题目 #24296
- UUID
cbf46dad-d3ae-4f4a-9368-5fd9305a16b2- 来源
- 人教版/九上/2026江苏九年级期中数学试卷+答案1185.pdf 第 3 页，bbox
[31.56, 429.42, 406.63, 700.08] - 题型 / 学科
- single_choice / math / JUNIOR
- 知识树
KT_JUNIOR_MATH_STANDARD- 难度
- 难度 2 / 5 简单 · 单一知识点
- QA 状态
- PUBLISHED 重试 0 次，得分 0.950
- 最终题 ID
11236
最终题干渲染（f_body 预览）
[小试2] 如图，AB、AC是⊙O的两条弦，OD⊥AB于点D，OE⊥AC于点E，连结OB、OC．若∠DOE=140°，则∠BOC的度数为( ).
A. 70°
B. 80°
C. 90°
D. 100°
A. 70°
B. 80°
C. 90°
D. 100°
答案 / 解析
答案（f_answer）
B
解析（f_ways）
因为OD\(\perp\)AB, OE\(\perp\)AC, \therefore\(\angle\)ADO = 90^{\(\circ\)},\(\angle\)AEO = 90^{\(\circ\)}, \because\(\angle\)DOE=140^{\(\circ\)}, \therefore\(\angle\)BAC = 360^{\(\circ\)} -\(\angle\)ADO -\(\angle\)AEO -\(\angle\)DOE = 360^{\(\circ\)} - 90^{\(\circ\)} - 90^{\(\circ\)} - 140^{\(\circ\)} = 40^{\(\circ\)}, \because\(\angle\)BOC =\(2\angle\)BAC, \therefore\(\angle\)BOC = 80^{\(\circ\)}，故选：B．
原图与资产（2）
| 预览 | 类型 | 页 | source bbox | hash | URL | 本地路径 |
|---|---|---|---|---|---|---|
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embedded_image | 3 | [31.5, 474.08, 173.19, 607.43] |
9eebee0c397023ab… |
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embedded_image | 3 | [30.0, 718.25, 71.19, 754.2] |
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审计记录
| 阶段 | 审计器 | 结果 | 得分 | 依据（简短） |
|---|---|---|---|---|
| STRUCTURE | structure-rule | PASS | 0.900 | |
| FORMULA | formula-auditor | PASS | 1.000 | |
| KNOWLEDGE | knowledge-auditor | WARN | - | |
| SOLVER | blind-solver | PASS | 1.000 | |
| CRITIC | critic | PASS | 1.000 | |
| VISION | vision-auditor | PASS | 1.000 | |
| SYMBOLIC | symbolic-auditor | PASS | 1.000 | |
| COHERENCE | coherence-auditor | PASS | 0.900 | |
| QUALITY_GATE | quality-gate | PASS | 0.950 |
知识点（0）
无
正式题库记录（t_question.f_id=11236）
- f_qkey
494d3efaa02495cda579f00a012d790f- f_style / 难度
- 1 / 2
- 入库题干
- [小试2] 如图，AB、AC是⊙O的两条弦，OD⊥AB于点D，OE⊥AC于点E，连结OB、OC．若∠DOE=140°，则∠BOC的度数为( ).
A. 70°
B. 80°
C. 90°
D. 100° - 入库答案
- B
- 入库解析
- 因为OD\(\perp\)AB, OE\(\perp\)AC, \therefore\(\angle\)ADO = 90^{\(\circ\)},\(\angle\)AEO = 90^{\(\circ\)}, \because\(\angle\)DOE=140^{\(\circ\)}, \therefore\(\angle\)BAC = 360^{\(\circ\)} -\(\angle\)ADO -\(\angle\)AEO -\(\angle\)DOE = 360^{\(\circ\)} - 90^{\(\circ\)} - 90^{\(\circ\)} - 140^{\(\circ\)} = 40^{\(\circ\)}, \because\(\angle\)BOC =\(2\angle\)BAC, \therefore\(\angle\)BOC = 80^{\(\circ\)}，故选：B．
事件
| 时间 | 阶段 | 级别 | 消息 |
|---|---|---|---|
| 2026-09-25 23:39:30 | PUBLISH | INFO | 已发布 t_question.f_id=11236 qkey=494d3efaa02495cda579f00a012d790f |
| 2026-09-25 23:39:30 | QA | INFO | QA: PASS (score=0.950) |