题目 #22719
- UUID
0d462335-d744-4d46-8f33-d43184448da7- 来源
- 人教版/七下/2026江苏七年级期末数学试卷+答案735.pdf 第 3 页,bbox
[30.22, 438.09, 369.37, 465.67] - 题型 / 学科
- fill_blank / math / SENIOR
- 知识树
KT_SENIOR_MATH_STANDARD- 难度
- 难度 2 / 5 简单 · 单一知识点
- QA 状态
- PUBLISHED 重试 0 次,得分 0.963
- 最终题 ID
10543
最终题干渲染(f_body 预览)
在平面直角坐标系中,点\(A_{1}(1, 2)\),\(A_{2}(2, 5)\),\(A_{3}(3, 10)\),\(A_{4}(4, 17)\), … ,用你发现的规律确定点\(A_{n}\)的坐标为____.
答案 / 解析
答案(f_answer)
(n,\(n^{2}\)+ 1)
解析(f_ways)
设\(A_{n}(x, y)\).∵当\(n = 1\)时,\(A_{1}(1, 2)\),即\(x = 1\),\(y = 1^{2}+ 1\);当\(n = 2\)时,\(A_{2}(2, 5)\),即\(x = 2\),\(y = 2^{2}+ 1\);当\(n = 3\)时,\(A_{3}(3, 10)\),即\(x = 3\),\(y = 3^{2}+ 1\);当\(n = 4\)时,\(A_{4}(4, 17)\),即\(x = 4\),\(y = 4^{2}+ 1\);... ∴当\(n = n\)时,\(x = n\),\(y = n^{2}+ 1\).故答案为:\((n, n^{2}+ 1)\).
原图与资产(0)
该题没有裁出图片资产
审计记录
| 阶段 | 审计器 | 结果 | 得分 | 依据(简短) |
|---|---|---|---|---|
| STRUCTURE | structure-rule | PASS | 0.900 | |
| FORMULA | formula-auditor | PASS | 1.000 | |
| KNOWLEDGE | knowledge-auditor | WARN | - | |
| VISION | vision-auditor | PASS | 0.950 | |
| SOLVER | blind-solver | PASS | 1.000 | |
| CRITIC | critic | PASS | 1.000 | |
| SYMBOLIC | symbolic-auditor | WARN | 0.550 | |
| COHERENCE | coherence-auditor | PASS | 1.000 | |
| QUALITY_GATE | quality-gate | PASS | 0.963 |
知识点(0)
无
正式题库记录(t_question.f_id=10543)
- f_qkey
fccc35fa5eaffc5e8da9c62e888bebc9- f_style / 难度
- 3 / 2
- 入库题干
- 在平面直角坐标系中,点\(A_{1}(1, 2)\),\(A_{2}(2, 5)\),\(A_{3}(3, 10)\),\(A_{4}(4, 17)\), … ,用你发现的规律确定点\(A_{n}\)的坐标为____.
- 入库答案
- (n,\(n^{2}\)+ 1)
- 入库解析
- 设\(A_{n}(x, y)\).∵当\(n = 1\)时,\(A_{1}(1, 2)\),即\(x = 1\),\(y = 1^{2}+ 1\);当\(n = 2\)时,\(A_{2}(2, 5)\),即\(x = 2\),\(y = 2^{2}+ 1\);当\(n = 3\)时,\(A_{3}(3, 10)\),即\(x = 3\),\(y = 3^{2}+ 1\);当\(n = 4\)时,\(A_{4}(4, 17)\),即\(x = 4\),\(y = 4^{2}+ 1\);... ∴当\(n = n\)时,\(x = n\),\(y = n^{2}+ 1\).故答案为:\((n, n^{2}+ 1)\).
事件
| 时间 | 阶段 | 级别 | 消息 |
|---|---|---|---|
| 2026-09-25 09:49:14 | PUBLISH | INFO | 已发布 t_question.f_id=10543 qkey=fccc35fa5eaffc5e8da9c62e888bebc9 |
| 2026-09-25 09:49:14 | QA | INFO | QA: PASS (score=0.963) |