题目 #180662
- UUID
5cad6191-4fcf-4bb0-8b70-51dc324f7532- 来源
- 青岛版/七上/杜辉Q_18951362233_1770.pdf 第 1 页,bbox
[30.0, 478.09, 282.05, 538.4] - 题型 / 学科
- fill_blank / math / JUNIOR
- 知识树
KT_JUNIOR_MATH_STANDARD- 难度
- 难度 2 / 5 简单 · 单一知识点
- QA 状态
- PUBLISHED 重试 0 次,得分 0.925
- 最终题 ID
30892
最终题干渲染(f_body 预览)
线段的和差计算: _________________________________________ _________________________________________

答案 / 解析
答案(f_answer)
AC + CD = AD, AD + DB = AB, AC + CB = AB, AB - AC = CB, AB - AD = DB, AD - AC = CD
解析(f_ways)
依据线段和差定义:若点C在线段AB上,则AC+CB=AB;若点D在线段AB上,则AD+DB=AB。由图可知点C、D均在线段AB上,且顺序为A-C-D-B,故可列出上述和差关系式。
原图与资产(1)
审计记录
| 阶段 | 审计器 | 结果 | 得分 | 依据(简短) |
|---|---|---|---|---|
| STRUCTURE | structure-rule | PASS | 0.900 | |
| FORMULA | formula-auditor | PASS | 1.000 | |
| KNOWLEDGE | knowledge-auditor | WARN | - | |
| VISION | vision-auditor | PASS | 0.900 | |
| SOLVER | blind-solver | PASS | 1.000 | |
| CRITIC | critic | PASS | 1.000 | |
| SYMBOLIC | symbolic-auditor | PASS | 1.000 | |
| COHERENCE | coherence-auditor | PASS | 0.900 | |
| QUALITY_GATE | quality-gate | PASS | 0.925 | |
| SOLVER | blind-solver | PASS | 1.000 | |
| CRITIC | critic | PASS | 1.000 | |
| AUTO_REPAIR_ATTEMPT | answer-repair | PASS | 1.000 | |
| AUTO_FILL_ANSWER | answer-repair | WARN | 1.000 | |
| VISION | vision-auditor | PASS | 0.950 |
知识点(0)
无
正式题库记录(t_question.f_id=30892)
- f_qkey
0739eac7e619b974880f5c1771cf30c6- f_style / 难度
- 3 / 2
- 入库题干
- 线段的和差计算: _________________________________________ _________________________________________

- 入库答案
- AC + CD = AD; AD + DB = AB; AC + CB = AB; AB - AC = CB; AB - AD = DB; AD - AC = CD
- 入库解析
- 依据线段和差定义:若点C在线段AB上,则AC+CB=AB;若点D在线段AB上,则AD+DB=AB。由图知A-C-D-B共线,故可推得各线段间和差关系。
事件
| 时间 | 阶段 | 级别 | 消息 |
|---|---|---|---|
| 2026-11-10 00:55:09 | PUBLISH | INFO | 已发布 t_question.f_id=30892 qkey=0739eac7e619b974880f5c1771cf30c6 |
| 2026-11-10 00:55:09 | QA | INFO | QA: PASS (score=0.925) |
| 2026-11-10 00:48:45 | HANDOUT | INFO | 注入学案核心知识点背景 160 字 |