题目 #181645
- UUID
ae90392f-80eb-4e55-bee0-c3a0374a5f11- 来源
- 冀教版/八下/薛豪Q_18952688822_305.pdf 第 2 页,bbox
[30.0, 704.27, 450.22, 717.24] - 题型 / 学科
- fill_blank / math / JUNIOR
- 知识树
KT_JUNIOR_MATH_STANDARD- 难度
- 难度 1 / 5 最简单 · 识记/直接套公式
- QA 状态
- PUBLISHED 重试 0 次,得分 0.975
- 最终题 ID
44367
最终题干渲染(f_body 预览)
将一次函数\(y = 4(x + 1) - 5\)写成\(y = kx + b\)的形式,那么\(k =\)____,\(b =\)____.
答案 / 解析
答案(f_answer)
k = 4, b = -9
解析(f_ways)
将 y = 4(x + 1) - 5 展开:y = 4x + 4 - 5 = 4x - 9,对比 y = kx + b 得 k = 4, b = -9。
原图与资产(0)
该题没有裁出图片资产
审计记录
| 阶段 | 审计器 | 结果 | 得分 | 依据(简短) |
|---|---|---|---|---|
| STRUCTURE | structure-rule | PASS | 0.900 | |
| FORMULA | formula-auditor | PASS | 1.000 | |
| KNOWLEDGE | knowledge-auditor | WARN | - | |
| SOLVER | blind-solver | PASS | 1.000 | |
| CRITIC | critic | PASS | 1.000 | |
| VISION | vision-auditor | PASS | 1.000 | |
| SYMBOLIC | symbolic-auditor | WARN | 0.500 | |
| COHERENCE | coherence-auditor | PASS | 1.000 | |
| QUALITY_GATE | quality-gate | FAIL | 0.975 | |
| SOLVER | blind-solver | PASS | 1.000 | |
| CRITIC | critic | PASS | 1.000 | |
| COHERENCE | coherence-auditor | PASS | 1.000 | |
| SYMBOLIC | symbolic-auditor | PASS | 1.000 | |
| AUTO_REPAIR_ATTEMPT | answer-repair | PASS | 1.000 | |
| AUTO_REPAIR | answer-repair | PASS | 1.000 | |
| VISION | vision-auditor | PASS | 1.000 |
知识点(0)
无
正式题库记录(t_question.f_id=44367)
- f_qkey
a883ff573beb70bd9db41a75d26d9507- f_style / 难度
- 3 / 2
- 入库题干
- 将一次函数\(y = 4(x + 1) - 5\)写成\(y = kx + b\)的形式,那么\(k =\)____,\(b =\)____.
- 入库答案
- k = 4, b = -9
- 入库解析
- 将 y = 4(x + 1) - 5 展开:y = 4x + 4 - 5 = 4x - 9,对比 y = kx + b 得 k = 4, b = -9.
事件
| 时间 | 阶段 | 级别 | 消息 |
|---|---|---|---|
| 2026-11-10 08:27:34 | PUBLISH | INFO | 已发布 t_question.f_id=44367 qkey=a883ff573beb70bd9db41a75d26d9507 |
| 2026-11-10 08:27:34 | QA | INFO | QA: PASS (score=0.975) |