题目 #24725
- UUID
69e01643-7b80-4f42-891b-28e90b98c74a- 来源
- 人教版/九上/2026江苏九年级期中数学试卷+答案130.pdf 第 3 页,bbox
[30.0, 635.75, 168.02, 679.92] - 题型 / 学科
- comprehensive / math / JUNIOR
- 知识树
KT_JUNIOR_MATH_STANDARD- 难度
- 难度 3 / 5 中等 · 多步骤
- QA 状态
- PUBLISHED 重试 0 次,得分 0.950
- 最终题 ID
11491
最终题干渲染(f_body 预览)
用公式法解下列方程:
(1)\(x^{2}\)+ x −1 = 0.
(2)\(3x^{2}\)= 2 -5x.
(1)\(x^{2}\)+ x −1 = 0.
(2)\(3x^{2}\)= 2 -5x.
答案 / 解析
答案(f_answer)
(1) x₁ = (√5 - 1)/2, x₂ = (-√5 - 1)/2;(2) x₁ = 1/3, x₂ = -2
解析(f_ways)
(1) 对于方程\(x^{2}\)+ x - 1 = 0,系数 a=1, b=1, c=-1。判别式\(\Delta =b^{2}\)- 4ac =\(1^2\)-\(4\times 1\times (-1) = 5\)。由求根公式得 x = [-b ±\(\sqrt{\Delta}\)] / (2a) = (-1 ± √5) / 2。故解为 x₁ = (√5 - 1)/2,x₂ = (-√5 - 1)/2。
(2) 对于方程\(3x^{2}\)= 2 - 5x,移项整理得\(3x^{2}\)+ 5x - 2 = 0。系数 a=3, b=5, c=-2。判别式\(\Delta =b^{2}\)- 4ac =\(5^2\)-\(4\times 3\times (-2) = 25 + 24 = 49\)。由求根公式得 x = [-b ±\(\sqrt{\Delta}\)] / (2a) = (-5 ± 7) / 6。故解为 x₁ = (-5 + 7)/6 = 2/6 = 1/3,x₂ = (-5 - 7)/6 = -12/6 = -2。
原图与资产(0)
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审计记录
| 阶段 | 审计器 | 结果 | 得分 | 依据(简短) |
|---|---|---|---|---|
| STRUCTURE | structure-auditor | PASS | 1.000 | |
| FORMULA | formula-auditor | PASS | 1.000 | |
| KNOWLEDGE | knowledge-auditor | WARN | - | |
| VISION | vision-auditor | PASS | 0.900 | |
| SOLVER | blind-solver | PASS | 1.000 | |
| CRITIC | critic | PASS | 1.000 | |
| SYMBOLIC | symbolic-auditor | WARN | 0.500 | |
| COHERENCE | coherence-auditor | FAIL | 0.900 | |
| QUALITY_GATE | quality-gate | FAIL | 0.950 | |
| SOLVER | blind-solver | PASS | 1.000 | |
| CRITIC | critic | PASS | 1.000 | |
| COHERENCE | coherence-auditor | PASS | 1.000 | |
| SYMBOLIC | symbolic-auditor | PASS | 1.000 | |
| AUTO_REPAIR_ATTEMPT | answer-repair | PASS | 1.000 | |
| AUTO_REPAIR | answer-repair | PASS | 1.000 | |
| VISION | vision-auditor | PASS | 0.950 |
知识点(0)
无
正式题库记录(t_question.f_id=11491)
- f_qkey
b76478f35f9370a9c7309409861ed75f- f_style / 难度
- 4 / 2
- 入库题干
- 用公式法解下列方程:
(1)\(x^{2}\)+ x -1 = 0.
(2)\(3x^{2}\)= 2 -5x. - 入库答案
- (1) x₁ = (√5 - 1)/2, x₂ = (-√5 - 1)/2;(2) x₁ = 1/3, x₂ = -2
- 入库解析
- (1) 对于方程\(x^{2}\)+ x - 1 = 0,系数 a=1, b=1, c=-1。判别式\(\Delta =b^{2}\)- 4ac =\(1^2\)-\(4\times 1\times (-1) = 5\)。由求根公式得 x = [-b ±\(\sqrt{\Delta}\)] / (2a) = (-1 ± √5) / 2。故解为 x₁ = (√5 - 1)/2,x₂ = (-√5 - 1)/2。 (2) 对于方程\(3x^{2}\)= 2 - 5x,移项整理得\(3x^{2}\)+ 5x - 2 = 0。系数 a=3, b=5, c=-2。判别式\(\Delta =b^{2}\)- 4ac =\(5^2\)-\(4\times 3\times (-2) = 25 + 24 = 49\)。由求根公式得 x = [-b ±\(\sqrt{\Delta}\)] / (2a) = (-5 ± 7) / 6。故解为 x₁ = (-5 + 7)/6 = 2/6 = 1/3,x₂ = (-5 - 7)/6 = -12/6 = -2。
事件
| 时间 | 阶段 | 级别 | 消息 |
|---|---|---|---|
| 2026-09-26 03:30:58 | PUBLISH | INFO | 已发布 t_question.f_id=11491 qkey=b76478f35f9370a9c7309409861ed75f |
| 2026-09-26 03:30:58 | QA | INFO | QA: PASS (score=0.950) |