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题目 #24723

UUID
7fafbdcb-7f00-47ed-9fcf-1a7b110a01ee
来源
人教版/九上/2026江苏九年级期中数学试卷+答案130.pdf 第 2-3 页,bbox [31.56, 792.35, 157.58, 177.52]
题型 / 学科
comprehensive / math / JUNIOR
知识树
KT_JUNIOR_MATH_STANDARD
难度
难度 2 / 5 简单 · 单一知识点
QA 状态
存疑 / 待修复 重试 0 次,得分 -
最终题 ID
-
错误
处理异常: LLM call failed after retries: HTTPConnectionPool(host='127.0.0.1', port=8091): Read timed out. (read timeout=120) [endpoints: http://127.0.0.1:8092/v1 -> http://127.0.0.1:8091/v1]

最终题干渲染(f_body 预览)

用公式法解下列方程:
(1)^\({3}_{2}x^{2}\)+ 4x −1 = 0;
(2)\(6x^{2}\)−4 = 3x;
(3)\(3x^{2}\)+ 6x −1 = 0.

答案 / 解析

答案(f_answer)

(1)\(x_{1}\)= 3,\(x_{2}\)= 3 (2)\(x_{1}\)= 12,\(x_{2}\)= 12\(x_{1}\)=−1 + _{3}√3,\(x_{2}\)= −1 − _{3}√3

解析(f_ways)

(1)∵a = _{2}, b = 4, c = −1, ∴\(b^{2}\)−4ac =\(4^{2}\)−\(4 \times 3 3_{2}\times (−1) = 22\)> 0,代入求根公式,得x = −4±√22 =\(2\times ^{3}_{2}\)−4±√22,∴\(x_{1}\)= −4+√22,\(x_{2}\)=−4−√22; 3 3 3 (2)将方程化为一般形式,得\(6x^{2}\)−3x −4 = 0, ∴a = 6, b = −3, c = −4,故\(b^{2}\)−4ac = (−3)^{2}−\(4 \times 6 \times (−4) = 105\)> 0,代入求根公式,得 x=3±√105 = 3±√105, ∴\(x_{1}\)= 3+√105,\(x_{2}\)= 3−√105;\(2\times 6 12 12 12\)(3)∵a = 3, b = 6, c = −1,∴\(b^{2}\)−4ac =\(6^{2}\)−\(4 \times 3 \times (−1) = 48\)> 0,代入求根公式, 得: x = −6±√48 =\(2\times 3\)−3±2√3 2 2 ,∴\(x_{1}\)= −1 + _{3}√3,\(x_{2}\)= −1 − _{3}√3 3 −1+√6 −1−√6 2 3

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审计记录

阶段审计器结果得分依据(简短)
STRUCTURE structure-rule PASS 0.900
FORMULA formula-auditor PASS 1.000
KNOWLEDGE knowledge-auditor WARN -
VISION vision-auditor WARN 0.200

知识点(0)

无

事件

时间阶段级别消息
2026-09-26 03:36:30ERRORERROR处理异常: LLM call failed after retries: HTTPConnectionPool(host='127.0.0.1', port=8091): Read timed out. (read timeout=120) [endpoints: http://127.0.0.1:8092/v1 -> http://127.0.0.1:8091/v1]
2026-09-26 03:32:29FORMULAWARN公式转换未确认,保留原文本: solution
2026-09-26 03:28:29FORMULAWARN公式转换未确认,保留原文本: answer
2026-09-26 03:27:50FORMULAWARN公式转换未确认,保留原文本: sub_3
2026-09-26 03:27:06FORMULAWARN公式转换未确认,保留原文本: sub_2
2026-09-26 03:26:14FORMULAWARN公式转换未确认,保留原文本: sub_1