题目 #24336
- UUID
b71a939b-31b0-48e5-9a2d-1d810ae22eed- 来源
- 人教版/九上/2026江苏九年级期中数学试卷+答案1195.pdf 第 2 页,bbox
[30.22, 103.28, 339.59, 284.54] - 题型 / 学科
- single_choice / math / JUNIOR
- 知识树
KT_JUNIOR_MATH_STANDARD- 难度
- 难度 2 / 5 简单 · 单一知识点
- QA 状态
- PUBLISHED 重试 0 次,得分 0.938
- 最终题 ID
11259
最终题干渲染(f_body 预览)
如图所示.\(AB\)是\(\odot O\)的直径,\(\angle D= 40^{\circ}\),则\(\angle BOC =\)( ).
A. 80°
B. 100°
C. 120°
D. 140°

A. 80°
B. 100°
C. 120°
D. 140°
答案 / 解析
答案(f_answer)
B
解析(f_ways)
因为AB是⊙O的直径,所以∠AOB = 180°。又因为∠D = 40°,根据圆周角定理,∠AOC = 2∠D = 80°。因此,∠BOC = ∠AOB - ∠AOC = 180° - 80° = 100°。故选:B。
原图与资产(1)
审计记录
| 阶段 | 审计器 | 结果 | 得分 | 依据(简短) |
|---|---|---|---|---|
| STRUCTURE | structure-rule | PASS | 0.900 | |
| FORMULA | formula-auditor | PASS | 1.000 | |
| KNOWLEDGE | knowledge-auditor | WARN | - | |
| VISION | vision-auditor | PASS | 0.950 | |
| SOLVER | blind-solver | PASS | 1.000 | |
| CRITIC | critic | PASS | 1.000 | |
| SYMBOLIC | symbolic-auditor | PASS | 1.000 | |
| COHERENCE | coherence-auditor | FAIL | 0.900 | |
| QUALITY_GATE | quality-gate | FAIL | 0.938 | |
| SOLVER | blind-solver | PASS | 0.800 | |
| CRITIC | critic | PASS | 1.000 | |
| COHERENCE | coherence-auditor | PASS | 1.000 | |
| SYMBOLIC | symbolic-auditor | PASS | 1.000 | |
| AUTO_REPAIR_ATTEMPT | answer-repair | PASS | 1.000 | |
| AUTO_REPAIR | answer-repair | PASS | 1.000 | |
| VISION | vision-auditor | PASS | 1.000 |
知识点(0)
无
正式题库记录(t_question.f_id=11259)
- f_qkey
0b9534a777d59a8fe65a532facd4ef57- f_style / 难度
- 1 / 2
- 入库题干
- 如图所示.\(AB\)是\(\odot O\)的直径,\(\angle D= 40^{\circ}\),则\(\angle BOC =\)( ).

A. 80°
B. 100°
C. 120°
D. 140° - 入库答案
- B
- 入库解析
- 因为AB是⊙O的直径,所以∠AOB = 180°。又因为∠D = 40°,根据圆周角定理,∠AOC = 2∠D = 80°。因此,∠BOC = ∠AOB - ∠AOC = 180° - 80° = 100°。故选:B。
事件
| 时间 | 阶段 | 级别 | 消息 |
|---|---|---|---|
| 2026-09-26 00:02:32 | PUBLISH | INFO | 已发布 t_question.f_id=11259 qkey=0b9534a777d59a8fe65a532facd4ef57 |
| 2026-09-26 00:02:32 | QA | INFO | QA: PASS (score=0.938) |