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题目 #19617

UUID
eabccb97-0133-4322-9346-62950a8c02fe
来源
A中考/2026江苏中考期末数学试卷+答案630.pdf 第 1-2 页,bbox [31.3, 782.87, 557.04, 242.13]
题型 / 学科
subjective / math / JUNIOR
知识树
KT_JUNIOR_MATH_STANDARD
难度
难度 2 / 5 简单 · 单一知识点
QA 状态
存疑 / 待修复 缺少答案 公式已降级 重试 0 次,得分 0.900
最终题 ID
-
错误
QA failed: FORMULA,COHERENCE,ANSWER

最终题干渲染(f_body 预览)

2026-06-22 如图,为了测量某电子厂的高度,小明用高1.8m的 测量仪EF测得的仰角为 ,小军在小明的前面\(\frac{45}{CD} 5m\)处用高1.5m的测量仪 测得的仰角为53,求电 子厂AB的高度参考数据:.(sin53\(\frac{4}{5},cos53\)\(\frac{3}{5}\)tan53 \(\frac{4}{3}\))
【典例 1】 【典例 2】

答案 / 解析

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解析(f_ways)

如图延长:DC交 于一点, MEF = EFB =\(\frac{EM}{四边形}\)G  = 90,, MEF =\(\frac{CDF}{EFB} \frac{EFDG}{四边形}\frac{是矩形}{EFBM}\) =  = 90, 是矩形同理得 B CDBN是矩形依题意,得, = =1.8m,frac四边形CD fracEF53 fracMBCG =1.5,AEM = 45,ACN =, = fracmm (− = 0.3, = = 5m, = = frac1.81.5)m fracmFDxm fracEGEM fracCGm fracMNRtAEM 3,设GM =,则 = (+ 5) 在 \(0. \frac{x}{AM}\), tan AEM =\(\frac{AM}{EM}\),EM =1 即AM = (x + 5)m 在Rt ACN,tan ACN =\(\frac{AN}{CN}\),CN tan53 =\(\frac{4}{3}\)x = AN,即AN =, = − AM =\(\frac{4}{3}\)x − (x +4 frac315.9fracxmm fracMNAM fracAN15.9 frac5)AB = 0.3, = = + 5 = 20.9(), =\(\frac{x}{EF} \frac{m}{m}\)AM + = + = + = 22.7().\(\frac{AM}{AB}\frac{MB}{的高度为}\frac{20.91.8}{m}\)答:电子厂 22.7.

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审计记录

阶段审计器结果得分依据(简短)
STRUCTURE structure-rule PASS 0.900
FORMULA formula-auditor FAIL 1.000
KNOWLEDGE knowledge-auditor WARN -
SOLVER blind-solver PASS 0.900
CRITIC critic PASS 0.950
VISION vision-auditor PASS 0.900
SYMBOLIC symbolic-auditor WARN 0.500
COHERENCE coherence-auditor FAIL 0.850
QUALITY_GATE quality-gate FAIL 0.900

知识点(0)

无

事件

时间阶段级别消息
2026-09-24 11:08:24QA_TERMINALWARNquestion terminal status=QUARANTINED: /data/qbank/quarantine/16de2e24-a616-456b-83c5-3364ab6bd928/question_eabccb97-0133-4322-9346-62950a8c02fe.json
2026-09-24 11:08:24QAWARNQA: FAIL (score=0.900)
2026-09-24 11:01:32FORMULAWARN公式转换未确认,保留原文本: solution
2026-09-24 10:57:32FORMULAWARN公式转换未确认,保留原文本: stem