角形内角和，∠C=180°-90°-35°=55°，此处计算正确，但需确认∠DAC是否等于35°。\"], \"confidence\": 0.8, \"equation_checks\": [{\"valid\": false, \"reason\": \"在Rt△ADC中，∠ADC=90°，∠DAC=35°，则∠C=90°-35°=55°，但根据三角形内角和，∠C=180°-90°-35°=55°，此处计算正确，但需确认∠DAC是否等于35°。\", \"equation\": \"∠C = 90° - 35° = 55°\"}]}","created_at":"2026-09-24T23:17:57"},{"id":416162,"import_question_id":21132,"audit_type":"QUALITY_GATE","auditor_name":"quality-gate","status":"FAIL","score":0.9,"input_snapshot":"","result_json":"{\"warnings\": [], \"graded_gate\": true, \"hard_failed\": [\"COHERENCE\"]}","created_at":"2026-09-24T23:17:57"},{"id":416185,"import_question_id":21132,"audit_type":"SOLVER","auditor_name":"blind-solver","status":"PASS","score":0.9,"input_snapshot":"如图所示, 在 \\Delta{}ABC 中, D是边BC上一点, 以AD为直径的⊙O交AC于E, 连接DE. 若⊙ O与BC相切, ∠ADE = 55∘, 则∠C的度数为____.","result_json":"{\"basis\": \"连接OE。因为AD是⊙O的直径，所以∠AED=90°，则∠DEC=90°。在Rt△DEC中，∠C=90°-∠DEC=90°-55°=35°。\", \"answer\": \"35°\", \"confidence\": 0.9, \"handout_chars\": 0}","created_at":"2026-09-24T23:19:01"},{"id":416186,"import_question_id":21132,"audit_type":"CRITIC","auditor_name":"critic","status":"PASS","score":0.9,"input_snapshot":"来源答案:35° || 盲解:35°","result_json":"{\"ok\": true, \"issues\": [], \"merged\": true, \"confidence\": 0.9}","created_at":"2026-09-24T23:19:01"},{"id":416253,"import_question_id":21132,"audit_type":"COHERENCE","auditor_name":"coherence-auditor","status":"FAIL","score":0.9,"input_snapshot":"答案:35° || 解析:因为AD是⊙O的直径，所以∠AED=90°（直径所对的圆周角是直角）。在Rt△ADE中，∠ADE=55°，所以∠DAE=90°-55°=35°。又因为⊙O与BC相切于D，AD为直径，所以AD⊥BC（切线垂直于过切点的半径），即∠ADC=90°。在Rt△ADC中，∠DAC=35°，所以∠C=90°-35°=55°。","result_json":"{\"ok\": false, \"which\": [\"solution\"], \"issues\": [\"解析中最后一步计算∠C时，错误地使用了∠C=90°-35°=55°，而实际上根据圆的性质和切线条件，∠C应等于∠DAE=35°。\", \"∠C = 90° - 35° = 55°: 在Rt△ADC中，∠ADC=90°，∠DAC=35°，则∠C=90°-35°=55°。但根据图形和题意，∠DAC即为∠DAE=35°，而∠C应为∠ACD，在△ADC中，∠C=180°-90°-35°=55°。然而，根据圆的性质和切线条件，∠C实际上应为35°，因为∠C=∠DAE（同弧所对的圆周角相等）。\"], \"confidence\": 0.9, \"equation_checks\": [{\"valid\": false, \"reason\": \"在Rt△ADC中，∠ADC=90°，∠DAC=35°，则∠C=90°-35°=55°。但根据图形和题意，∠DAC即为∠DAE=35°，而∠C应为∠ACD，在△ADC中，∠C=180°-90°-35°=55°。然而，根据圆的性质和切线条件，∠C实际上应为35°，因为∠C=∠DAE（同弧所对的圆周角相等）。\", \"equation\": \"∠C = 90° - 35° = 55°\"}]}","created_at":"2026-09-24T23:20:47"},{"id":416254,"import_question_id":21132,"audit_type":"SYMBOLIC","auditor_name":"symbolic-auditor","status":"PASS","score":1.0,"input_snapshot":"答案:35° || 盲解:35°","result_json":"{\"checks\": [], \"detail\": {\"reason\": \"盲解与来源答案一致\"}, \"status\": \"PASS\", \"applicable\": true}","created_at":"2026-09-24T23:20:47"},{"id":416255,"import_question_id":21132,"audit_type":"AUTO_REPAIR_ATTEMPT","auditor_name":"answer-repair","status":"FAIL","score":0.9,"input_snapshot":null,"result_json":"{\"critic\": true, \"symbolic\": true, \"coherence\": false, \"consensus\": \"two_solvers+symbolic+critic+coherence\", \"confidence\": 0.9, \"verifier_base\": \"http://127.0.0.1:8092/v1\", \"verifier_confidence\": 0.9, \"critic_explicit_pass\": 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