题目 #24335
- UUID
dea38778-416e-47fd-ae7a-018367ca6bae- 来源
- 人教版/九上/2026江苏九年级期中数学试卷+答案1195.pdf 第 1 页,bbox
[30.22, 535.57, 392.8, 726.52] - 题型 / 学科
- single_choice / math / JUNIOR
- 知识树
KT_JUNIOR_MATH_STANDARD- 难度
- 难度 3 / 5 中等 · 多步骤
- QA 状态
- PUBLISHED 重试 0 次,得分 0.975
- 最终题 ID
11257
最终题干渲染(f_body 预览)
如图所示,在\(\odot O\)中,弦\(CD\)与直径\(AB\)相交于点\(E\),连接 \(OC, BD\).若\(\angle ABD = 25^\circ\),\(\angle AED = 80^\circ\),则\(\angle COB\)的度数为( ).
A. 80°
B. 100°
C. 110°
D. 120°

A. 80°
B. 100°
C. 110°
D. 120°
答案 / 解析
答案(f_answer)
C
解析(f_ways)
因为\(\angle AED\)是\(\triangle BDE\)的外角,\(\therefore \angle AED= \angle ABD+ \angle BDE\therefore \angle BDE= \angle AED-\angle ABD= 80^{\circ} -25^{\circ} = 55^{\circ}\therefore \angle COB= 2\angle D= 55^{\circ} \times 2 = 110^{\circ}\).故选:C.
原图与资产(1)
审计记录
| 阶段 | 审计器 | 结果 | 得分 | 依据(简短) |
|---|---|---|---|---|
| STRUCTURE | structure-rule | PASS | 0.900 | |
| FORMULA | formula-auditor | PASS | 1.000 | |
| KNOWLEDGE | knowledge-auditor | WARN | - | |
| VISION | vision-auditor | PASS | 1.000 | |
| SOLVER | blind-solver | PASS | 0.900 | |
| CRITIC | critic | PASS | 1.000 | |
| SYMBOLIC | symbolic-auditor | PASS | 1.000 | |
| COHERENCE | coherence-auditor | PASS | 1.000 | |
| QUALITY_GATE | quality-gate | PASS | 0.975 |
知识点(0)
无
正式题库记录(t_question.f_id=11257)
- f_qkey
21fd5489f184218ab5cc670c3f2271d3- f_style / 难度
- 1 / 2
- 入库题干
- 如图所示,在\(\odot O\)中,弦\(CD\)与直径\(AB\)相交于点\(E\),连接 \(OC, BD\).若\(\angle ABD = 25^\circ\),\(\angle AED = 80^\circ\),则\(\angle COB\)的度数为( ).

A. 80°
B. 100°
C. 110°
D. 120° - 入库答案
- C
- 入库解析
- 因为\(\angle AED\)是\(\triangle BDE\)的外角,\(\therefore \angle AED= \angle ABD+ \angle BDE\therefore \angle BDE= \angle AED-\angle ABD= 80^{\circ} -25^{\circ} = 55^{\circ}\therefore \angle COB= 2\angle D= 55^{\circ} \times 2 = 110^{\circ}\).故选:C.
事件
| 时间 | 阶段 | 级别 | 消息 |
|---|---|---|---|
| 2026-09-26 00:00:00 | PUBLISH | INFO | 已发布 t_question.f_id=11257 qkey=21fd5489f184218ab5cc670c3f2271d3 |
| 2026-09-26 00:00:00 | QA | INFO | QA: PASS (score=0.975) |