题目 #184087
- UUID
b20eefcc-e1c0-448a-9cdd-195c9c57987c- 来源
- 冀教版/八下/薛豪Q_18952688822_455_检测.pdf 第 3 页,bbox
[30.22, 203.32, 444.13, 231.97] - 题型 / 学科
- fill_blank / math / JUNIOR
- 知识树
KT_JUNIOR_MATH_STANDARD- 难度
- 难度 2 / 5 简单 · 单一知识点
- QA 状态
- PUBLISHED 重试 0 次,得分 0.975
- 最终题 ID
53080
最终题干渲染(f_body 预览)
如图, 一次函数\(y_{1}\)=\(k_{1}\)x +\(b_{1}\)(\(k_{1}\),\(b_{1}\)为常数, 且\(k_{1}\)≠0)与\(y_{2}\)=\(k_{2}\)x +\(b_{2}\)(\(k_{2}\),\(b_{2}\)为常 数, 且\(k_{2}\)≠0)相交于点(2, 3), 则关于x的不等式\(k_{1}\)x −\(k_{2}\)x ≥\(b_{2}\)−\(b_{1}\)的解集是 ____.

答案 / 解析
答案(f_answer)
x ≥2
解析(f_ways)
由图象得当x ≥2时,\(y_{1}\)≥\(y_{2}\), 所以\(k_{1}\)x +\(b_{1}\)≥\(k_{2}\)x +\(b_{2}\),\(k_{1}\)x −\(k_{2}\)x ≥\(b_{2}\)−\(b_{1}\),所以 不等式\(k_{1}\)x −\(k_{2}\)x ≥\(b_{2}\)−\(b_{1}\)的解集是x ≥2, 故答案为: x ≥2.
原图与资产(1)
审计记录
| 阶段 | 审计器 | 结果 | 得分 | 依据(简短) |
|---|---|---|---|---|
| STRUCTURE | structure-rule | PASS | 0.900 | |
| FORMULA | formula-auditor | PASS | 1.000 | |
| KNOWLEDGE | knowledge-auditor | WARN | - | |
| SOLVER | blind-solver | PASS | 1.000 | |
| CRITIC | critic | PASS | 1.000 | |
| VISION | vision-auditor | PASS | 1.000 | |
| SYMBOLIC | symbolic-auditor | PASS | 1.000 | |
| COHERENCE | coherence-auditor | PASS | 1.000 | |
| QUALITY_GATE | quality-gate | PASS | 0.975 |
知识点(0)
无
正式题库记录(t_question.f_id=53080)
- f_qkey
e7757ab3894fb0390497007d776bc2f8- f_style / 难度
- 3 / 2
- 入库题干
- 如图, 一次函数\(y_{1}\)=\(k_{1}\)x +\(b_{1}\)(\(k_{1}\),\(b_{1}\)为常数, 且\(k_{1}\)≠0)与\(y_{2}\)=\(k_{2}\)x +\(b_{2}\)(\(k_{2}\),\(b_{2}\)为常 数, 且\(k_{2}\)≠0)相交于点(2, 3), 则关于x的不等式\(k_{1}\)x −\(k_{2}\)x ≥\(b_{2}\)−\(b_{1}\)的解集是 ____.

- 入库答案
- x ≥2
- 入库解析
- 由图象得当x ≥2时,\(y_{1}\)≥\(y_{2}\), 所以\(k_{1}\)x +\(b_{1}\)≥\(k_{2}\)x +\(b_{2}\),\(k_{1}\)x −\(k_{2}\)x ≥\(b_{2}\)−\(b_{1}\),所以 不等式\(k_{1}\)x −\(k_{2}\)x ≥\(b_{2}\)−\(b_{1}\)的解集是x ≥2, 故答案为: x ≥2.
事件
| 时间 | 阶段 | 级别 | 消息 |
|---|---|---|---|
| 2026-11-11 05:57:50 | PUBLISH | INFO | 已发布 t_question.f_id=53080 qkey=e7757ab3894fb0390497007d776bc2f8 |
| 2026-11-11 05:57:50 | QA | INFO | QA: PASS (score=0.975) |
| 2026-11-11 05:52:46 | FORMULA | WARN | 公式转换未确认,保留原文本: solution |
| 2026-11-11 05:48:45 | FORMULA | WARN | 公式转换未确认,保留原文本: stem |