{"ok":true,"question":{"id":21740,"question_uuid":"583bf787-b1e9-4643-b720-691969084373","job_id":3,"source_file":"人教版/七下/2026江苏七年级期末数学试卷+答案55.pdf","source_page_start":4,"source_page_end":4,"source_bbox":"[30.22, 427.86, 328.52, 457.73]","subject_code":"math","grade_level":"SENIOR","tree_code":"KT_SENIOR_MATH_STANDARD","question_type":"subjective","canonical_json":"{\"year\": null, \"blocks\": [{\"text\": \"如图直线AB、 CD相交于点O,过点O作射线OF ⊥ CD,作射线OE平分∠COF．\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\frac{(1)}{(2)}\"}, {\"text\": \"若∠BOE= 105∘，求∠AOC的度数； 若∠BOE的度数比∠AOC的度数大85∘，求∠AOC的度数．\", \"type\": \"text\"}, {\"kind\": \"embedded_image\", \"type\": \"figure\", \"width\": 520, \"height\": 349, \"sha256\": \"2c65f74dd45aa77b4b84ad7c11554b97fdee9072b77e961c06fb4ccaffdfb72e\", \"caption\": \"\", \"asset_key\": \"math/2026/09/2b06312b-7e3f-494e-ae3e-21d10207fcf7/583bf787-b1e9-4643-b720-691969084373/2c65f74dd45a.png\", \"public_url\": \"http://tikupdfpng.mtwlkj.net:5129/qbank/math/2026/09/2b06312b-7e3f-494e-ae3e-21d10207fcf7/583bf787-b1e9-4643-b720-691969084373/2c65f74dd45a.png\", \"source_bbox\": [30.21787452697754, 458.2359619140625, 126.67874908447266, 529.1781005859375], \"source_page\": 4}, {\"type\": \"answer\", \"blocks\": [{\"text\": \"30∘; 25∘\", \"type\": \"text\"}]}, {\"type\": \"solution\", \"blocks\": [{\"text\": \"∵OF⊥CD, ∴∠FOC= 90∘, ∵OE平分∠COF, ∴∠EOC=\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\frac{1}{2}\"}, {\"text\": \"∠FOC= 45∘,因为∠BOE= 105∘, ∴∠AOC= 180∘−105∘−45∘= 30∘;\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\frac{(1)}{(2)}\"}, {\"text\": \"∵∠AOC + ∠BOE + ∠EOC= 180∘,  又 ∵∠EOC= 45∘, ∴∠AOC + ∠BOE135∘,  又 ∵∠BOE= ∠AOC + 85∘, ∴∠AOC= 25∘.=\", \"type\": \"text\"}]}], \"source\": {\"bbox\": [30.22, 427.86, 328.52, 457.73], \"file\": \"人教版/七下/2026江苏七年级期末数学试卷+答案55.pdf\", \"regions\": [{\"bbox\": [30.22, 427.86, 328.52, 457.73], \"page\": 4}], \"section\": \"generic\", \"page_end\": 4, \"page_start\": 4, \"section_label\": \"\", \"answer_regions\": [{\"bbox\": [36.342376708984375, 402.8692321777344, 520.0476684570312, 440.883056640625], \"page\": 6}], \"answer_original\": \"30∘; 25∘\", \"solution_original\": \"∵OF⊥CD, ∴∠FOC= 90∘, ∵OE平分∠COF, ∴∠EOC= \\\\frac{1}{2} ∠FOC= 45∘,因为∠BOE= 105∘, ∴∠AOC= 180∘−105∘−45∘= 30∘; \\\\frac{(1)}{(2)} ∵∠AOC + ∠BOE + ∠EOC= 180∘,  又 ∵∠EOC= 45∘, ∴∠AOC + ∠BOE135∘,  又 ∵∠BOE= ∠AOC + 85∘, ∴∠AOC= 25∘.=\"}, \"version\": 1, \"grade_level\": \"SENIOR\", \"number_label\": \"15\", \"subject_code\": \"math\", \"question_type\": \"subjective\", \"content_sha256\": \"3ee825b6a32c28c8edab21253e84588bb9feeeeb373155ad1f71d75e3aa9c29f\"}","body_html":"<div>如图直线AB、 CD相交于点O,过点O作射线OF ⊥ CD,作射线OE平分∠COF．\\(\\frac{(1)}{(2)}\\)若∠BOE= 105∘，求∠AOC的度数； 若∠BOE的度数比∠AOC的度数大85∘，求∠AOC的度数．<img class=\"question-figure\" src=\"http://tikupdfpng.mtwlkj.net:5129/qbank/math/2026/09/2b06312b-7e3f-494e-ae3e-21d10207fcf7/583bf787-b1e9-4643-b720-691969084373/2c65f74dd45a.png\" style=\"width:128.6px!important;max-width:100%;height:auto\" alt=\"\" title=\"点击查看原图\"></div>","answer_html":"30∘; 25∘","ways_html":"∵OF⊥CD, ∴∠FOC= 90∘, ∵OE平分∠COF, ∴∠EOC=\\(\\frac{1}{2}\\)∠FOC= 45∘,因为∠BOE= 105∘, ∴∠AOC= 180∘−105∘−45∘= 30∘;\\(\\frac{(1)}{(2)}\\)∵∠AOC + ∠BOE + ∠EOC= 180∘,  又 ∵∠EOC= 45∘, ∴∠AOC + ∠BOE135∘,  又 ∵∠BOE= ∠AOC + 85∘, ∴∠AOC= 25∘.=","explain_html":null,"difficulty":2,"score":null,"year":null,"parse_status":"PARSED","qa_status":"QUARANTINED","retry_count":0,"final_score":0.917,"error_message":"QA failed: SOLVER,CRITIC,COHERENCE","published_question_id":null,"content_sha256":"3ee825b6a32c28c8edab21253e84588bb9feeeeb373155ad1f71d75e3aa9c29f","created_at":"2026-09-25T03:34:21","updated_at":"2026-09-25T03:47:35","answer_missing":false,"formula_fallback":false,"_number":"15","_section":"generic","_section_label":""},"assets":[{"id":4737,"asset_uuid":"f91b21ac8a2745619bf29eceffe41dca","job_id":3,"import_question_id":21740,"asset_type":"embedded_image","source_file":"2026江苏七年级期末数学试卷+答案55.pdf","source_page":4,"source_bbox":"[30.22, 458.24, 126.68, 529.18]","sha256":"2c65f74dd45aa77b4b84ad7c11554b97fdee9072b77e961c06fb4ccaffdfb72e","local_path":"/www/wwwroot/tikupdfpng.mtwlkj.net_5129/qbank/math/2026/09/2b06312b-7e3f-494e-ae3e-21d10207fcf7/583bf787-b1e9-4643-b720-691969084373/2c65f74dd45a.png","asset_key":"math/2026/09/2b06312b-7e3f-494e-ae3e-21d10207fcf7/583bf787-b1e9-4643-b720-691969084373/2c65f74dd45a.png","public_url":"http://tikupdfpng.mtwlkj.net:5129/qbank/math/2026/09/2b06312b-7e3f-494e-ae3e-21d10207fcf7/583bf787-b1e9-4643-b720-691969084373/2c65f74dd45a.png","width":520,"height":349,"qa_status":"PENDING","created_at":"2026-09-25T03:38:42","safe_public_url":"http://tikupdfpng.mtwlkj.net:5129/qbank/math/2026/09/2b06312b-7e3f-494e-ae3e-21d10207fcf7/583bf787-b1e9-4643-b720-691969084373/2c65f74dd45a.png"}],"knowledge":[],"audits":[{"id":430185,"import_question_id":21740,"audit_type":"STRUCTURE","auditor_name":"structure-rule","status":"PASS","score":0.9,"input_snapshot":"如图直线AB、 CD相交于点O,过点O作射线OF ⊥ CD,作射线OE平分∠COF． \\frac{(1)}{(2)} 若∠BOE= 105∘，求∠AOC的度数； 若∠BOE的度数比∠AOC的度数大85∘，求∠AOC的度数． [图]","result_json":"{\"ok\": true, \"rule\": \"clean-override\", \"issues\": [], \"confidence\": 0.9}","created_at":"2026-09-25T03:44:09"},{"id":430186,"import_question_id":21740,"audit_type":"FORMULA","auditor_name":"formula-auditor","status":"PASS","score":1.0,"input_snapshot":"\\frac{(1)}{(2)}; \\frac{1}{2}; \\frac{(1)}{(2)}","result_json":"{\"risky\": 3, \"issues\": [], \"checked\": 3, \"invalid\": 0, \"visual_check\": \"delegated_to_question_vision\", \"invalid_details\": [], \"visually_verified\": 0}","created_at":"2026-09-25T03:44:09"},{"id":430187,"import_question_id":21740,"audit_type":"KNOWLEDGE","auditor_name":"knowledge-auditor","status":"WARN","score":0.0,"input_snapshot":"如图直线AB、 CD相交于点O,过点O作射线OF ⊥ CD,作射线OE平分∠COF． \\frac{(1)}{(2)} 若∠BOE= 105∘，求∠AOC的度数； 若∠BOE的度数比∠AOC的度数大85∘，求∠AOC的度数． [图]","result_json":"{\"picks\": [], \"tree_code\": \"KT_SENIOR_MATH_STANDARD\", \"candidates\": 0, \"classifier_version\": null}","created_at":"2026-09-25T03:44:09"},{"id":430188,"import_question_id":21740,"audit_type":"VISION","auditor_name":"vision-auditor","status":"PASS","score":0.95,"input_snapshot":"题干：\n如图直线AB、 CD相交于点O,过点O作射线OF ⊥ CD,作射线OE平分∠COF．\\(\\frac{(1)}{(2)}\\)若∠BOE= 105∘，求∠AOC的度数； 若∠BOE的度数比∠AOC的度数大85∘，求∠AOC的度数．\n答案：\n30∘; 25∘\n解析：\n∵OF⊥CD, ∴∠FOC= 90∘, ∵OE平分∠COF, ∴∠EOC=\\(\\frac{1}{2}\\)∠FOC= 45∘,因为∠BOE= 105∘, ∴∠AOC= 180∘−105∘−45∘= 30∘;\\(\\frac{(1)}{(2)}\\)∵∠AOC + ∠BOE + ∠EOC= 180∘, 又 ∵∠EOC= 45∘, ∴∠AOC + ∠BOE135∘, 又 ∵∠BOE= ∠AOC + 85∘, ∴∠AOC= 25∘.=","result_json":"{\"ok\": true, \"hard\": false, \"issues\": [], \"confidence\": 0.95, \"suggestions\": [\"解析中‘∠AOC + ∠BOE135°’缺少加号，建议修正为‘∠AOC + ∠BOE = 135°’以增强可读性\"]}","created_at":"2026-09-25T03:44:23"},{"id":430196,"import_question_id":21740,"audit_type":"SOLVER","auditor_name":"blind-solver","status":"WARN","score":0.4,"input_snapshot":"如图直线AB、 CD相交于点O,过点O作射线OF ⊥ CD,作射线OE平分∠COF． \\frac{(1)}{(2)} 若∠BOE= 105∘，求∠AOC的度数； 若∠BOE的度数比∠AOC的度数大85∘，求∠AOC的度数． [图]","result_json":"{\"note\": \"盲解+评判合并调用未返回\"}","created_at":"2026-09-25T03:46:54"},{"id":430197,"import_question_id":21740,"audit_type":"CRITIC","auditor_name":"critic","status":"WARN","score":0.5,"input_snapshot":"如图直线AB、 CD相交于点O,过点O作射线OF ⊥ CD,作射线OE平分∠COF． \\frac{(1)}{(2)} 若∠BOE= 105∘，求∠AOC的度数； 若∠BOE的度数比∠AOC的度数大85∘，求∠AOC的度数． [图]","result_json":"{\"note\": \"Critic 未返回结果\"}","created_at":"2026-09-25T03:46:54"},{"id":430198,"import_question_id":21740,"audit_type":"SYMBOLIC","auditor_name":"symbolic-auditor","status":"WARN","score":0.5,"input_snapshot":"答案:30∘; 25∘ || 盲解:","result_json":"{\"checks\": [], \"detail\": {\"reason\": \"盲解未给出答案\"}, \"status\": \"WARN\", \"applicable\": true}","created_at":"2026-09-25T03:46:54"},{"id":430199,"import_question_id":21740,"audit_type":"COHERENCE","auditor_name":"coherence-auditor","status":"FAIL","score":0.9,"input_snapshot":"答案:30∘; 25∘ || 解析:∵OF⊥CD, ∴∠FOC= 90∘, ∵OE平分∠COF, ∴∠EOC=\\(\\frac{1}{2}\\)∠FOC= 45∘,因为∠BOE= 105∘, ∴∠AOC= 180∘−105∘−45∘= 30∘;\\(\\frac{(1)}{(2)}\\)∵∠AOC + ∠BOE + ∠EOC= 180∘, 又 ∵∠EOC= 45∘, ∴∠AOC + ∠BOE135∘, 又 ∵∠BOE= ∠AOC + 85∘,","result_json":"{\"ok\": false, \"which\": [\"solution\"], \"issues\": [\"解析中两次错误地使用共线假设，导致角度关系不成立。\", \"第一个问题正确答案应为 120°，第二个问题应为 70°（通过正确方程组求解）。\", \"∠AOC = 180° − 105° − 45°: 在第一个问题中，∠AOC、∠BOE 和 ∠EOC 并不共线，不能直接相加等于 180°。正确的推导应为：∠BOC = ∠BOE − ∠EOC = 105° − 45° = 60°，再由对顶角或邻补角关系得 ∠AOC = 180° − ∠BOC = 120°，或 ∠AOC = ∠BOD，需重新分析图形结构。\", \"∠AOC + ∠BOE + ∠EOC = 180°: 在第二个问题中，同样错误地假设三个角共线。实际上，∠AOC 与 ∠BOC 互补，而 ∠BOC = ∠BOE − ∠EOC，因此应有 ∠AOC + (∠BOE − ∠EOC) = 180°，即 ∠AOC + ∠BOE = 180° + ∠EOC = 225°。\"], \"confidence\": 0.9, \"equation_checks\": [{\"valid\": false, \"reason\": \"在第一个问题中，∠AOC、∠BOE 和 ∠EOC 并不共线，不能直接相加等于 180°。正确的推导应为：∠BOC = ∠BOE − ∠EOC = 105° − 45° = 60°，再由对顶角或邻补角关系得 ∠AOC = 180° − ∠BOC = 120°，或 ∠AOC = ∠BOD，需重新分析图形结构。\", \"equation\": \"∠AOC = 180° − 105° − 45°\"}, {\"valid\": false, \"reason\": \"在第二个问题中，同样错误地假设三个角共线。实际上，∠AOC 与 ∠BOC 互补，而 ∠BOC = ∠BOE − ∠EOC，因此应有 ∠AOC + (∠BOE − ∠EOC) = 180°，即 ∠AOC + ∠BOE = 180° + ∠EOC = 225°。\", \"equation\": \"∠AOC + ∠BOE + ∠EOC = 180°\"}]}","created_at":"2026-09-25T03:47:35"},{"id":430200,"import_question_id":21740,"audit_type":"QUALITY_GATE","auditor_name":"quality-gate","status":"FAIL","score":0.917,"input_snapshot":"","result_json":"{\"warnings\": [\"SOLVER\"], \"graded_gate\": true, \"hard_failed\": [\"CRITIC\", \"COHERENCE\"]}","created_at":"2026-09-25T03:47:35"}]}