{"ok":true,"question":{"id":21691,"question_uuid":"65ea7ba8-ee3c-495b-a74e-ed45ac45c07d","job_id":3,"source_file":"人教版/七下/2026江苏七年级期末数学试卷+答案5.pdf","source_page_start":6,"source_page_end":6,"source_bbox":"[30.0, 141.94, 534.94, 155.68]","subject_code":"math","grade_level":"JUNIOR","tree_code":"KT_JUNIOR_MATH_STANDARD","question_type":"fill_blank","canonical_json":"{\"year\": null, \"blocks\": [{\"text\": \"如图，直线AB、CD相交于点O,\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\angle AOC = 2x - 10^{\\\\circ}\"}, {\"text\": \",\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\angle BOD = x + 25^{\\\\circ}\"}, {\"text\": \"．则\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\angle AOD\"}, {\"text\": \"的度数为____．\", \"type\": \"text\"}, {\"kind\": \"embedded_image\", \"type\": \"figure\", \"width\": 1299, \"height\": 805, \"sha256\": \"6e78fcb04e0d2df0d7157e4ff4400e6938127ee53dd0bb6fa4909f76ae5a4aab\", \"caption\": \"\", \"asset_key\": \"math/2026/09/2b06312b-7e3f-494e-ae3e-21d10207fcf7/65ea7ba8-ee3c-495b-a74e-ed45ac45c07d/6e78fcb04e0d.png\", \"public_url\": \"http://tikupdfpng.mtwlkj.net:5129/qbank/math/2026/09/2b06312b-7e3f-494e-ae3e-21d10207fcf7/65ea7ba8-ee3c-495b-a74e-ed45ac45c07d/6e78fcb04e0d.png\", \"source_bbox\": [30.0, 163.3499755859375, 313.4100036621094, 336.6999816894531], \"source_page\": 6}], \"source\": {\"bbox\": [30.0, 141.94, 534.94, 155.68], \"file\": \"人教版/七下/2026江苏七年级期末数学试卷+答案5.pdf\", \"regions\": [{\"bbox\": [30.0, 141.94, 534.94, 155.68], \"page\": 6}], \"section\": \"match\", \"page_end\": 6, \"page_start\": 6, \"section_label\": \"智适化匹配练习   ★ 交互式系统学习\", \"answer_regions\": [], \"answer_original\": \"\", \"solution_original\": \"\"}, \"version\": 1, \"grade_level\": \"JUNIOR\", \"number_label\": \"3\", \"subject_code\": \"math\", \"question_type\": \"fill_blank\", \"content_sha256\": \"167c1f15ea771591b5affdfe354a7a6f5fc1d27dc53ebb98e0b7334f4f2c2794\"}","body_html":"<div>如图，直线AB、CD相交于点O,\\(\\angle AOC = 2x - 10^{\\circ}\\),\\(\\angle BOD = x + 25^{\\circ}\\)．则\\(\\angle AOD\\)的度数为____．<img class=\"question-figure\" src=\"http://tikupdfpng.mtwlkj.net:5129/qbank/math/2026/09/2b06312b-7e3f-494e-ae3e-21d10207fcf7/65ea7ba8-ee3c-495b-a74e-ed45ac45c07d/6e78fcb04e0d.png\" style=\"width:377.9px!important;max-width:100%;height:auto\" alt=\"\" title=\"点击查看原图\"></div>","answer_html":"","ways_html":"","explain_html":null,"difficulty":2,"score":null,"year":null,"parse_status":"PARSED","qa_status":"QUARANTINED","retry_count":0,"final_score":0.925,"error_message":"QA failed: COHERENCE,ANSWER","published_question_id":null,"content_sha256":"167c1f15ea771591b5affdfe354a7a6f5fc1d27dc53ebb98e0b7334f4f2c2794","created_at":"2026-09-25T03:06:50","updated_at":"2026-09-25T03:19:02","answer_missing":true,"formula_fallback":false,"_number":"3","_section":"match","_section_label":"智适化匹配练习   ★ 交互式系统学习"},"assets":[{"id":4709,"asset_uuid":"2fe45e92cc224205a3d1bea0320635cf","job_id":3,"import_question_id":21691,"asset_type":"embedded_image","source_file":"2026江苏七年级期末数学试卷+答案5.pdf","source_page":6,"source_bbox":"[30.0, 163.35, 313.41, 336.7]","sha256":"6e78fcb04e0d2df0d7157e4ff4400e6938127ee53dd0bb6fa4909f76ae5a4aab","local_path":"/www/wwwroot/tikupdfpng.mtwlkj.net_5129/qbank/math/2026/09/2b06312b-7e3f-494e-ae3e-21d10207fcf7/65ea7ba8-ee3c-495b-a74e-ed45ac45c07d/6e78fcb04e0d.png","asset_key":"math/2026/09/2b06312b-7e3f-494e-ae3e-21d10207fcf7/65ea7ba8-ee3c-495b-a74e-ed45ac45c07d/6e78fcb04e0d.png","public_url":"http://tikupdfpng.mtwlkj.net:5129/qbank/math/2026/09/2b06312b-7e3f-494e-ae3e-21d10207fcf7/65ea7ba8-ee3c-495b-a74e-ed45ac45c07d/6e78fcb04e0d.png","width":1299,"height":805,"qa_status":"PENDING","created_at":"2026-09-25T03:14:07","safe_public_url":"http://tikupdfpng.mtwlkj.net:5129/qbank/math/2026/09/2b06312b-7e3f-494e-ae3e-21d10207fcf7/65ea7ba8-ee3c-495b-a74e-ed45ac45c07d/6e78fcb04e0d.png"}],"knowledge":[],"audits":[{"id":428749,"import_question_id":21691,"audit_type":"STRUCTURE","auditor_name":"structure-rule","status":"PASS","score":0.9,"input_snapshot":"如图，直线AB、CD相交于点O, \\angle AOC = 2x - 10^{\\circ} , \\angle BOD = x + 25^{\\circ} ．则 \\angle AOD 的度数为____． [图]","result_json":"{\"ok\": true, \"rule\": \"clean-override\", \"issues\": [], \"confidence\": 0.9}","created_at":"2026-09-25T03:14:52"},{"id":428750,"import_question_id":21691,"audit_type":"FORMULA","auditor_name":"formula-auditor","status":"PASS","score":1.0,"input_snapshot":"\\angle AOC = 2x - 10^{\\circ}; \\angle BOD = x + 25^{\\circ}; \\angle AOD","result_json":"{\"risky\": 2, \"issues\": [], \"checked\": 3, \"invalid\": 0, \"visual_check\": \"delegated_to_question_vision\", \"invalid_details\": [], \"visually_verified\": 0}","created_at":"2026-09-25T03:14:52"},{"id":428751,"import_question_id":21691,"audit_type":"KNOWLEDGE","auditor_name":"knowledge-auditor","status":"WARN","score":0.0,"input_snapshot":"如图，直线AB、CD相交于点O, \\angle AOC = 2x - 10^{\\circ} , \\angle BOD = x + 25^{\\circ} ．则 \\angle AOD 的度数为____． [图]","result_json":"{\"picks\": [], \"tree_code\": \"KT_JUNIOR_MATH_STANDARD\", \"candidates\": 0, \"classifier_version\": null}","created_at":"2026-09-25T03:14:52"},{"id":428758,"import_question_id":21691,"audit_type":"VISION","auditor_name":"vision-auditor","status":"PASS","score":1.0,"input_snapshot":"题干：\n如图，直线AB、CD相交于点O,\\(\\angle AOC = 2x - 10^{\\circ}\\),\\(\\angle BOD = x + 25^{\\circ}\\)．则\\(\\angle AOD\\)的度数为____．\n答案：\n\n解析：\n","result_json":"{\"ok\": true, \"hard\": false, \"issues\": [], \"confidence\": 1.0, \"suggestions\": [\"解析部分可以补充更详细的步骤说明，例如先解出x的值，再代入计算∠AOC和∠BOD的具体度数，最后利用邻补角关系求出∠AOD。\"]}","created_at":"2026-09-25T03:15:23"},{"id":428766,"import_question_id":21691,"audit_type":"SOLVER","auditor_name":"blind-solver","status":"PASS","score":0.9,"input_snapshot":"如图，直线AB、CD相交于点O, \\angle AOC = 2x - 10^{\\circ} , \\angle BOD = x + 25^{\\circ} ．则 \\angle AOD 的度数为____． [图]","result_json":"{\"basis\": \"直线AB、CD相交于点O，∠AOC与∠BOD为对顶角，故∠AOC = ∠BOD。由2x - 10° = x + 25°，解得x = 35°，因此∠AOC = 2×35° - 10° = 60°。由于∠AOD与∠AOC互补（邻补角），所以∠AOD = 180° - 60° = 120°。\", \"answer\": \"125°\", \"confidence\": 0.9, \"handout_chars\": 0}","created_at":"2026-09-25T03:15:39"},{"id":428767,"import_question_id":21691,"audit_type":"CRITIC","auditor_name":"critic","status":"PASS","score":0.9,"input_snapshot":"来源答案: || 盲解:125°","result_json":"{\"ok\": true, \"issues\": [], \"merged\": true, \"confidence\": 0.9}","created_at":"2026-09-25T03:15:39"},{"id":428768,"import_question_id":21691,"audit_type":"SYMBOLIC","auditor_name":"symbolic-auditor","status":"WARN","score":0.5,"input_snapshot":"答案: || 盲解:125°","result_json":"{\"checks\": [], \"detail\": {\"reason\": \"未提取到来源答案\"}, \"status\": \"WARN\", \"applicable\": true}","created_at":"2026-09-25T03:15:39"},{"id":428771,"import_question_id":21691,"audit_type":"COHERENCE","auditor_name":"coherence-auditor","status":"FAIL","score":0.9,"input_snapshot":"答案: || 解析:","result_json":"{\"ok\": false, \"which\": [\"answer\", \"solution\"], \"issues\": [\"答案和解析均为空，缺少必要的推导过程和最终答案。\"], \"confidence\": 0.9, \"equation_checks\": []}","created_at":"2026-09-25T03:15:51"},{"id":428772,"import_question_id":21691,"audit_type":"QUALITY_GATE","auditor_name":"quality-gate","status":"FAIL","score":0.925,"input_snapshot":"","result_json":"{\"warnings\": [], \"graded_gate\": true, \"hard_failed\": [\"COHERENCE\", \"ANSWER\"]}","created_at":"2026-09-25T03:15:51"},{"id":428814,"import_question_id":21691,"audit_type":"SOLVER","auditor_name":"blind-solver","status":"PASS","score":1.0,"input_snapshot":"如图，直线AB、CD相交于点O, \\angle AOC = 2x - 10^{\\circ} , \\angle BOD = x + 25^{\\circ} ．则 \\angle AOD 的度数为____． [图]","result_json":"{\"basis\": \"直线AB、CD相交于点O，∠AOC与∠BOD为对顶角，故相等。由2x - 10° = x + 25°，解得x = 35°，从而∠AOC = 60°。又∠AOD与∠AOC互补（邻补角），所以∠AOD = 180° - 60° = 125°。\", \"answer\": \"125°\", \"confidence\": 1.0, \"handout_chars\": 0}","created_at":"2026-09-25T03:17:09"},{"id":428815,"import_question_id":21691,"audit_type":"CRITIC","auditor_name":"critic","status":"PASS","score":1.0,"input_snapshot":"来源答案:125° || 盲解:125°","result_json":"{\"ok\": true, \"issues\": [], \"merged\": true, \"confidence\": 1.0}","created_at":"2026-09-25T03:17:09"},{"id":428833,"import_question_id":21691,"audit_type":"COHERENCE","auditor_name":"coherence-auditor","status":"FAIL","score":0.9,"input_snapshot":"答案:125° || 解析:因为直线AB、CD相交于点O，所以∠AOC与∠BOD是对顶角，根据对顶角相等的性质，有∠AOC = ∠BOD。已知∠AOC = 2x - 10°，∠BOD = x + 25°，因此可列方程：2x - 10 = x + 25。解此方程得：2x - x = 25 + 10，即x = 35。将x = 35代入∠AOC表达式，得∠AOC =\\(2\\times 35 - 10 = 70 - 10 = 60°","result_json":"{\"ok\": false, \"which\": [\"answer\"], \"issues\": [\"解析得出的∠AOD为120°，但给出的答案是125°，答案与解析不一致\"], \"confidence\": 0.9, \"equation_checks\": [{\"valid\": true, \"reason\": \"对顶角相等，方程建立正确\", \"equation\": \"2x - 10 = x + 25\"}, {\"valid\": true, \"reason\": \"解方程正确\", \"equation\": \"x = 35\"}, {\"valid\": true, \"reason\": \"代入计算正确\", \"equation\": \"∠AOC = 2×35 - 10 = 60°\"}, {\"valid\": true, \"reason\": \"邻补角关系正确，计算正确\", \"equation\": \"∠AOD = 180° - 60° = 120°\"}]}","created_at":"2026-09-25T03:19:02"},{"id":428834,"import_question_id":21691,"audit_type":"SYMBOLIC","auditor_name":"symbolic-auditor","status":"PASS","score":1.0,"input_snapshot":"答案:125° || 盲解:125°","result_json":"{\"checks\": [], \"detail\": {\"reason\": \"盲解与来源答案一致\"}, \"status\": \"PASS\", \"applicable\": true}","created_at":"2026-09-25T03:19:02"},{"id":428835,"import_question_id":21691,"audit_type":"AUTO_REPAIR_ATTEMPT","auditor_name":"answer-repair","status":"FAIL","score":0.9,"input_snapshot":null,"result_json":"{\"critic\": true, \"symbolic\": true, \"coherence\": false, \"consensus\": \"two_solvers+symbolic+critic+coherence\", \"confidence\": 0.9, \"verifier_base\": \"http://127.0.0.1:8092/v1\", \"verifier_confidence\": 1.0, \"critic_explicit_pass\": true, \"symbolic_literal_warn\": false, \"symbolic_explicit_pass\": true, \"coherence_explicit_pass\": false}","created_at":"2026-09-25T03:19:02"}]}