{"ok":true,"question":{"id":21229,"question_uuid":"19306fb6-a4d9-4180-a338-5c19799ca08c","job_id":4,"source_file":"A中考/2026江苏中考期末数学试卷+答案85.pdf","source_page_start":5,"source_page_end":7,"source_bbox":"[30.0, 451.54, 565.3, 51.16]","subject_code":"math","grade_level":"JUNIOR","tree_code":"KT_JUNIOR_MATH_STANDARD","question_type":"subjective","canonical_json":"{\"year\": null, \"blocks\": [{\"text\": \"化简: _{a+1}− _{a2}_{−1}÷ _{a2}_{−2a+1}. 2 a−2 a2−2a AI智适化学案 学案编号:A10910085058\", \"type\": \"text\"}], \"source\": {\"bbox\": [30.0, 451.54, 565.3, 51.16], \"file\": \"A中考/2026江苏中考期末数学试卷+答案85.pdf\", \"regions\": [{\"bbox\": [30.0, 451.54, 173.46, 524.49], \"page\": 5}, {\"bbox\": [245.88, 21.64, 565.3, 51.16], \"page\": 7}], \"section\": \"match\", \"page_end\": 7, \"page_start\": 5, \"section_label\": \"智适化匹配练习 ★ 交互式系统学习\", \"answer_regions\": [], \"answer_original\": \"\", \"solution_original\": \"\"}, \"version\": 1, \"grade_level\": \"JUNIOR\", \"number_label\": \"6\", \"subject_code\": \"math\", \"question_type\": \"subjective\", \"content_sha256\": \"09313c50b08fa803b986098911d693677e5e1fd78bc5ccb50465260a01d9cb97\"}","body_html":"<div>化简: _{a+1}− _{a2}_{−1}÷ _{a2}_{−2a+1}. 2 a−2 a2−2a AI智适化学案 学案编号:A10910085058</div>","answer_html":"","ways_html":"","explain_html":null,"difficulty":2,"score":null,"year":null,"parse_status":"PARSED","qa_status":"QUARANTINED","retry_count":0,"final_score":0.95,"error_message":"QA failed: COHERENCE,ANSWER","published_question_id":null,"content_sha256":"09313c50b08fa803b986098911d693677e5e1fd78bc5ccb50465260a01d9cb97","created_at":"2026-09-24T23:22:50","updated_at":"2026-09-25T00:16:18","answer_missing":true,"formula_fallback":false,"_number":"6","_section":"match","_section_label":"智适化匹配练习 ★ 交互式系统学习"},"assets":[],"knowledge":[],"audits":[{"id":418742,"import_question_id":21229,"audit_type":"STRUCTURE","auditor_name":"structure-auditor","status":"PASS","score":0.95,"input_snapshot":"化简: _{a+1}− _{a2}_{−1}÷ _{a2}_{−2a+1}. 2 a−2 a2−2a AI智适化学案 学案编号:A10910085058","result_json":"{\"ok\": true, \"issues\": [], \"confidence\": 0.95}","created_at":"2026-09-25T00:01:22"},{"id":418743,"import_question_id":21229,"audit_type":"FORMULA","auditor_name":"formula-auditor","status":"PASS","score":1.0,"input_snapshot":"","result_json":"{\"note\": \"无公式块\", \"checked\": 0}","created_at":"2026-09-25T00:01:22"},{"id":418744,"import_question_id":21229,"audit_type":"KNOWLEDGE","auditor_name":"knowledge-auditor","status":"WARN","score":0.0,"input_snapshot":"化简: _{a+1}− _{a2}_{−1}÷ _{a2}_{−2a+1}. 2 a−2 a2−2a AI智适化学案 学案编号:A10910085058","result_json":"{\"picks\": [], \"tree_code\": \"KT_JUNIOR_MATH_STANDARD\", \"candidates\": 0, \"classifier_version\": null}","created_at":"2026-09-25T00:01:22"},{"id":418749,"import_question_id":21229,"audit_type":"VISION","auditor_name":"vision-auditor","status":"PASS","score":0.95,"input_snapshot":"题干：\n化简: _{a+1}− _{a2}_{−1}÷ _{a2}_{−2a+1}. 2 a−2 a2−2a AI智适化学案 学案编号:A10910085058\n答案：\n\n解析：\n","result_json":"{\"ok\": true, \"hard\": false, \"issues\": [], \"confidence\": 0.95, \"suggestions\": [\"题干中的表达式排版较为紧凑，建议在‘−’和‘÷’符号前后增加适当空格以提升可读性（不影响数学含义）\"]}","created_at":"2026-09-25T00:01:48"},{"id":419186,"import_question_id":21229,"audit_type":"SOLVER","auditor_name":"blind-solver","status":"PASS","score":1.0,"input_snapshot":"化简: _{a+1}− _{a2}_{−1}÷ _{a2}_{−2a+1}. 2 a−2 a2−2a AI智适化学案 学案编号:A10910085058","result_json":"{\"basis\": \"原式 = \\\\frac{2}{a+1} - \\\\frac{a-2}{(a+1)(a-1)} \\\\cdot \\\\frac{(a-1)^2}{a(a-2)} = \\\\frac{2}{a+1} - \\\\frac{a-1}{a(a+1)} = \\\\frac{2a - (a-1)}{a(a+1)} = \\\\frac{a+1}{a(a+1)} = \\\\frac{1}{a}\", \"answer\": \"\\\\frac{1}{a}\", \"confidence\": 1.0, \"handout_chars\": 0}","created_at":"2026-09-25T00:06:35"},{"id":419187,"import_question_id":21229,"audit_type":"CRITIC","auditor_name":"critic","status":"PASS","score":1.0,"input_snapshot":"来源答案: || 盲解:\\frac{1}{a}","result_json":"{\"ok\": true, \"issues\": [], \"merged\": true, \"confidence\": 1.0}","created_at":"2026-09-25T00:06:35"},{"id":419188,"import_question_id":21229,"audit_type":"SYMBOLIC","auditor_name":"symbolic-auditor","status":"WARN","score":0.5,"input_snapshot":"答案: || 盲解:\\frac{1}{a}","result_json":"{\"checks\": [], \"detail\": {\"reason\": \"未提取到来源答案\"}, \"status\": \"WARN\", \"applicable\": true}","created_at":"2026-09-25T00:06:35"},{"id":419218,"import_question_id":21229,"audit_type":"COHERENCE","auditor_name":"coherence-auditor","status":"FAIL","score":0.9,"input_snapshot":"答案: || 解析:","result_json":"{\"ok\": false, \"which\": [\"answer\", \"solution\"], \"issues\": [\"答案缺失\", \"解析缺失\"], \"confidence\": 0.9, \"equation_checks\": []}","created_at":"2026-09-25T00:06:58"},{"id":419219,"import_question_id":21229,"audit_type":"QUALITY_GATE","auditor_name":"quality-gate","status":"FAIL","score":0.95,"input_snapshot":"","result_json":"{\"warnings\": [], \"graded_gate\": true, \"hard_failed\": [\"COHERENCE\", \"ANSWER\"]}","created_at":"2026-09-25T00:06:58"},{"id":419519,"import_question_id":21229,"audit_type":"SOLVER","auditor_name":"blind-solver","status":"PASS","score":1.0,"input_snapshot":"化简: _{a+1}− _{a2}_{−1}÷ _{a2}_{−2a+1}. 2 a−2 a2−2a AI智适化学案 学案编号:A10910085058","result_json":"{\"basis\": \"先计算除法部分：(a-2)/(a^2-1) ÷ (a^2-2a)/(a^2-2a+1) = (a-2)/[(a+1)(a-1)] × (a-1)^2/[a(a-2)] = (a-1)/[a(a+1)]；再计算减法：2/(a+1) - (a-1)/[a(a+1)] = [2a - (a-1)]/[a(a+1)] = (a+1)/[a(a+1)] = 1/a\", \"answer\": \"1/a\", \"confidence\": 1.0, \"handout_chars\": 0}","created_at":"2026-09-25T00:12:28"},{"id":419520,"import_question_id":21229,"audit_type":"CRITIC","auditor_name":"critic","status":"PASS","score":1.0,"input_snapshot":"来源答案:\\(\\frac{1}{a}\\) || 盲解:1/a","result_json":"{\"ok\": true, \"issues\": [], \"merged\": true, \"confidence\": 1.0}","created_at":"2026-09-25T00:12:28"},{"id":419593,"import_question_id":21229,"audit_type":"COHERENCE","auditor_name":"coherence-auditor","status":"FAIL","score":0.9,"input_snapshot":"答案:\\(\\frac{1}{a}\\) || 解析:原式 =\\(\\frac{1}{a+1} - \\frac{a^{2}}{-1} \\div \\frac{a^{2}}{-2a+1}\\)=\\(\\frac{1}{a+1} + a^{2} \\cdot \\frac{-2a+1}{a^{2}}\\)=\\(\\frac{1}{a+1} + (-2a+1)\\)=\\(\\frac{1}{a+1} - 2a + 1\\)=\\(\\frac{1 - (2a - 1)(a+1)}{","result_json":"{\"ok\": false, \"which\": [\"solution\"], \"issues\": [\"解析中从 \\\\frac{1}{a+1} + (-2a+1) 到 \\\\frac{1}{a+1} - 2a + 1 的符号变换无依据；\", \"后续通分步骤错误，导致最终结果 2-2a 与参考答案 1/a 不符。\", \"\\\\frac{1}{a+1} + (-2a+1) = \\\\frac{1}{a+1} - 2a + 1: 等式左边是加法，右边变成了减法，符号改变无依据。正确应为 \\\\frac{1}{a+1} - 2a + 1 或保持原样，不能随意变号。\", \"\\\\frac{1}{a+1} - 2a + 1 = \\\\frac{1 - (2a - 1)(a+1)}{a+1}: 通分错误。\\\\frac{1}{a+1} - 2a + 1 应化为 \\\\frac{1 + (-2a+1)(a+1)}{a+1}，而非减去 (2a-1)(a+1)。\", \"\\\\frac{1 - (2a^2 - 1)}{a+1} = \\\\frac{2 - 2a^2}{a+1}: 分子化简错误。1 - (2a^2 - 1) = 2 - 2a^2 正确，但前一步通分已错，导致整体推导链断裂。\", \"\\\\frac{2(1 - a^2)}{a+1} = 2(1 - a): 约分错误。\\\\frac{2(1-a^2)}{a+1} = \\\\frac{2(1-a)(1+a)}{a+1} = 2(1-a) 仅在 a≠-1 时成立，但前步通分错误已使结果不可靠。\"], \"confidence\": 0.9, \"equation_checks\": [{\"valid\": false, \"reason\": \"等式左边是加法，右边变成了减法，符号改变无依据。正确应为 \\\\frac{1}{a+1} - 2a + 1 或保持原样，不能随意变号。\", \"equation\": \"\\\\frac{1}{a+1} + (-2a+1) = \\\\frac{1}{a+1} - 2a + 1\"}, {\"valid\": false, \"reason\": \"通分错误。\\\\frac{1}{a+1} - 2a + 1 应化为 \\\\frac{1 + (-2a+1)(a+1)}{a+1}，而非减去 (2a-1)(a+1)。\", \"equation\": \"\\\\frac{1}{a+1} - 2a + 1 = \\\\frac{1 - (2a - 1)(a+1)}{a+1}\"}, {\"valid\": false, \"reason\": \"分子化简错误。1 - (2a^2 - 1) = 2 - 2a^2 正确，但前一步通分已错，导致整体推导链断裂。\", \"equation\": \"\\\\frac{1 - (2a^2 - 1)}{a+1} = \\\\frac{2 - 2a^2}{a+1}\"}, {\"valid\": false, \"reason\": \"约分错误。\\\\frac{2(1-a^2)}{a+1} = \\\\frac{2(1-a)(1+a)}{a+1} = 2(1-a) 仅在 a≠-1 时成立，但前步通分错误已使结果不可靠。\", \"equation\": \"\\\\frac{2(1 - a^2)}{a+1} = 2(1 - a)\"}]}","created_at":"2026-09-25T00:16:18"},{"id":419594,"import_question_id":21229,"audit_type":"SYMBOLIC","auditor_name":"symbolic-auditor","status":"WARN","score":0.55,"input_snapshot":"答案:\\(\\frac{1}{a}\\) || 盲解:1/a","result_json":"{\"checks\": [], \"detail\": {\"reason\": \"盲解与来源答案存在字面差异，需 Critic 复核\"}, \"status\": \"WARN\", \"applicable\": true}","created_at":"2026-09-25T00:16:18"},{"id":419595,"import_question_id":21229,"audit_type":"AUTO_REPAIR_ATTEMPT","auditor_name":"answer-repair","status":"FAIL","score":1.0,"input_snapshot":null,"result_json":"{\"critic\": true, \"symbolic\": true, \"coherence\": false, \"consensus\": \"two_solvers+symbolic+critic+coherence\", \"confidence\": 1.0, \"verifier_base\": \"http://127.0.0.1:8091/v1\", \"verifier_confidence\": 1.0, \"critic_explicit_pass\": true, \"symbolic_literal_warn\": false, \"symbolic_explicit_pass\": false, \"coherence_explicit_pass\": false}","created_at":"2026-09-25T00:16:18"}]}