{"ok":true,"question":{"id":21730,"question_uuid":"eb0c122c-ae78-4f0a-8ba2-df4d80891c86","job_id":3,"source_file":"人教版/七下/2026江苏七年级期末数学试卷+答案55.pdf","source_page_start":2,"source_page_end":2,"source_bbox":"[30.22, 89.87, 136.61, 242.47]","subject_code":"math","grade_level":"SENIOR","tree_code":"KT_SENIOR_MATH_STANDARD","question_type":"single_choice","canonical_json":"{\"year\": null, \"blocks\": [{\"text\": \"如图，属于同位角的是(     )\", \"type\": \"text\"}, {\"type\": \"option\", \"label\": \"A\", \"blocks\": [{\"text\": \"∠2与∠3\", \"type\": \"text\"}], \"source_bbox\": [42.47, 204.2, 70.6, 213.26], \"source_page\": 2}, {\"type\": \"option\", \"label\": \"B\", \"blocks\": [{\"text\": \"∠1与∠4\", \"type\": \"text\"}], \"source_bbox\": [42.47, 213.89, 70.6, 222.95], \"source_page\": 2}, {\"type\": \"option\", \"label\": \"C\", \"blocks\": [{\"text\": \"∠1与∠3\", \"type\": \"text\"}], \"source_bbox\": [42.47, 224.1, 70.6, 233.16], \"source_page\": 2}, {\"type\": \"option\", \"label\": \"D\", \"blocks\": [], \"source_bbox\": [30.22, 234.31, 42.47, 242.47], \"source_page\": 2}, {\"type\": \"answer\", \"blocks\": [{\"text\": \"A\", \"type\": \"text\"}]}, {\"type\": \"solution\", \"blocks\": [{\"text\": \"由图得，∠2与∠3是两条直线被第三条直线所截形成的同位角,因此选项A符合题意. ∠1与∠4是对顶角,因此选项B不符合题意. ∠1与∠3是内错角，因此 选项C不符合题意. ∠2与∠4同旁内角, 因此选项D不符合题意. 故选: A． 6. A A、不是同位角，故本选项符合题意；B、是同位角，故本选项不符合题意；C 、是同位角，故本选项不符合题意；D、是同位角，故本选 项不符合题意．故选A． 7. A A、∠3和∠7是同位角，正确，符合题意；B、 ∠1的同旁内角有∠3, ∠8等，故原说法错误，不符合题意；C 、 ∠3不一定等于∠4，故原说法错 误，不符合题意；D、 ∠5的同位角有∠2, ∠4，故原说法错误，不符合题意；故选：A．\", \"type\": \"text\"}]}], \"source\": {\"bbox\": [30.22, 89.87, 136.61, 242.47], \"file\": \"人教版/七下/2026江苏七年级期末数学试卷+答案55.pdf\", \"regions\": [{\"bbox\": [30.22, 89.87, 136.61, 242.47], \"page\": 2}], \"section\": \"generic\", \"page_end\": 2, \"page_start\": 2, \"section_label\": \"\", \"answer_regions\": [{\"bbox\": [24.09337615966797, 482.9770812988281, 564.0861206054688, 571.538818359375], \"page\": 5}], \"answer_original\": \"A\", \"solution_original\": \"由图得，∠2与∠3是两条直线被第三条直线所截形成的同位角,因此选项A符合题意. ∠1与∠4是对顶角,因此选项B不符合题意. ∠1与∠3是内错角，因此 选项C不符合题意. ∠2与∠4同旁内角, 因此选项D不符合题意. 故选: A． 6. A A、不是同位角，故本选项符合题意；B、是同位角，故本选项不符合题意；C 、是同位角，故本选项不符合题意；D、是同位角，故本选 项不符合题意．故选A． 7. A A、∠3和∠7是同位角，正确，符合题意；B、 ∠1的同旁内角有∠3, ∠8等，故原说法错误，不符合题意；C 、 ∠3不一定等于∠4，故原说法错 误，不符合题意；D、 ∠5的同位角有∠2, ∠4，故原说法错误，不符合题意；故选：A．\"}, \"version\": 1, \"grade_level\": \"SENIOR\", \"number_label\": \"5\", \"subject_code\": \"math\", \"question_type\": \"single_choice\", \"content_sha256\": \"5a86a86f194b225963602952f0c580fc72f04363721a0cc5e1e00c86a2c8d5c3\"}","body_html":"<div>如图，属于同位角的是(     )<br>A. ∠2与∠3<br>B. ∠1与∠4<br>C. ∠1与∠3<br>D.</div>","answer_html":"A","ways_html":"由图得，∠2与∠3是两条直线被第三条直线所截形成的同位角,因此选项A符合题意. ∠1与∠4是对顶角,因此选项B不符合题意. ∠1与∠3是内错角，因此 选项C不符合题意. ∠2与∠4同旁内角, 因此选项D不符合题意. 故选: A． 6. A A、不是同位角，故本选项符合题意；B、是同位角，故本选项不符合题意；C 、是同位角，故本选项不符合题意；D、是同位角，故本选 项不符合题意．故选A． 7. A A、∠3和∠7是同位角，正确，符合题意；B、 ∠1的同旁内角有∠3, ∠8等，故原说法错误，不符合题意；C 、 ∠3不一定等于∠4，故原说法错 误，不符合题意；D、 ∠5的同位角有∠2, ∠4，故原说法错误，不符合题意；故选：A．","explain_html":null,"difficulty":1,"score":null,"year":null,"parse_status":"PARSED","qa_status":"QUARANTINED","retry_count":0,"final_score":0.938,"error_message":"发布失败: 正式发布门禁：选项内容为空: D","published_question_id":null,"content_sha256":"5a86a86f194b225963602952f0c580fc72f04363721a0cc5e1e00c86a2c8d5c3","created_at":"2026-09-25T03:34:21","updated_at":"2026-09-25T03:35:03","answer_missing":false,"formula_fallback":false,"_number":"5","_section":"generic","_section_label":""},"assets":[],"knowledge":[],"audits":[{"id":429651,"import_question_id":21730,"audit_type":"STRUCTURE","auditor_name":"structure-rule","status":"PASS","score":0.9,"input_snapshot":"如图，属于同位角的是( ) A. ∠2与∠3 B. ∠1与∠4 C. ∠1与∠3 D.","result_json":"{\"ok\": true, \"rule\": \"clean-override\", \"issues\": [], \"confidence\": 0.9}","created_at":"2026-09-25T03:34:22"},{"id":429652,"import_question_id":21730,"audit_type":"FORMULA","auditor_name":"formula-auditor","status":"PASS","score":1.0,"input_snapshot":"","result_json":"{\"note\": \"无公式块\", \"checked\": 0}","created_at":"2026-09-25T03:34:22"},{"id":429653,"import_question_id":21730,"audit_type":"KNOWLEDGE","auditor_name":"knowledge-auditor","status":"WARN","score":0.0,"input_snapshot":"如图，属于同位角的是( ) A. ∠2与∠3 B. ∠1与∠4 C. ∠1与∠3 D.","result_json":"{\"picks\": [], \"tree_code\": \"KT_SENIOR_MATH_STANDARD\", \"candidates\": 0, \"classifier_version\": null}","created_at":"2026-09-25T03:34:23"},{"id":429664,"import_question_id":21730,"audit_type":"VISION","auditor_name":"vision-auditor","status":"PASS","score":0.95,"input_snapshot":"题干：\n如图，属于同位角的是( ) A. ∠2与∠3 B. ∠1与∠4 C. ∠1与∠3 D.\n答案：\nA\n解析：\n由图得，∠2与∠3是两条直线被第三条直线所截形成的同位角,因此选项A符合题意. ∠1与∠4是对顶角,因此选项B不符合题意. ∠1与∠3是内错角，因此 选项C不符合题意. ∠2与∠4同旁内角, 因此选项D不符合题意. 故选: A． 6. A A、不是同位角，故本选项符合题意；B、是同位角，故本选项不符合题意；C 、是同位角，故本选项不符合题意；D、是同位角，故本选 项不符合题意．故选A． 7. A A、∠3和∠7是同位角，正确，符合题意；B、 ∠1的同旁内角有∠3, ∠8等，故原说法错误，不符合题意；C 、 ∠3不一定等于∠4，故原说法错 误，不符合题意；D、 ∠5的同位角有∠2, ∠4，故原说法错误，不符合题意；故选：A．","result_json":"{\"ok\": true, \"hard\": false, \"issues\": [], \"confidence\": 0.95, \"suggestions\": [\"解析部分存在冗余内容（第6、7题的解析），建议仅保留与题干对应的第5题解析\"]}","created_at":"2026-09-25T03:34:48"},{"id":429667,"import_question_id":21730,"audit_type":"SOLVER","auditor_name":"blind-solver","status":"PASS","score":0.9,"input_snapshot":"如图，属于同位角的是( ) A. ∠2与∠3 B. ∠1与∠4 C. ∠1与∠3 D.","result_json":"{\"basis\": \"同位角是指两条直线被第三条直线所截，在截线同旁，且在被截两直线同一侧的角。观察图形，∠2与∠3分别位于截线（右侧斜线）的同侧，且处于被截直线（水平线与左侧斜线）的同一方，符合同位角定义。\", \"answer\": \"A\", \"confidence\": 0.9, \"handout_chars\": 0}","created_at":"2026-09-25T03:34:54"},{"id":429668,"import_question_id":21730,"audit_type":"CRITIC","auditor_name":"critic","status":"PASS","score":1.0,"input_snapshot":"来源答案:A || 盲解:A","result_json":"{\"ok\": true, \"issues\": [], \"merged\": true, \"confidence\": 1.0}","created_at":"2026-09-25T03:34:54"},{"id":429669,"import_question_id":21730,"audit_type":"SYMBOLIC","auditor_name":"symbolic-auditor","status":"PASS","score":1.0,"input_snapshot":"答案:A || 盲解:A","result_json":"{\"checks\": [], \"detail\": {\"reason\": \"盲解与来源答案一致\"}, \"status\": \"PASS\", \"applicable\": true}","created_at":"2026-09-25T03:34:54"},{"id":429676,"import_question_id":21730,"audit_type":"COHERENCE","auditor_name":"coherence-auditor","status":"PASS","score":0.9,"input_snapshot":"答案:A || 解析:由图得，∠2与∠3是两条直线被第三条直线所截形成的同位角,因此选项A符合题意. ∠1与∠4是对顶角,因此选项B不符合题意. ∠1与∠3是内错角，因此 选项C不符合题意. ∠2与∠4同旁内角, 因此选项D不符合题意. 故选: A． 6. A A、不是同位角，故本选项符合题意；B、是同位角，故本选项不符合题意；C 、是同位角，故本选项不符合题意；D、是同位角，故本选 项不符合题意．故选A． 7. A ","result_json":"{\"ok\": true, \"which\": [], \"issues\": [], \"confidence\": 0.9, \"equation_checks\": []}","created_at":"2026-09-25T03:35:03"},{"id":429677,"import_question_id":21730,"audit_type":"QUALITY_GATE","auditor_name":"quality-gate","status":"PASS","score":0.938,"input_snapshot":"","result_json":"{\"warnings\": [], \"graded_gate\": true, \"hard_failed\": []}","created_at":"2026-09-25T03:35:03"},{"id":430105,"import_question_id":21730,"audit_type":"RETRO_REPAIR","auditor_name":"retro-deterministic","status":"FAIL","score":0.3,"input_snapshot":"A","result_json":"{\"hard\": {\"option_defect\": \"选项内容为空: D\"}, \"fixes\": {}, \"status_to\": \"QUARANTINED\", \"status_from\": \"QUARANTINED\"}","created_at":"2026-09-25T03:37:35"},{"id":430855,"import_question_id":21730,"audit_type":"RETRO_REPAIR","auditor_name":"retro-deterministic","status":"FAIL","score":0.3,"input_snapshot":"A","result_json":"{\"hard\": {\"option_defect\": \"选项内容为空: D\"}, \"fixes\": {}, \"status_to\": 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