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题目 #184087

UUID
b20eefcc-e1c0-448a-9cdd-195c9c57987c
来源
冀教版/八下/薛豪Q_18952688822_455_检测.pdf 第 3 页,bbox [30.22, 203.32, 444.13, 231.97]
题型 / 学科
fill_blank / math / JUNIOR
知识树
KT_JUNIOR_MATH_STANDARD
难度
难度 2 / 5 简单 · 单一知识点
QA 状态
PUBLISHED 重试 0 次,得分 0.975
最终题 ID
53080

最终题干渲染(f_body 预览)

如图, 一次函数\(y_{1}\)=\(k_{1}\)x +\(b_{1}\)(\(k_{1}\),\(b_{1}\)为常数, 且\(k_{1}\)≠0)与\(y_{2}\)=\(k_{2}\)x +\(b_{2}\)(\(k_{2}\),\(b_{2}\)为常 数, 且\(k_{2}\)≠0)相交于点(2, 3), 则关于x的不等式\(k_{1}\)x −\(k_{2}\)x ≥\(b_{2}\)−\(b_{1}\)的解集是 ____.

答案 / 解析

答案(f_answer)

x ≥2

解析(f_ways)

由图象得当x ≥2时,\(y_{1}\)≥\(y_{2}\), 所以\(k_{1}\)x +\(b_{1}\)≥\(k_{2}\)x +\(b_{2}\),\(k_{1}\)x −\(k_{2}\)x ≥\(b_{2}\)−\(b_{1}\),所以 不等式\(k_{1}\)x −\(k_{2}\)x ≥\(b_{2}\)−\(b_{1}\)的解集是x ≥2, 故答案为: x ≥2.

原图与资产(1)

预览类型页source bboxhashURL本地路径
embedded_image3 [30.22, 230.61, 126.68, 303.08] df15ca05fa6287d1…
打开
/www/wwwroot/tikupdfpng.mtwlkj.net_5129/qbank/math/2026/11/a13a92c3-ebda-4a16-b969-9efbd0519d0d/b20eefcc-e1c0-448a-9cdd-195c9c57987c/df15ca05fa62.png

审计记录

阶段审计器结果得分依据(简短)
STRUCTURE structure-rule PASS 0.900
FORMULA formula-auditor PASS 1.000
KNOWLEDGE knowledge-auditor WARN -
SOLVER blind-solver PASS 1.000
CRITIC critic PASS 1.000
VISION vision-auditor PASS 1.000
SYMBOLIC symbolic-auditor PASS 1.000
COHERENCE coherence-auditor PASS 1.000
QUALITY_GATE quality-gate PASS 0.975

知识点(0)

无

正式题库记录(t_question.f_id=53080)

f_qkey
e7757ab3894fb0390497007d776bc2f8
f_style / 难度
3 / 2
入库题干
如图, 一次函数\(y_{1}\)=\(k_{1}\)x +\(b_{1}\)(\(k_{1}\),\(b_{1}\)为常数, 且\(k_{1}\)≠0)与\(y_{2}\)=\(k_{2}\)x +\(b_{2}\)(\(k_{2}\),\(b_{2}\)为常 数, 且\(k_{2}\)≠0)相交于点(2, 3), 则关于x的不等式\(k_{1}\)x −\(k_{2}\)x ≥\(b_{2}\)−\(b_{1}\)的解集是 ____.
入库答案
x ≥2
入库解析
由图象得当x ≥2时,\(y_{1}\)≥\(y_{2}\), 所以\(k_{1}\)x +\(b_{1}\)≥\(k_{2}\)x +\(b_{2}\),\(k_{1}\)x −\(k_{2}\)x ≥\(b_{2}\)−\(b_{1}\),所以 不等式\(k_{1}\)x −\(k_{2}\)x ≥\(b_{2}\)−\(b_{1}\)的解集是x ≥2, 故答案为: x ≥2.

事件

时间阶段级别消息
2026-11-11 05:57:50PUBLISHINFO已发布 t_question.f_id=53080 qkey=e7757ab3894fb0390497007d776bc2f8
2026-11-11 05:57:50QAINFOQA: PASS (score=0.975)
2026-11-11 05:52:46FORMULAWARN公式转换未确认,保留原文本: solution
2026-11-11 05:48:45FORMULAWARN公式转换未确认,保留原文本: stem