题目 #184036
- UUID
59e5f32c-3281-48e0-bdb7-82bac96cb33e- 来源
- 青岛版/七上/杜辉Q_18951362233_410.pdf 第 1 页,bbox
[303.07, 460.21, 482.84, 497.28] - 题型 / 学科
- fill_blank / math / JUNIOR
- 知识树
KT_JUNIOR_MATH_STANDARD- 难度
- 难度 3 / 5 中等 · 多步骤
- QA 状态
- PUBLISHED 重试 0 次,得分 0.925
- 最终题 ID
32774
最终题干渲染(f_body 预览)
−\(\frac{2}{5}\) +\(\frac{3}{7} +\) −\(\frac{3}{5}\) = __________
答案 / 解析
答案(f_answer)
-4/7
解析(f_ways)
原式=(-2/5)+3/7+(-3/5),利用加法交换律与结合律,将同分母分数结合:[(-2/5)+(-3/5)]+3/7=(-5/5)+3/7=-1+3/7,再计算得-4/7。
原图与资产(0)
该题没有裁出图片资产
审计记录
| 阶段 | 审计器 | 结果 | 得分 | 依据(简短) |
|---|---|---|---|---|
| STRUCTURE | structure-rule | PASS | 0.900 | |
| FORMULA | formula-auditor | PASS | 1.000 | |
| KNOWLEDGE | knowledge-auditor | WARN | - | |
| SOLVER | blind-solver | PASS | 0.900 | |
| CRITIC | critic | PASS | 0.950 | |
| VISION | vision-auditor | PASS | 0.900 | |
| SYMBOLIC | symbolic-auditor | PASS | 1.000 | |
| COHERENCE | coherence-auditor | FAIL | 0.950 | |
| QUALITY_GATE | quality-gate | FAIL | 0.925 | |
| SOLVER | blind-solver | PASS | 1.000 | |
| CRITIC | critic | PASS | 1.000 | |
| COHERENCE | coherence-auditor | PASS | 1.000 | |
| SYMBOLIC | symbolic-auditor | PASS | 1.000 | |
| AUTO_REPAIR_ATTEMPT | answer-repair | PASS | 0.900 | |
| AUTO_REPAIR | answer-repair | PASS | 0.900 | |
| VISION | vision-auditor | PASS | 0.950 |
知识点(0)
无
正式题库记录(t_question.f_id=32774)
- f_qkey
f4427b6f6ef0697ab8a7ec92c271ac02- f_style / 难度
- 3 / 2
- 入库题干
- −\(\frac{2}{5}\) +\(\frac{3}{7} +\) −\(\frac{3}{5}\) = __________
- 入库答案
- -\(\frac{4}{7}\)
- 入库解析
- 原式 = (-\(\frac{2}{5}\)) +\(\frac{3}{7} + (-\frac{3}{5})\)。先合并同分母项:(-\(\frac{2}{5}\)) + (-\(\frac{3}{5}\)) = -\(\frac{5}{5} = -1\)。再计算 -1 +\(\frac{3}{7} = -\frac{7}{7} + \frac{3}{7} = -\frac{4}{7}\)。
事件
| 时间 | 阶段 | 级别 | 消息 |
|---|---|---|---|
| 2026-11-11 05:34:20 | PUBLISH | INFO | 已发布 t_question.f_id=32774 qkey=f4427b6f6ef0697ab8a7ec92c271ac02 |
| 2026-11-11 05:34:20 | QA | INFO | QA: PASS (score=0.925) |
| 2026-11-11 05:27:10 | HANDOUT | INFO | 注入学案核心知识点背景 179 字 |
| 2026-11-11 05:27:10 | FORMULA | WARN | 公式转换未确认,保留原文本: stem |