{"ok":true,"question":{"id":21203,"question_uuid":"50aaecbd-ca9b-4190-90e8-0dddf1f95c1b","job_id":4,"source_file":"A中考/2026江苏中考期末数学试卷+答案85.pdf","source_page_start":2,"source_page_end":2,"source_bbox":"[30.0, 553.82, 198.72, 586.88]","subject_code":"math","grade_level":"JUNIOR","tree_code":"KT_JUNIOR_MATH_STANDARD","question_type":"fill_blank","canonical_json":"{\"year\": null, \"blocks\": [{\"text\": \"1 1  _______________. x  2\", \"type\": \"text\"}, {\"type\": \"answer\", \"blocks\": [{\"text\": \"-\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\frac{2-x}{x-2}\"}]}, {\"type\": \"solution\", \"blocks\": [{\"text\": \"将 -1 写成\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\frac{-(x-2)}{x-2}\"}, {\"text\": \"，与\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\frac{1}{x-2}\"}, {\"text\": \"合并得\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\frac{1-(x-2)}{x-2}=\\\\frac{3-x}{x-2}\"}, {\"text\": \"，再化为 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\\\\frac{-(x-3)}{x-2}，而 -\\\\frac{2-x}{x-2} = \\\\frac{x-2}{x-2} = 1，所以两者不相等。\"], \"confidence\": 0.9, \"equation_checks\": [{\"valid\": false, \"reason\": \"左边是常数 -1，右边是 \\\\frac{2-x}{x-2}，当 x ≠ 2 时，\\\\frac{2-x}{x-2} = -1，但解析中写的是 \\\\frac{-(x-2)}{x-2} = -1，这是正确的。然而，在合并时，解析写的是 \\\\frac{1}{x-2} + \\\\frac{-(x-2)}{x-2} = \\\\frac{1 - (x-2)}{x-2} = \\\\frac{3 - x}{x-2}，这一步是正确的。但最后化简为 -\\\\frac{2-x}{x-2}，这是错误的，因为 \\\\frac{3-x}{x-2} 不能化简为 -\\\\frac{2-x}{x-2}。实际上，\\\\frac{3-x}{x-2} = \\\\frac{-(x-3)}{x-2}，而 -\\\\frac{2-x}{x-2} = \\\\frac{x-2}{x-2} = 1，所以两者不相等。\", \"equation\": \"-1 = \\\\frac{-(x-2)}{x-2}\"}]}","created_at":"2026-09-24T23:43:33"},{"id":417723,"import_question_id":21203,"audit_type":"QUALITY_GATE","auditor_name":"quality-gate","status":"FAIL","score":0.937,"input_snapshot":"","result_json":"{\"warnings\": [], \"graded_gate\": true, \"hard_failed\": 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