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题目 #24474

UUID
db8c2fbb-d844-4fc2-af3f-4bb8fd872d04
来源
人教版/九上/2026江苏九年级期中数学试卷+答案1210.pdf 第 3 页,bbox [31.56, 340.6, 397.15, 415.63]
题型 / 学科
comprehensive / math / SENIOR
知识树
KT_SENIOR_MATH_STANDARD
难度
难度 2 / 5 简单 · 单一知识点
QA 状态
存疑 / 待修复 重试 0 次,得分 0.950
最终题 ID
-
错误
QA failed: COHERENCE,ANSWER

最终题干渲染(f_body 预览)

【小试1】 如图,AB是半圆O的直径,C、D是半圆O上的两点,且OD ∥BC,有 OD与AC交于点E.
(1)若\(\angle B = 70^{\circ}\),求\(\angle CAD\)的度数;
(2)若AB = 4, AC = 3,求DE的长.

答案 / 解析

答案(f_answer)

(1)35^\(\circ\);(2)2-\(\frac{\sqrt{7}}{2}.\)

解析(f_ways)

(1)∵AB是半圆O的直径,∴∠ACB = 90∘, 又∵OD ∥BC, ∴∠AEO=90∘,即OE ⊥AC. ∵∠B = 70∘, ∴ ∠CAB = 90∘−∠B = 90∘−70∘=20∘, ∵OA = OD, ∴∠DAO = ∠ADO = 55∘,∴∠CAD=∠DAO −∠CAB = 55∘−20∘= 35∘; (2)在Rt △ABC中, BC =\(\sqrt{AB^{2}}\)−\(AC^{2}\)=\(\sqrt{4^{2}}\)−\(3^{2}\)= √7 ∵OE ⊥AC,所以AE = EC,又∵OA = OB,∴ OE = _{2}BC =\(\sqrt{7_{2}}\).又∵OD = _{2}AB=2, ∴DE = OD −OE = 2 −\(\sqrt{7_{2}}\). 1 1

原图与资产(1)

预览类型页source bboxhashURL本地路径
embedded_image3 [31.5, 416.41, 173.17, 507.96] 553babc3e316a65d…
打开
/www/wwwroot/tikupdfpng.mtwlkj.net_5129/qbank/math/2026/09/2b06312b-7e3f-494e-ae3e-21d10207fcf7/db8c2fbb-d844-4fc2-af3f-4bb8fd872d04/553babc3e316.png

审计记录

阶段审计器结果得分依据(简短)
STRUCTURE structure-rule PASS 0.900
FORMULA formula-auditor PASS 1.000
KNOWLEDGE knowledge-auditor WARN -
VISION vision-auditor PASS 0.950
SOLVER blind-solver PASS 1.000
CRITIC critic PASS 1.000
SYMBOLIC symbolic-auditor WARN 0.550
COHERENCE coherence-auditor FAIL 0.950
QUALITY_GATE quality-gate FAIL 0.950
SOLVER blind-solver WARN 0.400
CRITIC critic WARN 0.500
AUTO_REPAIR_ATTEMPT answer-repair FAIL 0.500

知识点(0)

无

事件

时间阶段级别消息
2026-09-26 01:14:51QA_TERMINALWARNquestion terminal status=QUARANTINED: /data/qbank/quarantine/2b06312b-7e3f-494e-ae3e-21d10207fcf7/question_db8c2fbb-d844-4fc2-af3f-4bb8fd872d04.json
2026-09-26 01:14:51QAWARNQA: FAIL (score=0.950)
2026-09-26 01:07:09FORMULAWARN公式转换未确认,保留原文本: solution
2026-09-26 01:02:12FORMULAWARN公式转换未确认,保留原文本: sub_2