题目 #21544
- UUID
d253da3f-0b56-41f0-aef0-418d75223d71- 来源
- 人教版/七下/2026江苏七年级期末数学试卷+答案440.pdf 第 3 页,bbox
[30.0, 119.79, 277.37, 133.24] - 题型 / 学科
- fill_blank / math / JUNIOR
- 知识树
KT_JUNIOR_MATH_STANDARD- 难度
- 难度 2 / 5 简单 · 单一知识点
- QA 状态
- PUBLISHED 重试 0 次,得分 0.925
- 最终题 ID
10065
最终题干渲染(f_body 预览)
已知\(|2x - \sqrt{3}| = \sqrt{2}\),则实数\(x\)的值为____
答案 / 解析
答案(f_answer)
x =\(\frac{\sqrt{3} + \sqrt{2}}{2}\)或 x =\(\frac{\sqrt{3} - \sqrt{2}}{2}\)
解析(f_ways)
由 |2x -\(\sqrt{3}| = \sqrt{2}\)得 2x -\(\sqrt{3} = \sqrt{2}\)或 2x -\(\sqrt{3} = -\sqrt{2}\)。
情形一:2x -\(\sqrt{3} = \sqrt{2} \Rightarrow 2x = \sqrt{3} + \sqrt{2} \Rightarrow\)x =\(\frac{\sqrt{3} + \sqrt{2}}{2}\)。
情形二:2x -\(\sqrt{3} = -\sqrt{2} \Rightarrow 2x = \sqrt{3} - \sqrt{2} \Rightarrow\)x =\(\frac{\sqrt{3} - \sqrt{2}}{2}\)。
经检验,两解均满足原方程。故实数 x 的值为\(\frac{\sqrt{3} + \sqrt{2}}{2}\)或\(\frac{\sqrt{3} - \sqrt{2}}{2}\)。
原图与资产(0)
该题没有裁出图片资产
审计记录
| 阶段 | 审计器 | 结果 | 得分 | 依据(简短) |
|---|---|---|---|---|
| STRUCTURE | structure-rule | PASS | 0.900 | |
| FORMULA | formula-auditor | PASS | 1.000 | |
| KNOWLEDGE | knowledge-auditor | WARN | - | |
| VISION | vision-auditor | PASS | 0.900 | |
| SOLVER | blind-solver | PASS | 1.000 | |
| CRITIC | critic | PASS | 1.000 | |
| SYMBOLIC | symbolic-auditor | WARN | 0.500 | |
| COHERENCE | coherence-auditor | FAIL | 0.900 | |
| QUALITY_GATE | quality-gate | FAIL | 0.925 | |
| SOLVER | blind-solver | PASS | 1.000 | |
| CRITIC | critic | PASS | 1.000 | |
| COHERENCE | coherence-auditor | PASS | 1.000 | |
| SYMBOLIC | symbolic-auditor | WARN | 0.550 | |
| AUTO_REPAIR_ATTEMPT | answer-repair | PASS | 1.000 | |
| AUTO_REPAIR | answer-repair | PASS | 1.000 | |
| VISION | vision-auditor | PASS | 1.000 |
知识点(0)
无
正式题库记录(t_question.f_id=10065)
- f_qkey
3c014ee681b648daff33802769856102- f_style / 难度
- 3 / 2
- 入库题干
- 已知\(|2x - \sqrt{3}| = \sqrt{2}\),则实数\(x\)的值为____
- 入库答案
- x =\(\frac{\sqrt{3} + \sqrt{2}}{2}\)或 x =\(\frac{\sqrt{3} - \sqrt{2}}{2}\)
- 入库解析
- 由 |2x -\(\sqrt{3}| = \sqrt{2}\)得 2x -\(\sqrt{3} = \sqrt{2}\)或 2x -\(\sqrt{3} = -\sqrt{2}\)。 情形一:2x -\(\sqrt{3} = \sqrt{2} \Rightarrow 2x = \sqrt{3} + \sqrt{2} \Rightarrow\)x =\(\frac{\sqrt{3} + \sqrt{2}}{2}\)。 情形二:2x -\(\sqrt{3} = -\sqrt{2} \Rightarrow 2x = \sqrt{3} - \sqrt{2} \Rightarrow\)x =\(\frac{\sqrt{3} - \sqrt{2}}{2}\)。 经检验,两解均满足原方程。故实数 x 的值为\(\frac{\sqrt{3} + \sqrt{2}}{2}\)或\(\frac{\sqrt{3} - \sqrt{2}}{2}\)。
事件
| 时间 | 阶段 | 级别 | 消息 |
|---|---|---|---|
| 2026-09-25 02:01:16 | PUBLISH | INFO | 已发布 t_question.f_id=10065 qkey=3c014ee681b648daff33802769856102 |
| 2026-09-25 02:01:16 | QA | INFO | QA: PASS (score=0.925) |