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题目 #22719

UUID
0d462335-d744-4d46-8f33-d43184448da7
来源
人教版/七下/2026江苏七年级期末数学试卷+答案735.pdf 第 3 页,bbox [30.22, 438.09, 369.37, 465.67]
题型 / 学科
fill_blank / math / SENIOR
知识树
KT_SENIOR_MATH_STANDARD
难度
难度 2 / 5 简单 · 单一知识点
QA 状态
PUBLISHED 重试 0 次,得分 0.963
最终题 ID
10543

最终题干渲染(f_body 预览)

在平面直角坐标系中,点\(A_{1}(1, 2)\),\(A_{2}(2, 5)\),\(A_{3}(3, 10)\),\(A_{4}(4, 17)\), … ,用你发现的规律确定点\(A_{n}\)的坐标为____.

答案 / 解析

答案(f_answer)

(n,\(n^{2}\)+ 1)

解析(f_ways)

设\(A_{n}(x, y)\).∵当\(n = 1\)时,\(A_{1}(1, 2)\),即\(x = 1\),\(y = 1^{2}+ 1\);当\(n = 2\)时,\(A_{2}(2, 5)\),即\(x = 2\),\(y = 2^{2}+ 1\);当\(n = 3\)时,\(A_{3}(3, 10)\),即\(x = 3\),\(y = 3^{2}+ 1\);当\(n = 4\)时,\(A_{4}(4, 17)\),即\(x = 4\),\(y = 4^{2}+ 1\);... ∴当\(n = n\)时,\(x = n\),\(y = n^{2}+ 1\).故答案为:\((n, n^{2}+ 1)\).

原图与资产(0)

该题没有裁出图片资产

审计记录

阶段审计器结果得分依据(简短)
STRUCTURE structure-rule PASS 0.900
FORMULA formula-auditor PASS 1.000
KNOWLEDGE knowledge-auditor WARN -
VISION vision-auditor PASS 0.950
SOLVER blind-solver PASS 1.000
CRITIC critic PASS 1.000
SYMBOLIC symbolic-auditor WARN 0.550
COHERENCE coherence-auditor PASS 1.000
QUALITY_GATE quality-gate PASS 0.963

知识点(0)

无

正式题库记录(t_question.f_id=10543)

f_qkey
fccc35fa5eaffc5e8da9c62e888bebc9
f_style / 难度
3 / 2
入库题干
在平面直角坐标系中,点\(A_{1}(1, 2)\),\(A_{2}(2, 5)\),\(A_{3}(3, 10)\),\(A_{4}(4, 17)\), … ,用你发现的规律确定点\(A_{n}\)的坐标为____.
入库答案
(n,\(n^{2}\)+ 1)
入库解析
设\(A_{n}(x, y)\).∵当\(n = 1\)时,\(A_{1}(1, 2)\),即\(x = 1\),\(y = 1^{2}+ 1\);当\(n = 2\)时,\(A_{2}(2, 5)\),即\(x = 2\),\(y = 2^{2}+ 1\);当\(n = 3\)时,\(A_{3}(3, 10)\),即\(x = 3\),\(y = 3^{2}+ 1\);当\(n = 4\)时,\(A_{4}(4, 17)\),即\(x = 4\),\(y = 4^{2}+ 1\);... ∴当\(n = n\)时,\(x = n\),\(y = n^{2}+ 1\).故答案为:\((n, n^{2}+ 1)\).

事件

时间阶段级别消息
2026-09-25 09:49:14PUBLISHINFO已发布 t_question.f_id=10543 qkey=fccc35fa5eaffc5e8da9c62e888bebc9
2026-09-25 09:49:14QAINFOQA: PASS (score=0.963)