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题目 #180368

UUID
095f5b73-7f83-4395-91a0-c445ed2ca45c
来源
沪教版/八下/周琼玟Q_18978751881_830.pdf 第 2 页,bbox [31.3, 221.9, 256.21, 272.77]
题型 / 学科
subjective / math / JUNIOR
知识树
KT_JUNIOR_MATH_STANDARD
难度
难度 2 / 5 简单 · 单一知识点
QA 状态
存疑 / 待修复 缺少答案 重试 0 次,得分 -
最终题 ID
-
错误
处理异常: LLM call failed after retries: HTTPConnectionPool(host='127.0.0.1', port=8091): Read timed out. (read timeout=120) [endpoints: http://127.0.0.1:8092/v1 -> http://127.0.0.1:8091/v1]

最终题干渲染(f_body 预览)

如图, 中,DE,分别交 于、\(\frac{ABC}{EEF} \frac{BC}{CD} \frac{AB}{AC}\)D 交 于, 垂直平分,分别交 于,\(\frac{AC}{BC}\)E 交 于.求证:四边形DFCE是菱形. F

答案 / 解析

答案(f_answer)缺少答案

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解析(f_ways)

 EF垂直平分CD.ED =, = FC\(\frac{ECFD}{FC}\) = ,又,\(\frac{EDC}{EDC} \frac{ECD}{DCF} \frac{DE}{ECD}\) = , = FCD, 设CD, EF交于点,O EF,\(\frac{垂直平分}{EOC}\frac{CD}{FOC}\) =  = ,在, 中\(\frac{EOC}{EOC} \frac{FOC}{FOC} \frac{90}{90}\) =  =   OC = OC EOC  FOC  = \(\frac{ECO}{CF} \frac{FCO}{DE}\) = CE, = EC = = FD,\(\frac{CF}{是菱形}\)所以:四边形DFCE

原图与资产(1)

预览类型页source bboxhashURL本地路径
embedded_image2 [30.05, 287.08, 173.55, 388.08] 6f513da44363e6e4…
打开
/www/wwwroot/tikupdfpng.mtwlkj.net_5129/qbank/math/2026/10/b66d1029-eef7-4822-b587-1e33acfa0201/55d2c17f-8a65-4039-8369-1a6c8b190478/6f513da44363.png

审计记录

阶段审计器结果得分依据(简短)
STRUCTURE structure-rule PASS 0.900
FORMULA formula-auditor PASS 1.000
KNOWLEDGE knowledge-auditor WARN -
VISION vision-auditor PASS 0.950

知识点(0)

无

事件

时间阶段级别消息
2026-11-09 23:09:29ERRORERROR处理异常: LLM call failed after retries: HTTPConnectionPool(host='127.0.0.1', port=8091): Read timed out. (read timeout=120) [endpoints: http://127.0.0.1:8092/v1 -> http://127.0.0.1:8091/v1]
2026-11-09 23:05:29FORMULAWARN公式转换未确认,保留原文本: solution
2026-11-09 23:01:29FORMULAWARN公式转换未确认,保留原文本: stem