题目 #23034
- UUID
dbac9af3-f8ba-4bc2-b1f4-2f79b0b04997- 来源
- 人教版/七下/2026江苏七年级期末数学试卷+答案930.pdf 第 4 页,bbox
[30.0, 283.98, 236.45, 310.51] - 题型 / 学科
- subjective / math / SENIOR
- 知识树
KT_SENIOR_MATH_STANDARD- 难度
- 难度 1 / 5 最简单 · 识记/直接套公式
- QA 状态
- PUBLISHED 重试 0 次,得分 0.925
- 最终题 ID
10655
最终题干渲染(f_body 预览)
解代入法解下列方程组{ 2x −y = 3 3x + 2y = 8
答案 / 解析
答案(f_answer)
x=2, y=1
解析(f_ways)
由方程2x - y = 3得y = 2x - 3。将其代入方程3x + 2y = 8,得3x + 2(2x - 3) = 8,即3x + 4x - 6 = 8,解得7x = 14,x = 2。将x = 2代入y = 2x - 3,得y =\(2\times 2 - 3 = 1\)。因此,方程组的解为x = 2,y = 1。
原图与资产(0)
该题没有裁出图片资产
审计记录
| 阶段 | 审计器 | 结果 | 得分 | 依据(简短) |
|---|---|---|---|---|
| STRUCTURE | structure-auditor | PASS | 1.000 | |
| FORMULA | formula-auditor | PASS | 1.000 | |
| KNOWLEDGE | knowledge-auditor | WARN | - | |
| VISION | vision-auditor | PASS | 0.800 | |
| SOLVER | blind-solver | PASS | 1.000 | |
| CRITIC | critic | PASS | 1.000 | |
| SYMBOLIC | symbolic-auditor | WARN | 0.500 | |
| COHERENCE | coherence-auditor | FAIL | 0.900 | |
| QUALITY_GATE | quality-gate | FAIL | 0.925 | |
| SOLVER | blind-solver | PASS | 1.000 | |
| CRITIC | critic | PASS | 1.000 | |
| COHERENCE | coherence-auditor | PASS | 1.000 | |
| SYMBOLIC | symbolic-auditor | PASS | 1.000 | |
| AUTO_REPAIR_ATTEMPT | answer-repair | PASS | 1.000 | |
| AUTO_REPAIR | answer-repair | PASS | 1.000 | |
| VISION | vision-auditor | PASS | 0.950 |
知识点(0)
无
正式题库记录(t_question.f_id=10655)
- f_qkey
05e1f5231e180708bb70b51fa25966c7- f_style / 难度
- 5 / 2
- 入库题干
- 解代入法解下列方程组{ 2x −y = 3 3x + 2y = 8
- 入库答案
- x=2, y=1
- 入库解析
- 由方程2x - y = 3得y = 2x - 3。将其代入方程3x + 2y = 8,得3x + 2(2x - 3) = 8,即3x + 4x - 6 = 8,解得7x = 14,x = 2。将x = 2代入y = 2x - 3,得y =\(2\times 2 - 3 = 1\)。因此,方程组的解为x = 2,y = 1。
事件
| 时间 | 阶段 | 级别 | 消息 |
|---|---|---|---|
| 2026-09-25 12:33:01 | PUBLISH | INFO | 已发布 t_question.f_id=10655 qkey=05e1f5231e180708bb70b51fa25966c7 |
| 2026-09-25 12:33:01 | QA | INFO | QA: PASS (score=0.925) |
| 2026-09-25 12:30:26 | FORMULA | WARN | 公式转换未确认,保留原文本: stem |