{"ok":true,"question":{"id":21926,"question_uuid":"e2ee98cb-8487-4c14-9bc3-e8f14ace75e0","job_id":3,"source_file":"人教版/七下/2026江苏七年级期末数学试卷+答案620.pdf","source_page_start":2,"source_page_end":2,"source_bbox":"[304.3, 263.79, 528.02, 350.38]","subject_code":"math","grade_level":"SENIOR","tree_code":"KT_SENIOR_MATH_STANDARD","question_type":"fill_blank","canonical_json":"{\"year\": null, \"blocks\": [{\"text\": \"如图，平行四边形ABCD在坐标系中的坐标 分别为(−4,1),(−1,2),(4, −1)，则点的坐标 D 为( ) ．(1,2) ．(−1,2) A B ．(1,−2) ．(2, −1) C D\", \"type\": \"text\"}, {\"kind\": \"embedded_image\", \"type\": \"figure\", \"width\": 637, \"height\": 487, \"sha256\": \"6d8a10a26fa9603c6f4ee29d8a418e101a5f1393efafbac1455a41972e59ba3e\", \"caption\": \"\", \"asset_key\": \"math/2026/09/2b06312b-7e3f-494e-ae3e-21d10207fcf7/e2ee98cb-8487-4c14-9bc3-e8f14ace75e0/6d8a10a26fa9.png\", \"public_url\": \"http://tikupdfpng.mtwlkj.net:5129/qbank/math/2026/09/2b06312b-7e3f-494e-ae3e-21d10207fcf7/e2ee98cb-8487-4c14-9bc3-e8f14ace75e0/6d8a10a26fa9.png\", \"source_bbox\": [303.04998779296875, 369.1479797363281, 427.6999816894531, 457.6399841308594], \"source_page\": 2}, {\"type\": \"solution\", \"blocks\": [{\"text\": \" ABCD是平行四边形，\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\frac{四边形}{BC}\"}, {\"text\": \"  且 BC = AD,\", \"type\": \"text\"}, {\"type\": \"math_inline\", \"latex\": \"\\\\frac{AD}{BC}\"}, {\"text\": \" 将线段 先向左平移个单位长度、再向3 下平移个单位长度得到线段1AD，  点坐标先向左平移个单位长度、再向下3 C 平移个单位长度可得点的坐标1(4 − 3,−−11)， D 即(1,−2)；故选：． C\", \"type\": \"text\"}]}], \"source\": {\"bbox\": [304.3, 263.79, 528.02, 350.38], \"file\": \"人教版/七下/2026江苏七年级期末数学试卷+答案620.pdf\", \"regions\": [{\"bbox\": [304.3, 263.79, 528.02, 350.38], \"page\": 2}], \"section\": \"example\", \"page_end\": 2, \"page_start\": 2, \"section_label\": \"跟我学        关键母题，常考题型各个击破！\", \"answer_regions\": [{\"bbox\": [302.8155212402344, 509.7515869140625, 545.39453125, 634.6578369140625], \"page\": 2}], \"answer_original\": \"\", \"solution_original\": \" ABCD是平行四边形， \\\\frac{四边形}{BC}   且 BC = AD, \\\\frac{AD}{BC}  将线段 先向左平移个单位长度、再向3 下平移个单位长度得到线段1AD，  点坐标先向左平移个单位长度、再向下3 C 平移个单位长度可得点的坐标1(4 − 3,−−11)， D 即(1,−2)；故选：． C\"}, \"version\": 1, \"grade_level\": \"SENIOR\", \"number_label\": \"2\", \"subject_code\": \"math\", \"question_type\": \"fill_blank\", \"content_sha256\": \"6e702ba71da3d694eeb2ebc495d07cfd8718709de4dbc25102879cb02f20a5ae\"}","body_html":"<div>如图，平行四边形ABCD在坐标系中的坐标 分别为(−4,1),(−1,2),(4, −1)，则点的坐标 D 为( ) ．(1,2) ．(−1,2) A B ．(1,−2) ．(2, −1) C D<img class=\"question-figure\" src=\"http://tikupdfpng.mtwlkj.net:5129/qbank/math/2026/09/2b06312b-7e3f-494e-ae3e-21d10207fcf7/e2ee98cb-8487-4c14-9bc3-e8f14ace75e0/6d8a10a26fa9.png\" style=\"width:166.2px!important;max-width:100%;height:auto\" alt=\"\" title=\"点击查看原图\"></div>","answer_html":"","ways_html":" ABCD是平行四边形，\\(\\frac{四边形}{BC}\\)  且 BC = AD,\\(\\frac{AD}{BC}\\) 将线段 先向左平移个单位长度、再向3 下平移个单位长度得到线段1AD，  点坐标先向左平移个单位长度、再向下3 C 平移个单位长度可得点的坐标1(4 − 3,−−11)， D 即(1,−2)；故选：． C","explain_html":null,"difficulty":2,"score":null,"year":null,"parse_status":"PARSED","qa_status":"QUARANTINED","retry_count":0,"final_score":0.938,"error_message":"QA failed: COHERENCE,ANSWER","published_question_id":null,"content_sha256":"6e702ba71da3d694eeb2ebc495d07cfd8718709de4dbc25102879cb02f20a5ae","created_at":"2026-09-25T04:32:25","updated_at":"2026-09-25T04:44:03","answer_missing":true,"formula_fallback":false,"_number":"2","_section":"example","_section_label":"跟我学        关键母题，常考题型各个击破！"},"assets":[{"id":4774,"asset_uuid":"2f01de68673c46e09d8d19ad43739252","job_id":3,"import_question_id":21926,"asset_type":"embedded_image","source_file":"2026江苏七年级期末数学试卷+答案620.pdf","source_page":2,"source_bbox":"[303.05, 369.15, 427.7, 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) ．(1,2) ．(−1,2) A B ．(1,−2) ．(2, −1) C D [图]","result_json":"{\"ok\": true, \"rule\": \"clean-override\", \"issues\": [], \"confidence\": 0.9}","created_at":"2026-09-25T04:38:56"},{"id":434054,"import_question_id":21926,"audit_type":"FORMULA","auditor_name":"formula-auditor","status":"PASS","score":1.0,"input_snapshot":"\\frac{四边形}{BC}; \\frac{AD}{BC}","result_json":"{\"risky\": 2, \"issues\": [], \"checked\": 2, \"invalid\": 0, \"visual_check\": \"delegated_to_question_vision\", \"invalid_details\": [], \"visually_verified\": 0}","created_at":"2026-09-25T04:38:56"},{"id":434055,"import_question_id":21926,"audit_type":"KNOWLEDGE","auditor_name":"knowledge-auditor","status":"WARN","score":0.0,"input_snapshot":"如图，平行四边形ABCD在坐标系中的坐标 分别为(−4,1),(−1,2),(4, −1)，则点的坐标 D 为( ) ．(1,2) ．(−1,2) A B ．(1,−2) ．(2, −1) C D [图]","result_json":"{\"picks\": [], \"tree_code\": \"KT_SENIOR_MATH_STANDARD\", \"candidates\": 0, \"classifier_version\": null}","created_at":"2026-09-25T04:38:56"},{"id":434072,"import_question_id":21926,"audit_type":"VISION","auditor_name":"vision-auditor","status":"PASS","score":0.95,"input_snapshot":"题干：\n如图，平行四边形ABCD在坐标系中的坐标 分别为(−4,1),(−1,2),(4, −1)，则点的坐标 D 为( ) ．(1,2) ．(−1,2) A B ．(1,−2) ．(2, −1) C D\n答案：\n\n解析：\n ABCD是平行四边形，\\(\\frac{四边形}{BC}\\)  且 BC = AD,\\(\\frac{AD}{BC}\\) 将线段 先向左平移个单位长度、再向3 下平移个单位长度得到线段1AD，  点坐标先向左平移个单位长度、再向下3 C 平移个单位长度可得点的坐标1(4 − 3,−−11)， D 即(1,−2)；故选：． C","result_json":"{\"ok\": true, \"hard\": false, \"issues\": [], \"confidence\": 0.95, \"suggestions\": [\"题干中点的顺序表述可更清晰，建议明确为‘A(-4,1), B(-1,2), C(4,-1)’以避免歧义\"]}","created_at":"2026-09-25T04:39:35"},{"id":434075,"import_question_id":21926,"audit_type":"SOLVER","auditor_name":"blind-solver","status":"PASS","score":1.0,"input_snapshot":"如图，平行四边形ABCD在坐标系中的坐标 分别为(−4,1),(−1,2),(4, −1)，则点的坐标 D 为( ) ．(1,2) ．(−1,2) A B ．(1,−2) ．(2, −1) C D [图]","result_json":"{\"basis\": \"在平行四边形ABCD中，对角线互相平分。设D(x,y)，则AC中点与BD中点重合。A(-4,1), C(4,-1)的中点为((−4+4)/2, (1+(−1))/2)=(0,0)。B(-1,2), D(x,y)的中点为((−1+x)/2, (2+y)/2)。令其等于(0,0)，得(−1+x)/2=0 ⇒ x=1；(2+y)/2=0 ⇒ y=−2。故D(1,−2)，对应选项A。\", \"answer\": \"A\", \"confidence\": 1.0, \"handout_chars\": 0}","created_at":"2026-09-25T04:39:40"},{"id":434076,"import_question_id":21926,"audit_type":"CRITIC","auditor_name":"critic","status":"PASS","score":1.0,"input_snapshot":"来源答案: || 盲解:A","result_json":"{\"ok\": true, \"issues\": [], \"merged\": true, \"confidence\": 1.0}","created_at":"2026-09-25T04:39:40"},{"id":434077,"import_question_id":21926,"audit_type":"SYMBOLIC","auditor_name":"symbolic-auditor","status":"WARN","score":0.5,"input_snapshot":"答案: || 盲解:A","result_json":"{\"checks\": [], \"detail\": {\"reason\": \"未提取到来源答案\"}, \"status\": \"WARN\", \"applicable\": true}","created_at":"2026-09-25T04:39:40"},{"id":434100,"import_question_id":21926,"audit_type":"COHERENCE","auditor_name":"coherence-auditor","status":"FAIL","score":0.9,"input_snapshot":"答案: || 解析: ABCD是平行四边形，\\(\\frac{四边形}{BC}\\)  且 BC = AD,\\(\\frac{AD}{BC}\\) 将线段 先向左平移个单位长度、再向3 下平移个单位长度得到线段1AD，  点坐标先向左平移个单位长度、再向下3 C 平移个单位长度可得点的坐标1(4 − 3,−−11)， D 即(1,−2)；故选：． C","result_json":"{\"ok\": false, \"which\": [\"solution\"], \"issues\": [\"解析中平移描述与数值计算不一致：'向下平移3个单位'实际只平移了1个单位。\", \"D = (4 - 3, -1 - 1) = (1, -2): 平移计算错误：原文称'向下平移3个单位'，但坐标从y=-1变为y=-2仅向下平移1个单位，与描述不符。\"], \"confidence\": 0.9, \"equation_checks\": [{\"valid\": false, \"reason\": \"平移计算错误：原文称'向下平移3个单位'，但坐标从y=-1变为y=-2仅向下平移1个单位，与描述不符。\", \"equation\": \"D = (4 - 3, -1 - 1) = (1, -2)\"}]}","created_at":"2026-09-25T04:40:32"},{"id":434101,"import_question_id":21926,"audit_type":"QUALITY_GATE","auditor_name":"quality-gate","status":"FAIL","score":0.938,"input_snapshot":"","result_json":"{\"warnings\": [], \"graded_gate\": true, \"hard_failed\": [\"COHERENCE\", \"ANSWER\"]}","created_at":"2026-09-25T04:40:32"},{"id":434156,"import_question_id":21926,"audit_type":"SOLVER","auditor_name":"blind-solver","status":"PASS","score":1.0,"input_snapshot":"如图，平行四边形ABCD在坐标系中的坐标 分别为(−4,1),(−1,2),(4, −1)，则点的坐标 D 为( ) ．(1,2) ．(−1,2) A B ．(1,−2) ．(2, −1) C D [图]","result_json":"{\"basis\": \"在平行四边形ABCD中，对角线互相平分。设D(x,y)，则AC中点与BD中点重合。A(-4,1), C(4,-1)的中点为((−4+4)/2, (1+(−1))/2)=(0,0)。B(-1,2), D(x,y)的中点为((−1+x)/2, (2+y)/2)。令其等于(0,0)，得(−1+x)/2=0 ⇒ x=1；(2+y)/2=0 ⇒ y=−2。故D(1,−2)，对应选项A。\", \"answer\": \"A\", \"confidence\": 1.0, \"handout_chars\": 0}","created_at":"2026-09-25T04:42:46"},{"id":434157,"import_question_id":21926,"audit_type":"CRITIC","auditor_name":"critic","status":"PASS","score":1.0,"input_snapshot":"来源答案:A || 盲解:A","result_json":"{\"ok\": true, \"issues\": [], \"merged\": true, \"confidence\": 1.0}","created_at":"2026-09-25T04:42:46"},{"id":434165,"import_question_id":21926,"audit_type":"COHERENCE","auditor_name":"coherence-auditor","status":"FAIL","score":0.95,"input_snapshot":"答案:A || 解析:由平行四边形ABCD的顶点A(-4,1)、B(-1,2)、C(4,-1)，根据向量关系，D点坐标可通过B点坐标加上向量AC得到。向量AC = C - A = (4 - (-4), -1 - 1) = (8, -2)。因此，D = B + AC = (-1 + 8, 2 + (-2)) = (7, 0)。但此结果不在选项中，说明需重新审视向量关系。实际上，在平行四边形中，向量AB = 向量DC。向量","result_json":"{\"ok\": false, \"which\": [], \"issues\": [\"D = B + AC = (-1 + 8, 2 + (-2)) = (7, 0): 计算结果 (7,0) 与后续正确推导矛盾，且不在选项中，说明该步向量关系应用错误（应为 D = A + AB + BC 或 D = C - DC，而非 B + AC）\"], \"confidence\": 0.95, \"equation_checks\": [{\"valid\": false, \"reason\": \"计算结果 (7,0) 与后续正确推导矛盾，且不在选项中，说明该步向量关系应用错误（应为 D = A + AB + BC 或 D = C - DC，而非 B + AC）\", \"equation\": \"D = B + AC = (-1 + 8, 2 + (-2)) = (7, 0)\"}, {\"valid\": true, \"reason\": \"B - A = (-1 - (-4), 2 - 1) = (3, 1)，正确\", \"equation\": \"向量AB = (3, 1)\"}, {\"valid\": true, \"reason\": \"C - D = (4 - x, -1 - y)，正确\", \"equation\": \"向量DC = (4 - x, -1 - y)\"}, {\"valid\": true, \"reason\": \"由 AB = DC 得此等式，正确\", \"equation\": \"(4 - x, -1 - y) = (3, 1)\"}, {\"valid\": true, \"reason\": \"解方程组 4 - x = 3 ⇒ x = 1；-1 - y = 1 ⇒ y = -2，正确\", \"equation\": \"x = 1, y = -2\"}]}","created_at":"2026-09-25T04:44:03"},{"id":434166,"import_question_id":21926,"audit_type":"SYMBOLIC","auditor_name":"symbolic-auditor","status":"PASS","score":1.0,"input_snapshot":"答案:A || 盲解:A","result_json":"{\"checks\": [], \"detail\": {\"reason\": \"盲解与来源答案一致\"}, \"status\": \"PASS\", \"applicable\": true}","created_at":"2026-09-25T04:44:03"},{"id":434167,"import_question_id":21926,"audit_type":"AUTO_REPAIR_ATTEMPT","auditor_name":"answer-repair","status":"FAIL","score":1.0,"input_snapshot":null,"result_json":"{\"critic\": true, \"symbolic\": true, \"coherence\": false, \"consensus\": \"two_solvers+symbolic+critic+coherence\", \"confidence\": 1.0, \"verifier_base\": \"http://127.0.0.1:8091/v1\", \"verifier_confidence\": 1.0, \"critic_explicit_pass\": true, \"symbolic_literal_warn\": false, \"symbolic_explicit_pass\": true, \"coherence_explicit_pass\": false}","created_at":"2026-09-25T04:44:03"}]}