{"ok":true,"question":{"id":21389,"question_uuid":"b567105c-ea0a-4180-925c-d30324c34658","job_id":3,"source_file":"人教版/七下/2026江苏七年级期末数学试卷+答案415.pdf","source_page_start":2,"source_page_end":2,"source_bbox":"[30.22, 553.94, 306.92, 596.51]","subject_code":"math","grade_level":"JUNIOR","tree_code":"KT_JUNIOR_MATH_STANDARD","question_type":"subjective","canonical_json":"{\"year\": null, \"blocks\": [{\"text\": \"已知\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"3x-5\"}, {\"text\": \"的算术平方根是\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"5，1-2y\"}, {\"text\": \"的立方根是\\\\)-3\\\\).\\n(1) 求\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"x\"}, {\"text\": \"，\\\\(y的值；\\n(2) 求\\\\(\\\\sqrt{x+2y-2}的平方根．\", \"type\": \"text\"}, {\"type\": \"answer\", \"blocks\": [{\"text\": \"x = 10, y = 14;\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\pm\\\\sqrt{6}\"}]}, {\"type\": \"solution\", \"blocks\": [{\"text\": \"(1)由题意可得，3x −5 =\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"5^{2}\"}, {\"text\": \",  1 −2y = (−3)^{3}，即3x −5 = 25,  1 −2y = −27，解 得x = 10,  y = 14，故x, y的值为x = 10, y = 14． (2)将x,y的值代入√x+ 2y−2，得x+ 2y−2 = 10 +\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"2 \\\\times 14\"}, {\"text\": \"−2 = 36,所以 √x + 2y −2 = √36 = 6, ∴√x + 2y −2 的平方根为  ± √6.\", \"type\": \"text\"}]}], \"source\": {\"bbox\": [30.22, 553.94, 306.92, 596.51], \"file\": \"人教版/七下/2026江苏七年级期末数学试卷+答案415.pdf\", \"regions\": [{\"bbox\": [30.22, 553.94, 306.92, 596.51], \"page\": 2}], \"section\": \"generic\", \"page_end\": 2, \"page_start\": 2, \"section_label\": \"\", \"answer_regions\": [{\"bbox\": [43.99800109863281, 743.4700927734375, 453.16119384765625, 785.2152709960938], \"page\": 4}, {\"bbox\": [43.99800109863281, 103.70601654052734, 424.3827209472656, 133.60198974609375], \"page\": 5}]}, \"version\": 1, \"grade_level\": \"JUNIOR\", \"number_label\": \"14\", \"subject_code\": \"math\", \"question_type\": \"subjective\", \"content_sha256\": \"0d0629b01a2ee26e8282610b06e9105e6c715ee3ae19bd01f9960c0f50542875\"}","body_html":"<div>已知\\(3x-5\\)的算术平方根是\\(5，1-2y\\)的立方根是-3.\n(1) 求\\(x，y的值；\n(2) 求\\sqrt{x+2y-2}的平方根．</div>","answer_html":"x = 10, y = 14;\\(\\pm\\sqrt{6}\\)","ways_html":"(1)由题意可得，3x −5 =\\(5^{2}\\),  1 −2y = (−3)^{3}，即3x −5 = 25,  1 −2y = −27，解 得x = 10,  y = 14，故x, y的值为x = 10, y = 14． (2)将x,y的值代入√x+ 2y−2，得x+ 2y−2 = 10 +\\(2 \\times 14\\)−2 = 36,所以 √x + 2y −2 = √36 = 6, ∴√x + 2y −2 的平方根为  ± √6.","explain_html":null,"difficulty":2,"score":null,"year":null,"parse_status":"PARSED","qa_status":"QUARANTINED","retry_count":0,"final_score":null,"error_message":"处理异常: LLM call failed after retries: HTTPConnectionPool(host='127.0.0.1', port=8091): Read timed out. (read timeout=120) [endpoints: http://127.0.0.1:8092/v1 -> http://127.0.0.1:8091/v1]","published_question_id":null,"content_sha256":"0d0629b01a2ee26e8282610b06e9105e6c715ee3ae19bd01f9960c0f50542875","created_at":"2026-09-25T00:43:18","updated_at":"2026-09-25T00:59:46","answer_missing":false,"formula_fallback":false,"_number":"14","_section":"generic","_section_label":""},"assets":[],"knowledge":[],"audits":[{"id":421810,"import_question_id":21389,"audit_type":"STRUCTURE","auditor_name":"structure-auditor","status":"PASS","score":0.95,"input_snapshot":"已知 3x-5 的算术平方根是 5，1-2y 的立方根是\\)-3\\). (1) 求 x ，\\(y的值； (2) 求\\(\\sqrt{x+2y-2}的平方根．","result_json":"{\"ok\": true, \"issues\": [], \"confidence\": 0.95}","created_at":"2026-09-25T00:54:50"},{"id":421811,"import_question_id":21389,"audit_type":"FORMULA","auditor_name":"formula-auditor","status":"PASS","score":1.0,"input_snapshot":"3x-5; 5，1-2y; x; \\pm\\sqrt{6}; 5^{2}","result_json":"{\"risky\": 3, \"issues\": [], \"checked\": 6, \"invalid\": 0, \"visual_check\": \"delegated_to_question_vision\", \"invalid_details\": [], \"visually_verified\": 0}","created_at":"2026-09-25T00:54:50"},{"id":421812,"import_question_id":21389,"audit_type":"KNOWLEDGE","auditor_name":"knowledge-auditor","status":"WARN","score":0.0,"input_snapshot":"已知 3x-5 的算术平方根是 5，1-2y 的立方根是\\)-3\\). (1) 求 x ，\\(y的值； (2) 求\\(\\sqrt{x+2y-2}的平方根．","result_json":"{\"picks\": [], \"tree_code\": \"KT_JUNIOR_MATH_STANDARD\", \"candidates\": 0, \"classifier_version\": null}","created_at":"2026-09-25T00:54:50"},{"id":421825,"import_question_id":21389,"audit_type":"VISION","auditor_name":"vision-auditor","status":"PASS","score":0.95,"input_snapshot":"题干：\n已知\\(3x-5\\)的算术平方根是\\(5，1-2y\\)的立方根是\\)-3\\). (1) 求\\(x\\)，\\(y的值； (2) 求\\(\\sqrt{x+2y-2}的平方根．\n答案：\nx = 10, y = 14;\\(\\pm\\sqrt{6}\\)\n解析：\n(1)由题意可得，3x −5 =\\(5^{2}\\), 1 −2y = (−3)^{3}，即3x −5 = 25, 1 −2y = −27，解 得x = 10, y = 14，故x, y的值为x = 10, y = 14． (2)将x,y的值代入√x+ 2y−2，得x+ 2y−2 = 10 +\\(2 \\times 14\\)−2 = 36,所以 √x + 2y −2 = √36 = 6, ∴√x + 2y −2 的平方根为 ± √6.","result_json":"{\"ok\": true, \"hard\": false, \"issues\": [], \"confidence\": 0.95, \"suggestions\": [\"题干中‘求x，y的值’可明确为‘求x，y的值’以增强可读性\"]}","created_at":"2026-09-25T00:55:24"},{"id":421828,"import_question_id":21389,"audit_type":"SOLVER","auditor_name":"blind-solver","status":"PASS","score":1.0,"input_snapshot":"已知 3x-5 的算术平方根是 5，1-2y 的立方根是\\)-3\\). (1) 求 x ，\\(y的值； (2) 求\\(\\sqrt{x+2y-2}的平方根．","result_json":"{\"basis\": \"由题意，3x-5的算术平方根是5，则3x-5=25，解得x=10；1-2y的立方根是-3，则1-2y=(-3)^3=-27，解得y=14。将x=10,y=14代入√(x+2y-2)得√(10+28-2)=√36=6，6的平方根是±√6。\", \"answer\": \"x=10, y=14; ±√6\", \"confidence\": 1.0, \"handout_chars\": 0}","created_at":"2026-09-25T00:55:46"},{"id":421829,"import_question_id":21389,"audit_type":"CRITIC","auditor_name":"critic","status":"PASS","score":1.0,"input_snapshot":"来源答案:x = 10, y = 14;\\(\\pm\\sqrt{6}\\) || 盲解:x=10, y=14; ±√6","result_json":"{\"ok\": true, \"issues\": [], \"merged\": true, \"confidence\": 1.0}","created_at":"2026-09-25T00:55:46"},{"id":421830,"import_question_id":21389,"audit_type":"SYMBOLIC","auditor_name":"symbolic-auditor","status":"WARN","score":0.55,"input_snapshot":"答案:x = 10, y = 14;\\(\\pm\\sqrt{6}\\) || 盲解:x=10, y=14; ±√6","result_json":"{\"checks\": [], \"detail\": {\"reason\": \"盲解与来源答案存在字面差异，需 Critic 复核\"}, \"status\": \"WARN\", \"applicable\": true}","created_at":"2026-09-25T00:55:46"}]}