{"ok":true,"question":{"id":21293,"question_uuid":"fa444d2d-5023-48d5-a8f6-629de7cf6875","job_id":3,"source_file":"人教版/七下/2026江苏七年级期末数学试卷+答案405.pdf","source_page_start":2,"source_page_end":2,"source_bbox":"[31.56, 751.07, 289.85, 780.74]","subject_code":"math","grade_level":"JUNIOR","tree_code":"KT_JUNIOR_MATH_STANDARD","question_type":"fill_blank","canonical_json":"{\"year\": null, \"blocks\": [{\"text\": \"【小试2】 请写出一个大于−1且小于1的无理数: ______.\", \"type\": \"text\"}, {\"type\": \"answer\", \"blocks\": [{\"text\": \"−\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\sqrt{2_{2}}\"}, {\"text\": \"(答案不唯一)\", \"type\": \"text\"}]}, {\"type\": \"solution\", \"blocks\": [{\"text\": \"设这个无理数为\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"x\"}, {\"text\": \", 即$-1 < x < 1$,\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"-\\\\frac{\\\\sqrt{2}}{2}\"}, {\"text\": \",\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"-\\\\frac{\\\\pi}{4}\"}, {\"text\": \",\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"-\\\\frac{\\\\sqrt{3}}{2}\"}, {\"text\": \"等均可, 故答案为：\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"-\\\\frac{\\\\sqrt{2}}{2}\"}, {\"text\": \".\", \"type\": \"text\"}]}], \"source\": {\"bbox\": [31.56, 751.07, 289.85, 780.74], \"file\": \"人教版/七下/2026江苏七年级期末数学试卷+答案405.pdf\", \"regions\": [{\"bbox\": [31.56, 751.07, 289.85, 780.74], \"page\": 2}], \"section\": \"quiz\", \"page_end\": 2, \"page_start\": 2, \"section_label\": \"小试牛刀   ★ 独立完成，见证实力！\", \"answer_regions\": [{\"bbox\": [30.0, 288.61, 414.79, 342.19], \"page\": 5}], \"answer_original\": \"−√2_{2}(答案不唯一)\", \"solution_original\": \"设这个无理数为x, 即−1 < x < 1, −√2 π _{2}, − _{4}, −√3_{2}等均可, 故答案为：−√2_{2}.\"}, \"version\": 1, \"grade_level\": \"JUNIOR\", \"number_label\": \"2\", \"subject_code\": \"math\", \"question_type\": \"fill_blank\", \"content_sha256\": \"b8231d6bbac9f73c8dcc423b14ab188a8f29d36d1a26e6c6322822f0c3b547e6\"}","body_html":"<div>【小试2】 请写出一个大于−1且小于1的无理数: ______.</div>","answer_html":"−\\(\\sqrt{2_{2}}\\)(答案不唯一)","ways_html":"设这个无理数为\\(x\\), 即$-1 &lt; x &lt; 1<span class=\"formula-fallback\">,\\(-fracsqrt22\\),\\(-fracπ4\\),\\(-fracsqrt32\\)等均可, 故答案为：\\(-fracsqrt22\\).</span>","explain_html":null,"difficulty":2,"score":null,"year":null,"parse_status":"PARSED","qa_status":"QUARANTINED","retry_count":0,"final_score":0.75,"error_message":"QA failed: VISION","published_question_id":null,"content_sha256":"b8231d6bbac9f73c8dcc423b14ab188a8f29d36d1a26e6c6322822f0c3b547e6","created_at":"2026-09-25T00:05:12","updated_at":"2026-09-25T00:12:46","answer_missing":false,"formula_fallback":true,"_number":"2","_section":"quiz","_section_label":"小试牛刀   ★ 独立完成，见证实力！"},"assets":[],"knowledge":[],"audits":[{"id":419503,"import_question_id":21293,"audit_type":"STRUCTURE","auditor_name":"structure-rule","status":"PASS","score":0.9,"input_snapshot":"【小试2】 请写出一个大于−1且小于1的无理数: ______.","result_json":"{\"ok\": true, \"rule\": \"clean-override\", \"issues\": [], \"confidence\": 0.9}","created_at":"2026-09-25T00:12:01"},{"id":419504,"import_question_id":21293,"audit_type":"FORMULA","auditor_name":"formula-auditor","status":"PASS","score":1.0,"input_snapshot":"\\sqrt{2_{2}}; x; -\\frac{\\sqrt{2}}{2}; -\\frac{\\pi}{4}; -\\frac{\\sqrt{3}}{2}","result_json":"{\"risky\": 5, \"issues\": [], \"checked\": 6, \"invalid\": 0, \"visual_check\": \"delegated_to_question_vision\", \"invalid_details\": [], \"visually_verified\": 0}","created_at":"2026-09-25T00:12:01"},{"id":419505,"import_question_id":21293,"audit_type":"KNOWLEDGE","auditor_name":"knowledge-auditor","status":"WARN","score":0.0,"input_snapshot":"【小试2】 请写出一个大于−1且小于1的无理数: ______.","result_json":"{\"picks\": [], \"tree_code\": \"KT_JUNIOR_MATH_STANDARD\", \"candidates\": 0, \"classifier_version\": null}","created_at":"2026-09-25T00:12:01"},{"id":419515,"import_question_id":21293,"audit_type":"SOLVER","auditor_name":"blind-solver","status":"PASS","score":1.0,"input_snapshot":"【小试2】 请写出一个大于−1且小于1的无理数: ______.","result_json":"{\"basis\": \"无理数是无限不循环小数。−√2/2 ≈ −0.707，满足大于−1且小于1，且为无理数。\", \"answer\": \"−√2/2\", \"confidence\": 1.0, \"handout_chars\": 0}","created_at":"2026-09-25T00:12:22"},{"id":419516,"import_question_id":21293,"audit_type":"CRITIC","auditor_name":"critic","status":"PASS","score":1.0,"input_snapshot":"来源答案:−\\(\\sqrt{2_{2}}\\)(答案不唯一) || 盲解:−√2/2","result_json":"{\"ok\": true, \"issues\": [], \"merged\": true, \"confidence\": 1.0}","created_at":"2026-09-25T00:12:22"},{"id":419523,"import_question_id":21293,"audit_type":"VISION","auditor_name":"vision-auditor","status":"WARN","score":0.2,"input_snapshot":"题干：\n【小试2】 请写出一个大于−1且小于1的无理数: ______.\n答案：\n−\\(\\sqrt{2_{2}}\\)(答案不唯一)\n解析：\n设这个无理数为\\(x\\), 即$-1 &lt; x &lt; 1$,\\(-\\frac{\\sqrt{2}}{2}\\),\\(-\\frac{\\pi}{4}\\),\\(-\\frac{\\sqrt{3}}{2}\\)等均可, 故答案为：\\(-\\frac{\\sqrt{2}}{2}\\).","result_json":"{\"note\": \"视觉比对不可用\", \"error\": \"invalid_json_root\", \"unavailable\": true}","created_at":"2026-09-25T00:12:31"},{"id":419524,"import_question_id":21293,"audit_type":"SYMBOLIC","auditor_name":"symbolic-auditor","status":"WARN","score":0.55,"input_snapshot":"答案:−\\(\\sqrt{2_{2}}\\)(答案不唯一) || 盲解:−√2/2","result_json":"{\"checks\": [], \"detail\": {\"reason\": \"盲解与来源答案存在字面差异，需 Critic 复核\"}, \"status\": \"WARN\", \"applicable\": true}","created_at":"2026-09-25T00:12:31"},{"id":419535,"import_question_id":21293,"audit_type":"COHERENCE","auditor_name":"coherence-auditor","status":"PASS","score":0.9,"input_snapshot":"答案:−\\(\\sqrt{2_{2}}\\)(答案不唯一) || 解析:设这个无理数为\\(x\\), 即$-1 &lt; x &lt; 1$,\\(-\\frac{\\sqrt{2}}{2}\\),\\(-\\frac{\\pi}{4}\\),\\(-\\frac{\\sqrt{3}}{2}\\)等均可, 故答案为：\\(-\\frac{\\sqrt{2}}{2}\\).","result_json":"{\"ok\": true, \"which\": [], \"issues\": [], \"confidence\": 0.9, \"equation_checks\": []}","created_at":"2026-09-25T00:12:46"},{"id":419538,"import_question_id":21293,"audit_type":"QUALITY_GATE","auditor_name":"quality-gate","status":"FAIL","score":0.75,"input_snapshot":"","result_json":"{\"warnings\": [], \"graded_gate\": true, \"hard_failed\": [\"VISION\"]}","created_at":"2026-09-25T00:12:46"}]}