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题目 #180982

UUID
158ff7e2-57c1-4eb6-8b42-1ec37fb3d303
来源
沪教版/八下/周琼玟Q_18978751881_855_检测.pdf 第 2 页,bbox [30.22, 511.49, 510.43, 660.68]
题型 / 学科
single_choice / math / JUNIOR
知识树
KT_JUNIOR_MATH_STANDARD
难度
难度 2 / 5 简单 · 单一知识点
QA 状态
存疑 / 待修复 重试 0 次,得分 -
最终题 ID
-
错误
处理异常: LLM call failed after retries: HTTPConnectionPool(host='127.0.0.1', port=8091): Read timed out. (read timeout=120) [endpoints: http://127.0.0.1:8092/v1 -> http://127.0.0.1:8091/v1]

最终题干渲染(f_body 预览)

如图,四边形ABCD是正方形,△ ADE是等边二角形,连接BD,BE,则∠DBE的度数为(          ).
A. 15∘
B. 20∘
C. 25∘
D. 30∘

答案 / 解析

答案(f_answer)

D

解析(f_ways)

因为四边形ABCD是正方形, ∴∠ABD = 45∘, AB = AD, ∠BAD = 90∘, ∵△ADE是 等边三角形, ∴AD = AE, ∠DAE= 60∘, ∴AB = AE, ∠BAE= ∠BAD + ∠DAE= 150∘, ∴∠ABE= ∠AEB =\(\frac{1}{2} (180∘−∠BAE) = 15∘\)∴∠DBE= ∠ABD −∠ABE=30∘. 故选:D.

原图与资产(1)

预览类型页source bboxhashURL本地路径
embedded_image2 [30.22, 526.63, 126.68, 581.24] 0b638c45224e8703…
打开
/www/wwwroot/tikupdfpng.mtwlkj.net_5129/qbank/math/2026/11/fa6762c7-a95b-46b0-8a9d-477bfc6d7525/158ff7e2-57c1-4eb6-8b42-1ec37fb3d303/0b638c45224e.png

审计记录

阶段审计器结果得分依据(简短)
STRUCTURE structure-rule PASS 0.900
FORMULA formula-auditor PASS 1.000
KNOWLEDGE knowledge-auditor WARN -
VISION vision-auditor PASS 1.000
SOLVER blind-solver PASS 0.950
CRITIC critic PASS 0.950
SYMBOLIC symbolic-auditor PASS 1.000

知识点(0)

无

事件

时间阶段级别消息
2026-11-10 03:56:44ERRORERROR处理异常: LLM call failed after retries: HTTPConnectionPool(host='127.0.0.1', port=8091): Read timed out. (read timeout=120) [endpoints: http://127.0.0.1:8092/v1 -> http://127.0.0.1:8091/v1]
2026-11-10 03:48:53FORMULAWARN公式转换未确认,保留原文本: solution