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题目 #20541

UUID
c232db01-3a68-4218-b900-71e5fcfee803
来源
人教版/七下/2026江苏七年级期末数学试卷+答案335.pdf 第 3 页,bbox [30.22, 609.83, 158.04, 653.03]
题型 / 学科
subjective / math / SENIOR
知识树
KT_SENIOR_MATH_STANDARD
难度
难度 2 / 5 简单 · 单一知识点
QA 状态
存疑 / 待修复 重试 0 次,得分 -
最终题 ID
-
错误
处理异常: LLM call failed after retries: HTTPConnectionPool(host='127.0.0.1', port=8091): Read timed out. (read timeout=120) [endpoints: http://127.0.0.1:8092/v1 -> http://127.0.0.1:8091/v1]

最终题干渲染(f_body 预览)

求下列各式中\(x\)的值:\(16x^{2}+ 2 = 11\);\(rac{(1)}{(2)} 2(2x -1)^{2}-50 = 0\).

答案 / 解析

答案(f_answer)

\(\frac{9}{16}\)直接开方得,\(x_{1}\)= −\(\frac{3}{4}x_{2}\)=\(\frac{3}{4}\).

解析(f_ways)

\(16x^{2}\)+ 2 = 11,移项、合并同类项得,\(16x^{2}\)= 9,\(x^{2}\)=\(\frac{(1)}{(2)} \frac{所以}{所以} 2(2x −1)^{2}−50 = 0\),移项得,2(2x −1)^{2}= 50, (2x −1)^{2}= 25, 直接方法得,2x −1 = 5或2x −1 = −5,所以\(x_{1}\)= 3,\(x_{2}\)= −2.

原图与资产(0)

该题没有裁出图片资产

审计记录

阶段审计器结果得分依据(简短)
STRUCTURE structure-auditor PASS 0.950
FORMULA formula-auditor PASS 1.000
KNOWLEDGE knowledge-auditor WARN -
VISION vision-auditor PASS 0.950
SOLVER blind-solver PASS 1.000
CRITIC critic PASS 1.000
SYMBOLIC symbolic-auditor WARN 0.550

知识点(0)

无

事件

时间阶段级别消息
2026-09-24 18:30:57ERRORERROR处理异常: LLM call failed after retries: HTTPConnectionPool(host='127.0.0.1', port=8091): Read timed out. (read timeout=120) [endpoints: http://127.0.0.1:8092/v1 -> http://127.0.0.1:8091/v1]
2026-09-24 18:26:03FORMULAWARN公式转换未确认,保留原文本: solution
2026-09-24 18:22:02FORMULAWARN公式转换未确认,保留原文本: answer