题目 #24146
- UUID
eaef70a5-7ee9-4d86-b4ba-6eb1f9e74a95- 来源
- 人教版/九上/2026江苏九年级期中数学试卷+答案1160.pdf 第 2 页,bbox
[31.56, 673.65, 458.86, 718.92] - 题型 / 学科
- fill_blank / math / JUNIOR
- 知识树
KT_JUNIOR_MATH_STANDARD- 难度
- 难度 1 / 5 最简单 · 识记/直接套公式
- QA 状态
- PUBLISHED 重试 0 次,得分 0.900
- 最终题 ID
11170
最终题干渲染(f_body 预览)
【小试2】如图, AB为⊙O的直径, 点C、D是BE的三等分点, ∠AOE = 60°, 则∠BOD的度数为____.
答案 / 解析
答案(f_answer)
20°
解析(f_ways)
因为AB是⊙O的直径,所以∠AOB = 180°。已知∠AOE = 60°,所以∠BOE = ∠AOB - ∠AOE = 180° - 60° = 120°。点C、D是BE的三等分点,所以∠BOC = ∠COD = ∠DOE = ∠BOE / 3 = 120° / 3 = 40°。因此,∠BOD = ∠BOC + ∠COD = 40° + 40° = 80°。
原图与资产(0)
该题没有裁出图片资产
审计记录
| 阶段 | 审计器 | 结果 | 得分 | 依据(简短) |
|---|---|---|---|---|
| STRUCTURE | structure-rule | PASS | 0.900 | |
| FORMULA | formula-auditor | PASS | 1.000 | |
| KNOWLEDGE | knowledge-auditor | WARN | - | |
| VISION | vision-auditor | PASS | 0.900 | |
| SOLVER | blind-solver | PASS | 0.900 | |
| CRITIC | critic | PASS | 1.000 | |
| SYMBOLIC | symbolic-auditor | WARN | 0.500 | |
| COHERENCE | coherence-auditor | FAIL | 0.800 | |
| QUALITY_GATE | quality-gate | FAIL | 0.900 | |
| SOLVER | blind-solver | PASS | 0.800 | |
| CRITIC | critic | PASS | 1.000 | |
| COHERENCE | coherence-auditor | PASS | 0.950 | |
| SYMBOLIC | symbolic-auditor | PASS | 1.000 | |
| AUTO_REPAIR_ATTEMPT | answer-repair | PASS | 0.900 | |
| AUTO_REPAIR | answer-repair | PASS | 0.900 | |
| VISION | vision-auditor | PASS | 0.900 |
知识点(0)
无
正式题库记录(t_question.f_id=11170)
- f_qkey
54d092c1c4747200af84171767721fa2- f_style / 难度
- 3 / 2
- 入库题干
- 【小试2】如图, AB为⊙O的直径, 点C、D是BE的三等分点, ∠AOE = 60°, 则∠BOD的度数为____.
- 入库答案
- 20°
- 入库解析
- 因为AB是⊙O的直径,所以∠AOB = 180°。已知∠AOE = 60°,所以∠BOE = ∠AOB - ∠AOE = 180° - 60° = 120°。点C、D是BE的三等分点,所以∠BOC = ∠COD = ∠DOE = ∠BOE / 3 = 120° / 3 = 40°。因此,∠BOD = ∠BOC + ∠COD = 40° + 40° = 80°。
事件
| 时间 | 阶段 | 级别 | 消息 |
|---|---|---|---|
| 2026-09-25 22:35:43 | PUBLISH | INFO | 已发布 t_question.f_id=11170 qkey=54d092c1c4747200af84171767721fa2 |
| 2026-09-25 22:35:43 | QA | INFO | QA: PASS (score=0.900) |